 All right friends, so this is Dheeraj and we have Tushar also with me. So we are live here and the agenda of today's session is to have a discussion on the need paper. So today I am sure many of you might have taken the need paper and eager to know whether you have got the correct one or not. So we are here to talk about the question paper. We have tried ensuring that we are error-free in this discussion. But you know that since we are in a hurry and you are also probably eager to know the solution as soon as possible. So we have the entire team sitting here and as and when we are solving the questions we are coming here one by one and just having a discussion on questions. So let's start the discussion with the physics section. So we will have physics section, I will open up that. So you can see on your screen the first question. So here you can see that there is a galonometer which does not show any deflection in that circuit shown and we need to find out the value of the resistance. Now if you see the circuit here if galonometer does not show any deflection what does it mean? It means that galonometer doesn't have any current. So all the current that is let us say generated by the battery will pass through the resistance after crossing the 400 ohm. So if I have to let us say let us say solve this I can simply use Kirchoff law here this is my loop number one there is no current over there. So you can directly write in fact the current is 10 divided by 400 plus R isn't it? Now when do you think there is no current to the galonometer when whatever is a voltage drop across the resistance it matches with the potential drop of 2 volts. So all you have to do is equate 10 R by 400 plus R equals to 2 and you are going to get the value of resistance as 100 ohms. So let us go to the next question guys so you know of course you might have written different different sections or sorry different different papers so the sequence may not match so I am expecting you to find out your questions you are expecting you to find your questions looking at the questions over here. So here is a second question you can see that here is a second question here is a second question. So sorry for those small small technical glitches we are having so we are taking every precaution to make sure that we are error free and in a hurry also so anyways. So this is a question you can see we have a wire that is suspended from the ceiling and is stretched by the weight W attached at its free end. So we need to find longitudinal stress at any point of the cross section area A so we are assuming here the wire have a mass in it so whatever is a weight which is attached tension is throughout the weight only so simply you have to say W by A as the answer over here so option number 4 is the correct answer. So let us go to the next question so you can see there is a big you know paragraph here if I were you I would have left this question and move to the next so that I could save couple of second and feel comfortable that I have got many questions correct but anyways the exam is over so we can talk about it. So the work function of the cesium potassium and sodium 3 elements the work functions are given and the electromagnetic radiation is falling on it which has the photon of that has 2.2 electron volt and we need to find which of the surfaces will emit the photo electrons so we know that the work function what is the work function the photon of the radiation energy of that has to be more than that so you can see 2.2 electron volt is only above the 2.14 electron volt work function and it is less than 2.3 and 2.75 so definitely only cesium so option number 3 is correct over here okay so let us go to the next question now here this is a theoretical question so this is a relief so the venturi meter works on which principle so you can if you remember from whatever you have learning grade 11 to derive the entire principle of venturi meter the flow rate and all you have to use continuity and the Bernoulli's principle so we can say option number 4 is correct for the question number 4. So let us go to the next question alright so we have potential energy of a long spring which is stretched by 2 cm is u if the spring is stretched by 8 cm you need to find the potential energy now here we need to do a little bit of work but it is not much so you can see potential energy is half k into 2 square now I am not taking care of units here you need to basically convert into SI unit if somebody ask you exactly what is the energy but since I have been taking ratio so I am just writing 2 here so let us say this is u1 and potential energy the second case is half k into 8 square right now if you take a ratio here u2 by u1 becomes 8 by 2 whole square which is 16 now you are in a hurry so you just see the factor of 16 here mark option 2 correct and move forward alright so this is your fifth question let us go to the sixth question so you can see how fast we are solving here so I am assuming that you might be getting you know you might be solving at the similar speed in the exam also so you can see this is a question which is little twisted but anyhow we will be solving it so you know we did not wait for it to be getting typed and all so we just taken the screenshot as soon as possible and putting it here here you can see here the temperature of the gas is minus 50 degree Celsius we need to find the temperature of gas should be heated so that rms is speed to be increased by the three times now we know that the velocity is proportional to root over temperature right so v1 you can say is proportional to root t1 and v2 is proportional to root over t2 so we can see v2 by v1 is equal to root over t2 by t1 and from here v2 is three times so we can say 3 is equal to root over t2 by t1 and this will give you t2 to be equal to 9 times t1 alright now you have to make sure that you convert this temperature into kelvin you can't do 9 times of 5 minus 50 degree Celsius okay so t2 is equal to 9 times of 273 minus 50 alright now we have verified at our end that whatever answer you get here in kelvin you know that doesn't match with any of the options so we will wait for the confirmation but from our end we we are reasonably sure that you will get bonus marks for this so congratulations alright so let us go to the next question question number seven now this question is on surface tension which is probably the most ignored topic of the flutes so you can see that amount of energy required to form a soap bubble of radius 2 centimeter from a soap solution is what now when it is a soap solution we are assuming the interface to be horizontal radius is infinity now we are creating a soap bubble of radius 2 centimeter now if surface tension is sorry if the surface tension is s we know that the surface energy is surface tension into surface area but here it is a bubble so bubble has two interface so we need to double it up right so 2s into 4 pi r square you have to do this is the potential energy alright so you know this is the answer so when you substitute here all the values surface tension is 0.03 radius when you put as 2 into 10 so minus 2 meters you will get the answer you will get the answer as option number one 3 into 10 so minus 4 joules alright so let us go to the next question question number eight so I am here to discuss only the first 10 questions after that my colleague Shankar will take over alright so let us discuss this the ratio of radius of garation of of a solid sphere of mass m and radius r about its own access to the radius of garation of a hollow sphere of the same mass and radius about it access is what now if radius of garation is k we can write m into k square yeah as the moment of inertia right so this is equal to 2 by 5 m r square for the case of solid sphere alright now for the case of the hollow sphere m into k2 square I can say 2 by 3 m r square now I am assuming radius is same for both we can confirm that yeah both having the same radius so now when you take a ratio you will get k1 by k2 the whole square to be equal to 3 by 5 now you can see here k1 by k2 comes out to be root over 3 by 5 now this is also surprising my dear friend because the option doesn't have root over 3 by 5 so most probably you are going to get another bonus alright so but then again we will wait for the confirmation but as far as whatever collection we have done we think that the option for the correct answer is not in this question so we will go to the next question so you can see here now the moment you see such question you find relief because however much you see that you know mechanics is difficult and all but yes we are so a bullet is fired from a gun speed of 280 meter per second and in the direction 30 degrees up the horizontal we need to find maximum height now this is a direct formula application question alright so we should know that the maximum height formula is u square sine square theta by 2g now you know do you think they are testing your own concept here definitely not they are testing you on your calculation abilities alright so the calculation is you know a little difficult here you need to substitute u as you know 280 and square it then sine square theta you have to do then g you can't take 10 you have to take 9 pointed but my dear friend when you do that calculation you get a beautiful answer you get 1000 meter as the correct answer alright so let us go to the next question question number 10 alright so so here is a question number 10 you can see here this is on em wave and we just you know this is a huge question so we'll just look at the data points here this is the frequency this is the amplitude of the this is the amplitude of the electric field and we need to find the amplitude of the magnetic field now we know that electric field amplitude divided by magnetic field amplitude has to be equal to speed of light isn't it so sorry about that so magnetic field is equal to electric field divided by speed of light so electric field amplitude is 48 that divided by 3 into 10 is for 8 so you can see beautiful answer comes option number one again alright so this is how you can you know this is how you can solve the first 10 question I hope you liked it now I am welcome Shankar we have making we are making sure that we are giving you solutions live very far thick and fast so that's why more than one person is solving questions alright so Shankar welcome thank you thank you so much dear sir I am here with the next set of questions okay let's clean this and let's close this okay let's move on to the next question I have a question on magnetic flux and it's a very easy question they're asking the net magnetic flux through any closed surface is how much now we know we have studied magnetism and okay one thing we know about magnets is there will always have a north and a southern pole even if you break the magnet into two the two pieces broken pieces will always form uh two by poles like north and south and north and south so this what it means is essentially that monopoles in case of magnetism does not exist so the solution to the question is zero okay the net magnetic flux through any closed surface will be zero because there cannot be any magnetic monopoles let's move on to the next question guys okay next question is based on a car not engine we know about car not engine car car not engine takes up you know there's a there's a hot reservoir okay and there's a coal reservoir and this is the engine the engine takes energy from hot reservoirs gives us output of work and it sends out some energy to the coal reservoir okay now one thing we know about this is that the temperature here is given to us as 327 degree centigrade if I convert this to Kelvin guys this will become well plus 273 so this becomes 600 Kelvin's so I'm given that the hot reservoir is working at 600 Kelvin's this is given at 600 Kelvin's now in the coal reservoir and the work the efficiency is given to us as 50 percent and efficiency is essentially in a heat engines it is how much is the work divided by how much energy put inside the from the hot reservoir right so this is given to us as half and since this is half that means half of the energy is going into work then and half energy is coming to the coal reservoir so if and also one thing we know that these temperatures right here are directly proportional to the heat energy transferred so t1 by t2 okay so this right here is 600 Kelvin remember that this