 Hello and welcome to the session. In this session, we are going to discuss the following question. The question says that the population of a town is 85,000. It is known that the town has an annual death rate of 5.2% and birth rate of 13.2%. Find the population of the town after two years. The compound interest law is amount A is equal to P into 1 plus R upon 100 raised to power n, which is applicable to any quantity that increases or decreases. With this key idea, we shall proceed with the solution. According to the question, we are given the population of a town as 85,000 and we need to find the population of the town after two years where the death rate is given to be 5.2% and the birth rate is 13.2%. As population is a quantity that can increase or decrease, so we can apply the compound interest law here. Here the population P is equal to 85,000, the rate of death is equal to 5.2% and the rate of birth is equal to 13.2%. Here the rate of birth is greater than the rate of death. Therefore, the growth rate is equal to the birth rate that is 13.2% minus the death rate that is 5.2%, which is equal to 8%. In this case, we see that the population of the town increases by 8% in two years. So the growth factor, that is, the ratio of the amount at the end of a certain period with the ratio at the beginning is greater than 1. Hence, by using the compound interest law, the population of the town after two years is equal to 85,000 into 1 plus 8 upon 100 raised to part 2. That is equal to 85,000 into 100 plus 8 upon 100, the whole raised to part 2, which is equal to 85,000 into 108 upon 100 raised to part 2. This is equal to 99,144. So the population after two years is equal to 99,144, which is our answer. This completes the session. Hope you enjoyed the session.