calculation will happen only in Kelvin don't forget to you know change your units to Kelvin so this becomes half equal to whatever is the temperature of the coal reservoir divided by 600 Kelvin's right so from here you get the temperature to be 300 Kelvin's now your options are in centigrade so if you convert this into centigrade your cancer comes out to be 27 degree centigrade let's move on question number 13 a full wave rectifier circuit consists of two pn junction diodes a center tap transformer capacitor and a load resistance this is a theory based question you have to know this from the chapter okay which of these components remove the ac ripple from the rectified output this is a theory based question the answer to this is the capacitor okay so in the capacitor option number a is used to refine your you know ac output to have a better outlook okay of dc let's move forward to the next question guys this is a very easy question the equivalent capacitance of the system shown in the following so our circuit is how much well we know these two circuits these these two capacitors right here are located in parallel are they they're positioned as parallel connection so that means the voltage across them will be same and the equivalent capacitance will be simply three plus three okay so this will be what six micro farads guys this part is six micro farads now this converts into a very easy question you have two capacitors one is three micro farad the other is six micro farad these are connected in series in series the net capacitance is given by c1c2 divided by c1 plus c2 if I apply this formula here three into six divided by three plus six gives me how much 18 by nine which is two micro farad okay so three is the correct option here guys let's move on to the next question question number 15 lcr circuit has an inductance value of 10 micro farad capacitance is one micro farad resistance is 100 ohms the frequency at which the resonance occurs is how much well one thing I notice here from the options is that I have two sets of units here okay one is in radian per second and the other one is in kilohertz so either they're asking us omega or f okay in resonance we know let's clean this okay so I would say that omega is equal to one upon root lc or if I want to change it into normal frequency f becomes equals to one by two pi of root lc okay so either we can do the calculations here I don't need the value of resistance this is useless information I have 10 micro henry and one micro farad so I have to multiply this this value is how much 10 into 10 raise to power minus three henry capacitance is 10 raise to power minus six okay and if I multiply this I get 10 raise to power minus eight which goes up this becomes 10 raise to power four so omega is 10 to power four okay so omega's value is sorry omega's value is 10 to power four I see both these options are cancelled here I don't need this okay I have to figure out how much is this value in in in actual frequency okay so this value is 10 to power four I just have to divide it by two pi and I get the value of the frequency which is essentially one 10 divided by two pi in kilohertz okay 10 divided by two pi okay so this comes out to be 1.59 kilohertz okay the key in this question is just notice the units here I know some people might have got stuck I could not find out the value of omega but they were not asking the value of omega they were asking the value of f let's move on to the next question question number 16 is a question on flux okay so if e.ds is zero over a surface then which of these statements is correct well I have gone through all the statements and option number three is the best one that that describes it okay so if I know that the flux uh e.dx is zero well one thing is for sure that the net flux coming out of that is going to be zero so one of these statements the third statement the number of the flux lines entering the surface must be equal to the number of the flux lines leaving it is the best statement to describe this scenario let's move on so question number three option number three is the correct option okay now this is a question based on electric dipole uh so the electric dipole is placed in at an angle of 30 degrees with the electric field okay so I have some sort of electric field which is traveling okay and I have kept a dipole like this okay the dipole is making an angle of 30 degrees so this is let's say is p this is electric field e so the formula for torque is actually a p vector cross e vector okay p cross oh okay let's move this down so the formula for torque is p cross e okay so if I open this this is essentially p e sin theta where p is what p is the dipole moment is the electric field and sin theta where theta is the angle between the p vector and e vector well p value is something that we need to figure out e is given to us it is 2 into 10 raise to power 5 and sin of 30 degrees is half okay sin of 30 degrees is half torque is also given to us this is equals to 4 okay so if I do this 2 and 2 cancels out and the value of dipole moment comes out to be 4 into 10 to power I think I did some mistake no 4 into 10 raise to power minus 5 seems correct yes this is perfectly correct now one thing that is given to us this is the length of the dipole okay let's move forward football player is moving southward okay so let's draw this okay a football player is moving southward so this is the initial velocity okay feed to avoid an opponent of uh if he suddenly turns eastward okay so if I if I designate a certain direction this is north then southward is the initial velocity final velocity is in eastward direction this is happening in the eastward direction so what they are asking is what what is the direction of force well for finding out the direction of force I need the direction of acceleration how do you find out acceleration final velocity minus initial velocity right so this is the direction of final velocity what is the direction of minus because I have to do vf minus vi right what is the direction of minus vi well it is in this direction because vi is in this direction minus vi is in the north direction so I have to add these two vectors because this will be the direction of this will be the direction of vf minus vi well I'm only talking about the direction here so don't don't say take in final minus initially there has to be a time component as well. So, if I add to these vectors this is the direction of the acceleration and hence this is the direction of the force. So, among these option number 1 which is saying north east is going to be the correct answer because this is direction this is not direction. So, north east is the correct answer ok. Let us move forward guys 19 the magnetic energy stored in an inductor well I then I know the direct formula for this one guys ok. The energy in an inductor is given by half times l i square half l is how much 4 micro 4 into 10 raised to power minus 6 i is how much well it is 2 2 square which is 4. So, I will essentially get half it is correct. So, this is goes 4 to the 8 8 into 10 raised to power minus 6 ok. So, 8 micro joules is the correct answer here no complication in this kind of question let us move forward guys 20 resistance of a carbon resistor determined by the color codes is 2 2 the triple 0 plus minus 5 percent ohm. So, this is that question from BB Roy ok. So, I hope I hope you remember the BB Roy acronym BB Roy ok. So, these colors are this is black followed by brown this is red this is orange and this is yellow this is how you color code your resistor there is more to this there is more to this but I am going to require only these why because the first band ok. So, in a resistor if you make a resistor the first band represents the first digit second band second digit third is the band which determines how many zeros what is the multiplier that you need to use well I see that my resistor has well 2 2 and then triple 0. So, I am looking for a multiplier in in range of 10 raised to power 3. So, 1 2. So, it starts from 0 1 2 3. So, orange is the one correct answer here ok. So, orange is the correct answer here let us move forward to the next question and the next question will be dealt with by one and only Subu sir. Let us start with the question number 21. Now, this is a question from refraction and he is asking the critical angle you will use the direct formula where critical is sin inverse of mu sin inverse of mu where mu is the rarer with respect to denser so that you get a value less than 1 here. So, as a shortcut we are just going to divide the velocities to find mu which velocity to divide by which without thinking too much we will just say we need to get a value less than 1 velocity in denser medium is the light is slower which means to get a velocity less than 1 we will divide denser velocity by rarer velocity. Denser velocity is 10 x distance by t 2 time divided by the rarer velocity which is x distance by t 1 time x cancels out and you get 10 t 1 by t 2 as the refractive index less than 1 of the rarer with respect to denser and sin inverse of this refractive index is sin inverse 10 t 1 by t 2 which you can expect is going to be a value less than 1. So, simple question about refractive index for speed you can not worry about which to divide by which just observe that you are finding a value less for sin inverse right. So, this is a question on Young's double slit experiment it's a straightforward question. So, if the screen is moved away the angular separation between the fringes keyword here is angular separation we are not talking about the separation distance between fringes we are talking about the angular separation which means at what angle are the two fringes forming right. If you remember the YDSE diagram you find that the path length between the light rays traveling from each slit is proportional to d sin theta which means the path length defines the path length distance decides for constructive or destructive interference this will decide whether the angular separation of the dark and light fringes where it forms. Changing the distance of the screen does not affect this angular separation which means the distance will not change statement 1 is true the angular separation remains constant. Statement 2 if the monochromatic source is replaced by another monochromatic source of larger wavelength this means that the wavelength increases and to provide a similar path length of half wavelength the path difference will have to be larger because half wavelength is larger which means a larger angle would have to be deviated through by the beam. So, the angular separation of fringes is supposed to increase angular separation is will increase then we will have a larger path difference to provide for a larger wavelength larger half wavelength as the difference. So, statement 1 is true angular separation does not change statement 2 angular separation decreases this is false the angular separation actually increases so option 1 is correct. Option 1 the half life of a radioactive substance is 20 minutes in how much time the activity of a substance drops to 1 by 16 to 240 by 80 into 10 power minus 2 and 3's are 24. So, you get 3 into 10 power minus 2 per degree Celsius option 1 3 into 10 power minus 2 ahead of time you know that we are asking only about the order of magnitude since 3 is common in all options. So, remember this while solving questions only talk about order of magnitude. This is a very very interesting question because here he has used the phrase dipole he has used the phrase an electric dipole, but you are not supposed to use the dipole formula for this question very very important because this is the origin and the separation between charges is 3 centimeter 3 centimeter this itself 6 centimeter. The point P at which we are looking is 5 centimeter away from this the essence of a dipole is that this gap has to be much smaller than the distance of the point from the center the gap between charges has to be very small this is the important essence of a dipole. This gap is 6 this is 5 this is nowhere this is not even smaller forget much smaller. So, this does not count as the dipole in the sense that you cannot use dipole formula you cannot use Kp by R square Kp for the potential of a dipole here because that formula assumes that this is much smaller than this since it is not what will you do you will just use the potential formula what the distance from this to this this is 5 this is 3 so this is 2 and this is 5 this is 3 this distance is 8 centimeter 8 centimeter and 2 centimeter what is the potential due to this charge the potential is Kq by 2 into 10 power 2 for centimeters and then due to the other charge it is minus Kq by this is 8 into 10 power 2. So, if I subtract these two LCM is going to be 8 and then 4 minus 1 is 3 by 8 Kq into 10 power 2. So, 3 by 8 Kq 10 power 2 volts is asking the units of 10 power 2 volts answer is 3 by 8 Kq in terms of K only. So, option 3 3 by 8 Kq very interesting you are supposed to yourself realize that gap between charges is not small compared to the distance of the point therefore, you cannot use the dipole formula if you use you will not get the correct answer excellent question. This is very straightforward for the following circuit the truth table. So, instead of drawing up each value like take 1 1 1 0 1 0 1 we can use this also in a short cut in a logical way because you have to solve 45 questions in 1 hour this is a NAND gate right which means this part of this gate is AND. Now, AND is very good because AND is true only in one condition when both of them are true right. If AND is true NAND is going to be 0 if AND is 1. So, there is we will just we will find that there is only one condition where we get 0 that is when the AND gate shows 1 that means they these two show 1, but because of this not this will only happen when these two show 0. So, this tells us that if A and B are both 0 these two will be 1 AND will be 1 NAND will be 0. So, apart from this case if these are anything else AND is going to become 0 NAND is going to become 1. So, for AND we evaluate only the one case where these two 0 will give you 0 and anything else will give you 1. Look at the options y is 0 should be only in the case where A and B are 0 2 cases here wrong answer 3 cases here wrong answer 1 case here 1 case here, but this 0 is when both are 1 this 0 is when both are 0 y is 0 when A and B are both 0 and 1 every time else fourth option is the correct one y is 0 when A and B are both 0. So, for AND and OR evaluate only one condition rather than evaluating all of the conditions. This is a direct formula based question. So, there is a conducting wire the magnetic field due to this conducting wire arranged in this there is a line infinite line semicircle what is formula for infinite line ampere slot tells us that infinite line is mu naught i by 2 pi r, but this is not an infinite line this is semi finite right semi finite line will be half of this value mu naught i by 4 pi r, but then there are two semi finite lines are their fields going to add up or cancel this is going this way align your thumb curl your right hand fingers it is going inwards due to this what about this align your thumb curl your fingers it is also going inwards the fields add up and you get two times of this and you get again mu naught i by 2 pi r this is the field magnetic field due to the two straight segments what about due to this the magnetic field due to an arc is mu naught i by 2 r for the whole circle this is since there is a semicircle it is going to be mu naught i by 4 r and now if you add these two you will get mu naught i by 4 r common yeah, but are you supposed to add them or subtract what is the direction of field due to this arc align your thumb curl your fingers by the time your fingers reach p they are coming outwards which means this is outwards and these two are going inwards this is the inward field this is the outward field you need to subtract them take mu naught i by 4 r common for the curved part you get 1 for the this part you will get the 4 r so there should be a pi in the denominator there will be 2 in the numerator and this is inwards or outwards as I have written it this is taking this one as positive the arc as positive which means it is taking outwards as positive 1 minus 2 by pi outwards away from the page option 1 mu naught i by 4 r into 1 minus 2 by pi away from the page last question which I will be taking two thin lenses are of same focal lengths one is convex and the other is concave when they are placed in contact with each other the equivalent focal length of the combination will be they are placed in contact or close together from optics you know that when two lenses are placed close together whether they are convex or concave or whatever combination the powers add up this is the simple fact the powers add up is a simple fact which you need to remember for this what is the power of one lens it is the inverse of the focal length convex lenses have positive focal length so power is also positive 1 by f concave lenses have negative focal length power is negative so minus 1 by f you add them up you get power 0 so your answer is 0 no power is 0 is asking equivalent focal length of the combination will be how much a 0 power which means focal length has to be infinity because power is inverse of focal length 0 will be only when focal length is infinity and therefore the combination will have an infinite focal length so now Dheeraj sir will continue with the rest of the questions thanks subu so I am back again so last 10 questions only in physics so earlier used to be 45 questions now they are 50 but the trend that we have seen the trend we have seen is that the quality of question or you can say the difficulty level of the question that is actually going down fine so let us go to the next question question number 41 all right question number 41 so you can see that they are asking what the question is the radius of the innermost orbit of the hydrogen atom is given to us they are asking us to find their radius of the third allowed orbit now third allowed orbit means that the quantum number is 3 so n equal to 3 now the radius formula I hope all of us know is r naught n square by z where r naught is the radius at the n equal to 1 so when you substitute here it will be equal to r naught which is 5.3 into 10 is power minus 11 into n square n is 3 so into 9 so now when you simplify it you will get 39 to 27 47.7 into tensor minus 11 so you are going to get option number 2 s correct so this is the correct answer for question number 41 let us go to the next question so here we need to find the maximum iteration of a moving car so that the body which is on the floor of the car remains stationary now the scenario is something like this let just imagine there is a truck instead of a car so there is this block now we need to find maximum iteration of the truck so that this block doesn't move all right now the the thing is that the block will start sliding only and only if the truck is moving with truck is moving with so fast acceleration that the block is not able to sustain because of its own friction so maximum allowed acceleration of the block is what we need to find out first now who will move the block only friction force is there which can move it forward now friction force is mu time normal reaction now we are in a hurry and we can see that normal reaction is mg only here so mu mg when you equate it to mass times maximum acceleration so you will get maximum acceleration of the block so if the car or a truck moves with higher acceleration than this then the block will not be able to sustain because it can at max move with this acceleration so this is the maximum acceleration of the truck or a car so that the block kept on it also moves with the same acceleration or both moves together so mu is what mu is 0.15 and g is 10 so the answer is 1.5 meter per second square all right so let us go to the next question so you can see here a satellite is orbiting just above the surface of the earth with time period t if d is a density and g is the universal gravitation constant we need to find out what is the value of this quantity need to find out what is the value of this quantity now like we always say that whenever someone or some object is orbiting in a circle the first equation that you have to write is the force toward the center is mass times centripetal acceleration all right so you can see here the radius of revolution is a radius of earth only all right so I can directly write g times mass of the satellite into mass of the earth divided by radius of the earth square that is equal to mass of the satellite omega square into radius of the orbit so this is the this is our first equation now I need to bring in the time period over here right t so what I will do I will simplify a little bit here m is gone and omega I can write it as 2 pi by time period so that square into r e and also mass of earth is not given to us rather density is given so I will use that so mass the earth can be written as density times 4 by 3 pi into radius cube that divided by radius square is equal to 4 pi square by t square into radius fine now all you have to do is simplify a little bit and you will get the answer right away so you can see many things are getting cancelled out here and you will get the value of here g d by 3 to be equal to pi by t square right so 3 pi by g d is equal to t square so option number 4 is correct here all right so let us go to the next question okay so now here is a question where we need to find the impedance all right now here we know that impedance formula this is equal to x l minus x e whole square plus r square this formula holds good when things are connected in series okay so we need to be patient here little bit because the calculation is slightly heavier so one by one we have to calculate x l x l is omega into l which is 2 pi into 50 into l l is 50 by pi okay so 50 by pi millihenry so times of minus 3 so you can see here this becomes 100 into 50 into times of minus 3 so this is 5 ohms okay now x c is 1 by omega c omega is 2 pi again 50 this is 50 sorry for my writing here that into the capacitance value tens of my 10 square 3 by pi into 10 square minus 6 now this when you do your calculation properly you will get this as 10 ohms okay so I have done little bit of calculation myself before coming here so that's why I can directly write here so this is 10 this is 5 and resistance is 10 so you can substitute here you will get root over 10 minus 5 whole square 5 square plus 10 square so it can take 5 out this will become 1 plus 4 so it will be 5 root 5 so the answer is option number 1 okay so let's move forward now this is you know I can definitely say that while you prepare so hard for exam like need you will definitely have encountered this kind of question so this is not an unseen type of question so 10 resistances each resistance are when they are connected in series now when you see this up to here you immediately write the equivalent resistance in the first case is 10 R they are connected in series now if then those are connected in parallel now if they same thing is contained parallel the equivalent resistance will go to R by 10 okay like 1 by R plus 1 by R plus 1 by R 10 times is equal to 1 by R equivalent so 1 so R equivalent is equal to R by 10 now current in the first case is equal to V by R equivalent in the first case which is 10 R current in the second case is V divided by R by 10 now you know if you have done enough practice you don't need to move forward from here you can see the factor of 100 is a difference I mean if you take a ratio so definitely you know factor of 100 will come out when you take a ratio option number 4 is correct here all right so let us go to the next question question number 6 so hurry on the bridges built across a river the student there is a student who is throwing a stone upwards with this velocity the ball strikes the water surface after 4 second you need to find the height of the bridge all right so a small diagram will always help my dear friends so let's say height is h you're throwing it up with a velocity of 4 meter per second okay now what it does the ball goes up and comes back here so you know while it is coming and hitting total displacement let's say upward you're taking positive total displacement the y direction is minus h okay time you know what is time time is 4 seconds and the velocity is plus 4 meter per second this is the initial velocity so which formula comes in your mind definitely everything is given for a formula which is s equal to ut plus half 80 square okay so s is minus h u is plus 4 t is again 4 and acceleration I hope they are sustained yes so acceleration is minus 10 into 4 square so that is 16 so this is 8 so you can see here minus h is equal to 16 minus 18 now 16 minus 80 a factor of 4 should come in here so I'll mark option number one one because we are in a hurry so let's move forward this question number 46 now here is again one more question on the equivalent you know focal length so you might have seen subbu discussing you know finding the equivalent focal length this is one more question so you can see you know it is written here that these are three thin lenses in contact so we need to find out the equivalent focal length all right so this is one lens this is another one and this is a third one so we know that one by focal length is equal to one by f1 plus one by f2 plus one by f3 okay so one by f1 let us say this one can be written as mu minus 1 into the radius of this side is infinite is a flat surface so 0 minus the radius of that side is plus 20 so this so you are going to get it as 0.4 by 20 minus of that okay so this is one by f1 okay so when you do this when you use the same formula for this you're going to get the same thing 0.4 by you know minus 0.4 by 20 it doesn't matter how the lens is kept whether you come from this side or that side the focal length of this one remains same so same way it holds good for that so one by you can say that side is f3 so 1 by f3 is also equal to minus of 0.4 by 20 now this is f2 so 1 by f2 is equal to mu minus 1 that is 1.5 minus 1 now here r1 is plus 20 and r2 is minus 20 so you get 1 by f2 as you get 1 by 20 so this is 1 by 20 this is 1 by 0.4 by 20 so you need to add it up when you add everything up you will get the equal focal length as minus 100 centimeters okay so let me just confirm because I have already solved yes so the this is the correct answer let us move to the next question okay alright so this is question number 48 so while carrying a current i along the positive x axis has length l it is kept in a magnetic field which is given to us the magnitude of the magnetic force acting on the wire is what now this wire is a straight wire right so length we have to treat it like a vector so we can say that the length l is length vector l is nothing but l into i cap now the force we know the formula i l cross d so you can see here it is i l i cross of this now i cross of 2 i is 0 so you can see here you will get 3 i cross j is k i cross k is minus j so this is what you will get now this is force vector now I can see the option option is actually talking about the magnitudes only so when you take the magnitude root over 3 square plus 4 square will come as factor of 5 will be there so option number 1 is correct alright so let us go to the question number 49 so an xt graph of the particle performing a simple harmonic motion is given to us we need to find the expression of the particle at t equal to 2 now we know that the acceleration is equal to minus of omega square x where x is a distance from the mean position right so this is the distance from the mean position at t equal to 2 the distance is 1 okay and we just need to find out what is omega to find out the omega we can simply use this formula 2 pi by t time period is what from 0 to 8 it completes one cycle so it will be 2 pi by 8 so this is pi by 4 okay so the acceleration is omega square which is pi square by 16 into amplitude x is amplitude which is 1 so it is minus of pi versus so you can see here if you are in a very very hurry towards the end they are tricking us by giving option number one as this so we have to make sure that you are putting a minus option number two is correct not option number one alright so let us go to the next question the last question of physics is this now you can see if I were you this is a huge question and typically I skip a big question like this and move on to mark it for the later but anyhow since we are talking about all the questions let us move ahead a bullet from the fun from the gun is fired on a rectangular wooden block with the velocity of u when would when bullet travels 24 centimeter through the block the velocity becomes one third okay now I am sure you might have done this question a similar question while practicing right so you can do it little faster here you can use v square equal to u square plus 2 as we are assuming we are assuming that the disillusion of the bullet is constant that is why we are using it okay so from here v square is nothing but by 9 this is equal to u square plus 2 a what is s here s is 24 centimeter now I am not converting centimeter into meter because I have to anyway take a ratio I know that so I will write it as minus of 8 u square by 9 is equal to 48 times a so this is my first equation now it is written that it comes to rest exactly at the other end and they are asking us to find out the total length so again we will use the same formula a remains the same in both the cases now the final velocity is 0 initial velocity is u square initial velocity is u so u square plus 2 a let us say length is l so u a l so minus of u square is equal to 2 a l so now 1 and 2 equation I do not care about velocity u so we will take a ratio to find out whatever value of l even a will go away so you will get 8 by 9 when you take a ratio to be equal to 48 by l so oh sorry by 2 l so this is 24 this is 38 that this so l is equal to 27 I hope it is there yes it is there so option number 3 is correct all right so I hope you have done really well in the physics section now now we have another Dheeraj coming here Dheeraj Sharath is the name and he is a chemistry teacher at Centrum Academy so you know so please welcome Mr. Dheeraj Sharath to talk about the chemistry section all right thank you good evening students hope you guys have done a great job in today's neat paper we will straight away start with the question the question is not from the code that the physics teacher discussed the question is from a different paper code paper so try to connect with the question not with the code moving further the first question is really simple homoleptic complexes from the following complexes are homoleptic simply means homoleptic simply means that the complexes will be made up of the same type of ligands okay if the complex is made up of same type of ligands then we will call such complexes as homoleptic complexes you just have to look at the options I have amine here I have aqua so that's two ligand and I have potassium potassium tri-oxalato aluminate so potassium is the counter ion which will be present outside the complex and tri-oxalato refers to the negative ligand that we have so oxalato will be the ligand and aluminum will be the the counter metal atom so basically this should be the answer because it is made up of only one kind of ligand so homoleptic complex one kind of ligand moving on next question taking stability as the factor which one of the following represents the correct relationship so straight away we will have to answer this based on based on inert pair effect inert pair effect so based on this the answer can be very easily derived for example they are talking about thallium indium aluminium they all belong to the same group with boron as the first element first element then aluminium then gallium then indium then thallium so basically what is inert pair effect very simple as I move down the group in the periodic table the oxidation number which is smaller that compound will have higher stability so what are the oxidation number that this particular group will have it will have an oxidation number of plus one and it have an oxidation number of plus three so if you ask me up to gallium I would say plus three oxidation state compound would be more stable but the moment we come to indium and thallium compounds with plus one oxidate oxidation state will be more stable so if you ask me indium thallium will prefer to form compounds with plus one oxidation state over plus three now you just have to figure out where is the oxidation state for indium and thallium plus one option one so thallium oxidation state here is plus one and its stability is greater than thallium whose oxidation state is plus three here here indium is in plus three oxidation state definitely it is not stable this is stable so option a has to be the answer where plus one oxidation state compound is more stable compared to the plus three oxidation state compound okay we will move on to the next question organic question pretty interesting simple I have benzene diazone a diazonium chloride the moment benzene diazonium chloride reacts with Cu2Br to HBr you get this product the diazonium chloride component gets replaced by Br that will be the first step first reaction now when this is made to react with mg and dry ether all of us know what mg and dry ether does it leads to the formation of Grignard's reagent so I get benzene ring mg and to mg we would have Br associated okay and very simple this part is also over what will happen to a Grignard's reagent when it undergoes hydrolysis when a Grignard's reagent undergoes hydrolysis it leads to the formation of the respective hydrocarbon in this case the respective hydrocarbon would be benzene with the side product of mg OHBr so where do we have the only hydrocarbon here it is option see straightforward three action involving question we will move ahead to the next question guys yeah the right option for the mass of carbon dioxide so I hope you guys have uh understood the organic and the inorganic problems we solved so this is the first physical problem for the day so he's talking to us about the amount of carbon dioxide produced when you heat 20 grams of 20 percent let us first look at the reaction what's limestone limestone is CaCO3 if you heat limestone what happens it decomposes to give you calcium oxide carbon dioxide a simple straightforward question and the reaction is balanced so if I take how much of calcium carbonate according to the balance reaction calcium's weight is 40 carbon is 12 oxygen is 16 threes are 48 so 40 plus 12 plus 48 will make it 100 grams so if I take 100 grams I'll get how much of carbon dioxide 12 plus 16 into 2 32 plus 12 44 grams so if I take 100 grams of calcium carbonate I would be getting 44 grams and he's taking how much here 20 grams but this is the twist in the question he's telling that the calcium carbonate is 20 percent pure so what does it mean if I take 20 grams of calcium carbonate and if it's only 20 percent pure only 20 percent would be calcium carbonate the other would be the impurity no so how much would be how much would 20 into 20 by 100 be 4 grams correct so it would be 4 grams so in reality we are not taking 20 grams of calcium carbonate we are taking only 4 grams so if I take 4 grams I'll do the calculation here if I take 4 grams how much of calcium I mean carbon dioxide will be produced how much of carbon dioxide will be produced to the map x equals to 4 into 44 divided by 100 that would come up to 1.76 grams so 1.76 grams option c is the answer okay next e-question note in you it's a very simple question for example he is simply talking to about the solubility of a gas alwa so he says helium is used to dilute oxygen in the diving apparatus that's 100 correct simple helium if you add helium to oxygen what the divers experience has been the physical pain once they come back to the shore that gets avoided so why is helium added to oxygen helium is added to oxygen because helium solubility is least or it is probably one of the least soluble gases that we have so statement number one is correct that's the assertion is right helium is definitely used to dilute oxygen in diving apparatus that is not because it is highly soluble that is because it is least soluble so the assertion is right but the reason is wrong okay so a is let's say both a and r true a and so it is a for rather i'm sorry it is four a is true but r is false okay simple another physical chemistry question from chemical kinetics pretty interesting and easy to solve also okay so what does it say for a certain reaction the rate equals to k into concentration of a to the power 2 into concentration of b simple when the initial concentration of a is tripled so all that we will have to do is we will have to triple the initial concentration let's say how will i triple a can be written as 3a the rest will be as it is because he is not changing the concentration of b so this is one equation and this equation is after you have tripled the concentration of a try to remove what is common so k can be removed a square a square b b can be removed what is left out 3 square will be left out 3 square would be 9 so the rate would increase how many times the rate would increase by a factor of 9 very simple question again okay next one which one is an example of heterogeneous catalysis simple what do you mean by heterogeneous catalysis the reactants the reactants and the products state of matter or phase will not match with that of the catalyst if catalyst catalyst state of matter or phase if it does not match with reactant or product we will solve will call such reactions as heterogeneous just look at it first one combination of dihydrogen dinitrogen sorry dinitrogen is a gas along with dihydrogen dihydrogen is also a gas to form ammonia ammonia is also a gas in the presence of finely divided iron iron is a solid therefore the solid that is the catalyst that is present here is in the solid format compared to the reactants and products which are in gaseous phases so straight away option one is the answer because they are all not in the same phase or in the same state of matter okay simple one again a very very simple question four marks in your pocket by just looking at the graphs which amongst the following option is the correct graphical representation of Boyle's law it's very simple it would have been this if the sign would have been reverse the greater to lesser to sign would have been reverse then if this is not the answer which one is the exact answer this is the exact answer when the temperature is higher the curve that you draw will be more closer to the pressure curve so straightforward graphical question option c is correct option b would have been correct if the signs would have would have been reversed straightforward question okay we are talking about s-block elements here carbon we have coke here coke we know is an allotrop of carbon and it is a beautiful reducing agent so coke can be used as a reducing agent diamond diamond we know is another allotrop of carbon whose hybridization is sp3 what about fullerine we know about buck minister fullerine no so buck minister fullerine has a football or a cage like structure or appearance so it is cage like molecule what about graphite graphite is used as a dry lubricant for a very simple reason that the intermolecular forces and graphite is really low what happens sir what happens when the intermolecular force is low when the intermolecular force is low one molecule tend to slide over the other molecule so what happens when molecules slide over each other when molecules slide over each other they have less friction which means they can be used as a lubricant so that's the only logic here now you choose option a a has four so a as four done b one okay b one c four uh c four fullerine so a one minute a was three sorry a was three and b was one a was three b was one c is c is four and d is two so this will be the option okay now let's look at another question again a very simple one from the first chapter of 11 standard from the Dalton's law theory which select the correct statement from the following atoms of all elements are composed atoms of all elements are composed you'll have two here composed of two fundamental particles definitely not if you take metals metals exist as for that matter noble gases also metals and noble gases exist as monotomic so there is no compulsion that all fundamental particles should be composed of two units that's wrong the mass of an electron is 9.11 into 10 to the power minus 31 kg this statement is right or if they give it to you in grams it will be 28 grams all isotopes of the given element show same chemical property this is also correct because all isotopes have the same number of electrons if the number of electrons are same the chemical properties also would be same so this statement is also right protons and electrons are collectively known as nucleons no protons and neutrons together are known as known as nucleons so basically the particles inside the nucleus is known as nucleons Dalton's atomic theory regarded atom as the ultimate particle of mass yes this was corrected by Berzelius so Dalton considered atom to be the ultimate particle this is also wrong so we have option yes it is right he considered as the ultimate particle later it was modified by Berzelius so you have b c and e so b c and e is option e okay so these were the first 10 questions that I got to discuss with you guys hope you have understood and you kind of got a clarity as to what the answers are for these questions now next you would have another teacher discussing the questions okay so I now welcome Pallavi ma'am my colleague from the chemistry department she'll take over and start discussing a few more questions from the chemistry paper please ma'am yes hello everyone a very good evening to all of you I hope you guys did amazing job in your exams okay so our very first question it starts from 51 okay is based on an organic test okay so I hope the qualitative analysis really helped you now this lasnees test for n and s please be very careful there are three different products when it is only talking about nitrogen test when there is only it is only talking about sulfur test and then there is a different product if both of the products are if both detection is taking place simultaneously okay so this would have been your answer when it was just talking about the nitrogen test if it was just sulfur it would have been this but guys please be very careful this is the question for the detection of both the elements nitrogen and sulfur so your answer should be thiosinate so sulfur or thio so I hope you have marked your right answer option number eight okay so moving to next question very quickly yes so this is coming straight from electrochemistry now guys it can be there can be a possibility when you sometimes don't remember your formula and there your units are going to be very helpful there your units are going to be very helpful so if you see this is the unit what is this the values for conductivity and the values for resistance is given now sometimes we are very much confused with the formula like here they are asking you for the value of cell constant which is nothing but l upon a now if you remember your formula which is a direct relationship between conductivity and resistance very good way to go in case suppose suppose you don't remember your formula your how your units are going to be helpful so if you see your options your all the options are very straightforward and the unit of all the answers are in centimeter inverse as I'm just telling you one way in the case where you don't know your formula so all the answers are in centimeter inverse that that is the only possibility is they have taken out the product for resistance and conductivity and you should know that it is nothing but if you remember your basic formula electricity class 10 formula resistance is equal to rho l upon a and if you take the reciprocal of resistivity this is resistivity this is resistivity so if you take your reciprocal it is just conductivity which we denote by kappa and this is cell constant from here you will get your cell constant value which is nothing but the product for resistance and conductivity and hopefully you should get your option as straight multiplication so you should get option d just just calculate and just check okay so moving on to next question question number 53 guys this is straight coming from chemical bonding so if please be very careful they're asking you the species which is not having eight electron which is not having eight electron okay so first just check what are the species ammonia aluminum chloride with barium chloride ccl4 and pcl5 so there are some species here which is greater than eight electron which is less than eight electron which is equal to eight okay so if you see very simple compounds are given to you this this is a compound which is having three bonds with hydrogen and one lone pair okay this is barium chloride so this is four electron species straight just see the bonding and that that will help you okay this is going to be a six electron species this is four okay this is exactly your eight electron okay and this is go exceeding your eight electron number of eight electron species five cl bonds are there so this is going to be a 10 electron species and this is three bonds are there with hydrogen but be careful there is just one lone pair also so there are two compounds NH3 ccl4 which is having eight electron but they are asking for not so your answer should be three species which is not having eight electron so option number two that's the right answer guys okay moving on to next question what is the next question okay simply lewis acid what are lewis acid what are lewis acid so lewis acid are the species which are electron acceptors lewis are acids are the species which is electron acceptor and clearly you can see including with the structure they clearly you can see bf3 is a lewis acid here okay so option number four should be a right answer isn't it too direct okay so bf3 is a lewis acid let's go to next question now this question you can just see this is your coming from amines coming from amines primary amine formation are they asking not primary amine yes not primary amine okay so where you don't see the possibility of primary amine as a product formation so just see what are the options what are the reactants your amide is there amide is there where one side reduction is taking place where one side in the presence of kOH then if you see very carefully option number c and four option number c and d there is cyanide and then there is isosynide okay so guys if you see this whenever there is a reduction of primary amide reduction of amide it is always going to form one degree amine okay so this is definitely not your answer in both the cases whether it's reduction or whether it's taking place in the presence of br2 care this is the only answer nitrocyanide where you don't get your one degree amide do let me know in the comments where what is a product if it's not one degree amine what is a product okay so option four should be your answer okay let's move to next question yes now there you need to remember the pyridine structure let's go with the pyridine structure first so what is the pyridine structure it includes one n and alternate double bonds now if you see there is a there is one lone pair which is there with nitrogen so guys there are few questions where you can just apply straight elimination technique okay this is that question which can help you with eliminating the options what are those options first don't start counting your number of sigma and pi bond it might take a little it might consume your time so first just check the lone pair that there is only one lone pair in the pyridine structure and what are those options option one and four so definitely your option answer is going to be either one or four okay then you can go with the double bond i mean the pi bond number of pi bonds because that you can clearly see it is way less than number of sigma bonds and what is this three pi bonds are there so you don't even need to calculate your sigma bond please these are the things which will where your hard work will not be important your smart strategy strategy should be important so first go with your lone pair then go with your pi bond and then go with your sigma bond in fact you don't need to count your sigma bonds okay that's the very very easy options are there option four is your right answer now going to next question okay now let's see what are what is the question given okay let's see what is the structure given this is coming from solid state so see what are the details given b is a ccp structure i can also say our fcc okay now you clearly know what is the effective number for fcc or ccp z equals to four right and a is what is the detail given for a that element b is forming ccp and atoms of a are coming at tetrahedral voids but not straight tetrahedral it is just one by third of tetrahedral so first let's see if it is ccp or fcc your effective number is four and obviously there also optahedral voids will also be four but tetrahedral voids is going to be double so that's eight now if it is eight you can see in the question it is given that a is just occupying one third of eight one third of tetrahedral voids which is eight by three now they are just asking you the formula which will help you to find out the sum of these x and y the stoichiometry so let's see what is the what is going to be the possible formula a eight upon three b is simply b is simply four okay because it's b is occupying all the ccp structure corners okay now if you just simplify this is going to come as a two upon three and b okay it can go like this simple mathematics a to b three now if you just check they are not asking you the formula they are asking you the sum of these stoichiometry which is obviously two plus three so your answer is going to be option number two okay very direct but it's just that you need to be aware of the ccp structure and the tetrahedral formula tetrahedral void formula let's move to different next question okay this is very simple coming from atomic size now if you just say just check the largest time what is the largest time either it is going to be the anion with the largest charges okay or the cation with the smallest one okay that decides the largest ionic size largest ionic size now please see they're asking you the noble gas configuration checked with the options how each of them will form the noble gas formation okay n a will only lose one electron okay fluorine will gain one electron then it can achieve the noble gas configuration am i right 2 comma 10 this is also 2 comma 8 what about oxygen o2 minus and what about nitrogen only if it gains three electron it achieves the noble gas configuration so this is the only option guys if you see forget about the cation just check the anions so anion with the largest as i told you earlier anions with the largest negative charge was going to achieve the largest size okay largest size so option four should be a right answer none next question okay so this is not only just the use of any organic reaction it also involves your simple mole concept what is there in this question please see firstly you need to identify what is this which which reaction is this so if you see your reagents n a OH and in presence of CO first of all what is this reagent called it is known as soda line this is soda line so whenever you are taking your organic compound in the presence of soda line there is step down reaction taking place step down or you say degradation which means minus one carbon will happen and if you see what is the formula for sodium ethanoid ch3 coo n a and simple hydro carbon forms which is obviously two carbon is there then what is the hydrocarbon with one carbon that a simple methane okay but please don't jump to the answer and just don't take out the weight of methane which is 16 read the question properly they're asking you two moles of the product and then you have to calculate the weight of the two moles of the product so if you take two moles the weight is going to be 32 so it's not 16 guys option two is not your answer option three is your right answer yes let's go to the last question that is of question number 16 which is fully direct polymerization reaction and that too they have given you a specific product neoprene is your product if where where if you remember your monomers trade you know your answer so this is a question where there should be no confusion neoprene is the polymer if you remember your monomer for neoprene what is that chloroprene so guys let me tell you in fact you will agree with me the options are very straight they are very clear there is no confusion there is only one option with with chlorine in it am i right there is only one option and that is this one this is the structure for chloroprene no confusion if you remember the monomer name you know your answer so option c is the right answer guys okay so we are done with 51 to 60 questions let's move to different section let's take the another 10 questions yeah thank you okay hi guys welcome back again so we have completed 20 questions so so far we'll be looking at another set of next 10 questions read the question very carefully considering the following reaction identify the product p it looks like a very straightforward simple substitution kind of a reaction but it is not so we would feel that oh h can be replaced by br if oh h gets replaced by br this one of it should be the option yeah this should be the option but that's not the answer in this particular context you have something called as carbocation rearrangement which i'll talk to you about briefly so what happens is you have ch3 here then you have ch once oh h is removed this carbon will bear a positive sign that's why we call it a carbocation now what happens is this is a primary carbocation the moment hydrogen shifts to this what we refer to as 1 2 hydride shift so if hydrogen shifts what really happens i will have ch3 ch sorry hydrogen is shifting no so you'll have only carbon attached to ch3 so the hydride is shifting so this will have one more extra bond with hydrogen and ch3 finally now keep one thing in mind hydrogen along with its bond has shifted to this carbon therefore this carbon is losing one of its valence electron hence making it a carbocation what kind of a carbocation is this this is a tertiary carbocation how because the carbocation is attached to three other carbons and we should know by now tertiary carbocations are more stable compared to primary carbocation so this process of carbocation rearrangement happens to attain stability now it is very simple what is remaining now br is remaining the br will come and attack this carbon if br comes and attacks this carbon this has to be the product ch3 ch3 ch3 ch3 br will attack that carbon which bears a positive sign then you have ch2 ch3 this has to be the answer yes it is a simple case of substitution but substitution is followed by i mean carbocation rearrangement is followed by substitution so this has to be the answer okay this is the next question some tranquilizers are listed below which one from the following belongs to barbiturates simple barbiturates is a type of tranquilizer which is kind of used to artificially induce coma or it is used as a sedative and it is also used for hypnotic treatment okay this is the major role of barbiturates this is just a memory based question out of all of these four compounds verinal is the only compound which will belong to this class of chemicals called as barbiturates which is a subset of tranquilizers straightforward question now look at this which of the following statement are not correct okay are not correct first one hydrogen is used to reduce heavy metal oxides to metal all of us know hydrogen is a beautiful reducing agent so this statement is correct heavy water is used to study reaction mechanism heavy water is d2o to study about how a reaction goes about conducting itself from the initial stage to the final stage that is referred to as a mechanism to study about mechanism of a chemical reaction we definitely use heavy water which is d2o this statement is also correct third one hydrogen is used to make saturated fats from oil that is correct it will convert the double and triple bonds into single bonds that is why we say hydrogen is used to make saturated fats from oil next is hydrogen hydrogen bond dissociation enthalpy all of us know what is dissociation enthalpy correct it is the energy required to break one mole of bonds between different atoms so they say the dissociation enthalpy of hydrogen is the lowest this is wrong guys as a matter of fact dissociation enthalpy of hydrogen is the highest if you look at all single bonded species dissociation constant for hydrogen is the highest that is why it is quite stable and does not easily react with any other species so first I mean option D or statement D rather is incorrect and option E hydrogen reduces oxides of metal that are more active than iron wrong this is also incorrect because if you look at elements which are more reactive than iron you have zinc you have aluminum you have potassium all of these cannot be reduced by hydrogen because hydrogen is less reactive than these particular metals or these particular metals are more reactive than hydrogen hence hydrogen cannot reduce them so option or rather the statement D and E is incorrect which is option 4 so this is the logic behind this particular question next one identify the product in the following reaction if you have Zn and He in the presence of concentrated HCl yeah reaction either yeah reaction either this is Clemensons Clemensons reduction Clemensons reduction okay sir Clemensons reduction what is it useful for Clemensons reduction is used to convert aldehydes or ketones into respective hydrocarbons very simple it breaks this double bond oxygen double bond oxygen and in place of double bond oxygen it will introduce hydrogen it will introduce hydrogen that is the only work of Zn Hg and concentrated HCl they're just reducing agents basically now straightforwardly you can say okay I had a carbon here so that carbon two hydrogens were added and an oxygen was removed okay this matches here also two hydrogens were added to one carbon and oxygen was removed it matches straight away this has to be the answer this cannot be the answer because we are showing two two carbons correct so one see here there is scope for considering this also as the answer I will tell you why because usually the free ends indicate CH3 group okay if the free ends indicate CH3 group you will have two carbons then this will be the answer or in some cases where they don't indicate anything we say hydrogen is also applicable so if I consider this as hydrogen this will be the answer if I consider this as hydrogen this will be the answer but if I consider this as carbon and the free end as methyl this will be the answer out of my experience I am telling you usually the free ends are considered as methyl groups so there are two carbons here two carbons here hence this has to be the answer okay so let us have the clarity if the free ends are there we will consider that as methyl and if it is considered as methyl this has to be the answer okay this will let us not have any ambiguity with regards to this so option two is the answer moving on again a very simple question is asking you to predict the correct order of energies of molecular orbitals of N2 so it is sigma 1s2 sigma star 1s sigma 2s sigma star 2s then pi 2px pi 2py sigma it is a straightforward question sigma 1s is the lowest sigma star 1s a little higher in energy then comes sigma 2s then comes sigma star 2s then comes pi 2px which is equal to pi 2py then above that comes sigma 2pz and above sigma 2pz comes pi star pi star 2px equals to pi star 2py and above that finally comes sigma star 2pz this is the order and this matches with which option 1 sigma star 1 2s sigma star 2s pi 2px pi 2py then sigma 2pz then pi star 2px then pi star 2py and then sigma star 2pz so it matches with option 2 so this is to be a very simple question you just had to remember the electronic configuration 76 a question from biomolecules which most PCM students would have found little difficult to begin with statement number one a unit again a completely factual question a unit formed from the attachment of a base when a nitrogenous base is attaching to the one prime position of sugar it is known as a nucleoside this is a correct statement this statement is right okay statement two when nucleoside is linked to a phosphorus entity or a phosphorus acid at five prime position of sugar then we get nucleotide this is also correct guys basically what happens a nitrogenous base attaches to a sugar you get nucleoside nucleoside going forward attaches itself to a phosphorus acid entity or a phosphorus acid moiety together we call this as nucleotide so nucleosides plus phosphorus acid will make it nucleotide so both of this is right okay statement number one statement number two both of this is right so which option statement one and statement two are true so option two next one intermolecular forces are forces of attraction and repulsion between interacting molecules that will include basically is asking which of these will act as intermolecular forces dipole dipole force is a kind of intermolecular force basically seen between polar molecules between a polar and a polar molecule that is one of the intermolecular forces dipole induce dipole forces that is again an answer because it is seen between a polar molecule and a non-polar molecule hydrogen bonding yes it is a type of intermolecular force which plays pivotal role in a lot of other physical properties then covalent bonding these are not intermolecular forces these are intramolecular so two atoms combined together to form a molecule using covalent bonding so this is not the answer dispersion forces dispersion forces also called as London forces is seen between a non-polar molecule and a non-polar molecule so since it is seen between two molecules this will also act as intermolecular forces so it has to be a b c and e a b c and e which is option four okay next one try to understand the question properly because this links thermodynamics with electrochemistry a straightforward electrochemistry question there are two statements assertion and reason in equation delta g which is gives free energy and it is equal to minus n f e cell that's e cell so n stands for number of electrons involved number of electrons involved f is a constant faraday's constant and e cell is again what you get from the values of the electrode potential of cathode and anode now remember this is an extensive property gives free energy is an extensive property whereas e cell is an intensive property okay to just briefly tell you what intensive and extensive properties are intensive properties are those which will not depend on the size of the sample or in very simple words that particular property which doesn't depend on the amount of a substance will be referred to as intensive that which depends on the amount of the substance in the chemical reaction will be referred to as extensive so this is extensive this is intensive having understood this look at this equation in equation delta g equals to minus n f e cell value of delta g depends on n that is true because i've told you that it is an intensive property and this is a constant so obviously the value of delta g has to depend on what the number of electrons involved in the electrochemical reaction so that statement is right e cell is an intensive property and delta g is an extensive property this is also right the reason why the value of delta g will depend on n is because one is intensive the other one is a constant hence the value of this has to depend on the only person left whose value can be altered which is minus n so this statement is also right so both a and b are right and r is the correct explanation for a okay so option b moving further the relation between n m and he has very clearly told that n m is magnetic quantum number and l l is azimuthal quantum number the relationship is really simple magnetic quantum number m is equal to 2l plus 1 and here is asking us to take magnetic quantum number as nm so let's take it as nm so nm equals to 2l plus 1 so we don't have a direct version of it nl equals to l plus 2 that's not the correct one so now we'll try to rearrange this equation in terms of l so how do I rearrange simple 2l equals to nm minus 1 therefore l equals to nm minus 1 divided by 2 so do we have that nm minus 1 divided by 2 yes option 2 l equals to nm minus 1 divided by 2 a simple question again moving further a question from which is again quite easy for biology students which one of the following statement is correct magnesium plays roles in neuromuscular function and inter neuronal transmission this is not right because magnesium doesn't do this calcium does so this is incorrect second option the daily requirement of magnesium and calcium in the human body is estimated to be around 0.2 to 0.3 grams let's come back to that question all enzymes that utilize ATP in phosphate transfer requires calcium as the cofactor it does not require calcium it requires magnesium as the cofactor so we know this is also not the answer the bone in the human body is an inert that's inert and unchanging substance this is also wrong because this is very basic we know that as we age the bones are remodeled no so it's not an unchanging substances it definitely changes so if i eliminate even though you don't remember this you wouldn't have paid too much attention to these minute values but by eliminating the wrong options we get to know that this has to be the right answer okay so i've covered the next 10 questions so we will have one of our biology faculty Mr. Vicky Vaswani sir to discuss some important questions from the biology part of today's need paper i welcome you sir 151 yeah so we'll be going live with the zoology portion okay so some questions i think maybe one or two questions maybe from botany also so we'll keep discussing that also i'll just tell the answers for that yeah hello everyone so we are going to discuss the zoology question paper now so let's start with the first question that is 151 so you can easily see this is so very easy question from human physiology okay so let's see paptic cells so paptic cells are also called as what chief cells correct paptic cells are also called as chief cells so these chief cells produce what pro enzyme if you remember pro enzyme that is pepsinogen so you'll easily market what that paptic cells for what that is pro enzyme so you're getting it a as three remember a as three so no other option is there which says as three so you got easily answer them just confirm it now so goblet cells so you know goblet cells secrete what mucus correct so goblet cells will go for mucus that is one okay so you got the b as one oxyntic cells so oxyntic cells or the parietal cells you know they secrete HCl or the car cells intrinsic factor okay so what's the answer for this you see c has answer as that this one you know that is HCl and intrinsic factor so what does the intrinsic factor do it is helpful helpful for the absorption of vitamin b12 this was a question which came in need 2018 also if you remember okay so here you got c as four and d that is hepatic cells it goes clearly with the hepatic cells will produce what bile so answer will be your fourth option you can easily reduce the answer got my point very easy correct yes we'll go with the next question now so next question you see 152 was was the question here you see it's a very easy question from class 12 okay so from class 12 this is question and that says about the stds correct and it is clearly mentioned in ncrt statement is mentioned in ncrt that which diseases won't be cured if they are not diagnosed early so they are usually viral diseases correct so let's see very easy question so which of the following you see here which one of the following commonly a common sexually transmitted disease is completely curable so you can completely cure the disease which is bacterial disease but not the viral disease it's clearly mentioned in the ncrt so easy question okay so what are the viral diseases and which is the bacterial disease if you can easily identify I think it's very easy to identify see HIV is again a viral genital herpes is also what viral even the hepatitis b also viral so you can't cure these they are not curable so answer will be what simply gonorrhea gonorrhea has a bacterial disease so it's a bacterial others are what viral so such a easy question you see such a easy question okay so biology was not very tough it was mostly from ncrt correct so let's move to the next question now yeah so next question you see beta was the next question here you see select the correct group or the set of australian marsupials see now if this comes to me even I will not be able to answer easily okay because the problem is they're talking about the australian marsupials correct so you see lemur is a mammal so this is answer is wrong because he's asking about marsupials correct next comes the Tasmanian wolf bobcat marsupial mole I think we'll keep this numbat is spotted cuscus the numbat is spotted cuscus they are one is a australian marsupial other is a you know a placental mammal so we can't go with this also so we will not go with this answer next is the mole flying a squirrel and the Tasmanian tiger cat so you see whenever you have placental mammals so this is also a placental mammal this is also a placental mammal correct even numbat is also a placental mammal so you see placental mammals are excluded so this is called as process of elimination so in the process of elimination what you've done you've taken out the placental mammals now you'll be going for what for the question ask select the correct group or set of australian marsupials so which is the set of marsupials here you easily got the answer that is Tasmanian wolf bobcat and marsupial mole so this is how you go with the answers this is called as process of elimination means you have eliminated the placental mammals and you easily got what the marsupials got my point let's come to the next question beta very easy questions but i think many students would have done this question wrong i can challenge okay even after just you know passing boards now also some students would have done wrong come on let's talk about the next question now this is from human physiology chapter is body fluids and circulation so here what he's asking you see he's asking about p-wave so p-wave is for what depolarization of atria so simply you will have an option here you can see depolarization of atria is given simple so you have to match with p-wave as three got it clear in them so a goes for what three you can see here there's only one option anyway but still we will cross check okay so q wave you know that q wave that is qrs wave is for the depolarization of ventricles so that means q wave the depolarization will start correct or not so let's see q wave is the beginning of systole they haven't mentioned which systole but you understand it should be usually ventricular systole got my point let's come to the qrs now so qrs as i discuss now it will be for the depolarization of the ventricles so let's make it as b as one so you got b as one and c as four and simply you got the t-wave the t-wave is for what repolarization of ventricles correct repolarization so you got simply the answer as two so you see question was very easy if you know one answer also simply if you know the a answer as p-wave depolarization of ventricles you got the answer such a simple question they gave you see such a easy question only one option you need to know okay so such an easy question here come to the next one now but yes now we will go for 151 155 question so what does the 155 question says here let's see okay so 155 question says okay it says about matching okay so ringworm you know the ringworm the genus says which genus has caused a ringworm you know the trichophyton okay that micro micro ones are there micro spore phyton so micro phyton and trichophytons these are for what these are for the ringworms they will cause a ringworm correct so it is trichophyton simply you got it micro spore micro spore and trichophyton correct and next is phyleriasis phyleriasis is also called as eleventiasis and this is caused by woosheria bankruptcy correct so simply you got what ringworms trichophyton that is as two phyleriasis that is woosheria bankruptcy that is three so two and three malaria is by what the malaria parasite is plasmodium so you got plasmodium somewhere so that is now two three four simply you got two three four okay and next pneumonia pneumonia is by hemophilus infranzy to two three four one two three four one that simple answer you got it all right again you can check it two three four and one simple okay what it the ringworm by what trichophyton phyleriasis by what woosheria which is a roundworm malaria plasmodium is a pathogen pneumonia pathogen is hemophilus infranzy so they have talked about the pathogen pathogens and you have easily done the matching here i think it's a easy question because it was from class 12 and most of the class 12 revision you did for the boards also correct let's move to the next question now okay let's see the one of the easiest question again this is from human reproduction and it's a it's a easy question because the vast difference if you see the vast difference takes a loop around the uni bladder and comes and joins the seminal vesicle here correct so whenever it joins a vesicle seminal vesicle so ampula of the vast difference joins the seminal vesicle and forms a duct called as ejaculatory duct okay so absolutely the statement is correct i think most of you know it very well because it's some class 12 again so cavity of the cervix is called cervical canal obviously that will be called as cervical canal which along with vagina forms a birth canal so it's absolutely correct statement okay cervical canal and the vagina together will form the birth canal correct so let's talk about the options now so both are correct so wherever you see both is statement one and the statement two are correct you go for it is it okay so we just solve the 156th question correct so let's let's come to the next one now let's come to the next one yeah 157 correct so 157 is from botany but still what we'll do is we'll just check those statements RNA mutates at a faster rate correct so obviously RNA will mutate at a very fast rate that's that's understood correct because the genome is like that so viruses having RNA genome and the shorter life span mutate and evolve faster so this statement is also correct so we'll go for the option as both statement one and a statement two are correct is it okay with everyone yeah so any any doubts you have you can put in the chat okay you can put in the chat so we'll be keeping a check on the chat also if you have any doubts if you feel like you know uh means if you want some more information just just put in a chat okay come on now this question is from animal kingdom correct this question is from animal kingdom first year that is class 11th so radial symmetry now radial symmetry you know very well that is found in the tinofora the niteria and adult ikonoderms because in larval ikonoderms you have what you have bilateral okay so let's see now so ikonodermita it says it's not found in but the question is it's not found in adults of which phylum so as i told you it's found in what cylindrates that is niteria okay tinofora absolutely correct adult ikonodermita absolutely correct so it is saying not found in adult so this is found in adult so hemicorita okay hemicorita will have what bilateral symmetry okay so many students suppose if they don't know this if they don't know the answer so they can go for other way also if they you can solve in other way also you know that hemicorites have what type of symmetry it's bilateral symmetry so in that way also you can go and approach the answer it's not like you should know about all these three got it come on next question we'll see hope you are getting it hope you're getting your answers you know clear the way it has to be solved also it has to be understood how you should solve those questions correct let's let's talk about now the next question that is assertion and reason question so whenever assertion and reason question comes just read the statement or the assertion and reason properly so let's see assertion a says nephrons are the two types so nephrons are obviously of two types one is cortical one is juxtamidulary so let's see their cortical and juxtamidulary based on their relative position in the cortex and medulla obviously the cortical nephrons will be mostly in the cortex region and the juxtamidulary will be in the junction of cortex and medulla got it so let's talk about this is the absolutely correct statement next comes the juxtamidulary nephron this is a reason have short loop of Henley see juxtamidulary nephrons have long loop of Henley so they have trapped you here okay so you can see how they have trapped you they have just written juxtamidulary nephrons have short loop so this is a wrong answer so what answer will go for assertion is correct and reason is wrong so where you can see that the assertion is true but r is not the correct explanation of a so we will go for what third answer got my point okay clear no no we will go for fourth because it says a is true but r is false just give me one minute okay so let's clean this one yeah so we will go for what we will go for fourth option because third option says both are true but r is not the correct explanation but we have seen that you know nephrons are of two types is the assertion is correct but the reason is wrong because it says short loop here okay so we'll go for the fourth one clear so we just completed 159th question we'll go with 160 now okay hope you're getting this answers 160 now 160 is vital capacity of lungs is so see now they have tried to confuse you maximum here okay everyone knows that irv plus erv plus the tv is equal to what vital capacity so it's clearly given it irv plus erv plus tv okay inspirator is a volume expirator is a volume and tidal volume is equal to what vital capacity or you can also say tlc minus vc tlc minus rv is equal to what tlc minus rv is equal to vc that means residual volume when it is taken out from tlc it becomes vital capacity but here they've tried to confuse you okay so this can absolutely because it doesn't is incomplete because irv plus erv plus tv should be there so it's not there so you exclude this option irv plus erv plus tv plus rv so if we go for this it becomes the total lung capacity that is also wrong but how smartly we see they have tried to confuse a student irv plus erv plus tv minus rv what was need of writing minus rv there was no need because you're not going to subtract rv from that and then calculate the vital capacity simply in ncrt you see they have clearly mentioned irv plus erv plus tv so whenever you have these kind of questions you don't have to get into too much complexity whatever give given ncrt just go with that okay so what for this 160 that is 1 okay so 160 also we have solved it let's move to what 161 now yeah so 161 is again from botany but let's discuss it okay so which of the following are not considered as a part of endomembrane system so you know very easy question you know that g erl complex okay so what is g erl complex that is golgi endoplasmic reticulum and lysosomes correct so that is the only thing which comes in what endomembrane system correct okay so golgi endoplasmic reticulum and lysosome clear yes i think okay so let's let's talk about this what are the options now golgi obviously it will be there so he is talking which are not considered endoplasmic reticulum considered lysosome is not written so mitochondria not considered chloroplasts not considered peroxysomes not considered so you have a ce which is not considered you have to be very specific see they are asking not they are not asking which are considered so you go for a ce option here so answer is your third one got it easy now okay very nice very nice let's move to the next question now beta okay let's see again this is from what botany but let's you know do with this also so 162 162 question you see now so 162 question says that match the list with one with list two okay so you have to see list one with list two correct so let's see very easy question it is once you know a little bit of you know genes so what is gene a gene b gene 3 if you know only this wire someone has done this very easy gene z is for what beta galactosidase if you know this i think you know the answer correct or not simple such a easy question to give okay gene z codes for what beta galactosidase such a easy answer you see if you know one option you got the right answer got it come on let's move to the next question now 163 163 this is from the human health and disease okay and let's see what they mean by this let's let's talk about it yeah so you have to again match one match the list one with list two correct okay let's see so heroin heroin is a dye as style morphine correct which will cause slowing of the body action correct it will depress the system okay so let's let's wait for some time let's come down come to other options also and then we'll go with a final answer so see morphine very nicely you know that morphine is a painkiller correct so when morphine is a painkiller you just come forward d is three so where you find d is three you see simply you get the right answer the complete answer becomes right so this is a how how you should approach the answer anyway but don't go for that first you confirm your answers so d morphine is a painkiller obviously cocaine cocaine is usually interfering with your what it is interfering with your you know what you call dopamine neurotransmitter correct it is interfering with your dopamine neurotransmitters so it's c is for what the dopamine somewhere you see dopamine here so c is for what fourth correct next is marijuana so marijuana is a cannabinoid okay marijuana is a cannabinoid so it will have the effect on what cardiovascular system so let's talk about the b as what b as one and the heroin heroin will slow down the body functions because it's a depressant got it very easy question okay so let's move to the next one now now come on 164 it is from the skeletal system so let's talk about this also again it's very easy so let's see they talk about cartilaginous joint now cartilaginous joint where are they found in the body you have to think about it just a glance if you know means little bit of uh information you have that where is the cartilaginous joint found in your body so you know very well it is found in the adjacent vertebrae correct so wherever you see adjacent vertebrae you kick click it so this is the adjacent vertebrae keyword so these keywords are there which can help you to get the right answer so you got a s2 so a s2 you got in two options now okay let's move to the next one now ball and socket joint so ball and saw in the pectoral girdle between the humerus and you know is is capital means humerus and the this glenoid cavity or it is found in the hip girdle correct that is pelvic girdle so let us see pectoral girdle you see the keyword pectoral girdle nowhere you find the any girdle so you go forward this is the keyword so in this way you will get the right answer you see you go for the fourth one now you see you got the fourth one so you see now they are smart they're adding in two options they're adding the bs4 correct let's come to the c1 now fibrous joint fibrous joint are immobile first you should know this they're what immobile so when they're immobile they are found in what in the skull okay so wherever you find the skull as a keyword you can go with that okay so you got a c as one now you see you will differentiate here c as one so you got the right answer s third which you see this boy has gone wrong here they have put somewhere a that means they got confused with this one correct and saddle joint everyone knows it is found in the thumb and in the carpal and metacarpal of thumb you have the saddle joint so you got the right answer you see cross check also d is for what 3 so d is for 3 so this is why you see somewhere there someone has made this wrong got it so be very careful come on so let's discuss the next one better yeah this is from human physiology okay the the excretory products so see sorry this is from the hormones chapter this is from the hormones chapter that is chemical coordination so cck that you know coley-systo-kinan so coley-systo-kinan will never work singly it always works like cck pz whenever i teach in my class i tell them that cck is not going to work singly okay it is always going to work along with a pancreozyme in coming from the pancreas okay so here you see cck and pz wherever you see pancreas you got the answer clear next comes a gip gip is gastric inhibitory peptide so it is going to inhibit something so gastric inhibiting what gastric plants so we will go for third a nf a nf is against the ras system that is renin angiotensin aldo strong system okay so a nf comes from what atrial walls of the heart so you have the heart here you can go with cs2 so let's find cs2 verifying here is cs2 so this is the option which will go for this is the answer adh adh is what anti diuretic hormone it is also called as vasopressin it will work on what kidney so answer for d is one here okay and b is what b is your three that is gastric glands and as forward fourth pancreas so he has done correct got it see questions are not that tough if you have the basic knowledge also you can do it if you have the basic knowledge if you have the basic knowledge of the physiology how it works in your body you can easily answer it correct let's come to the next question that is your botany that is 166 so 166 is your botany question you can simply go for the answer let's see what the question here which of the following statements is correct algal booms decrease fish mortality okay so algal booms are not going to decrease they are going to increase the fish mortality means death of the fishes eutrophication refers to increase in domestic sewage and waste water in lakes so eutrophication doesn't refers to increase in domestic sewage and waste water in lakes only okay eutrophication means that how the nitrogenous compounds come and how those you know the algal booms starts okay so we'll go for the next option biomagnification refers to increase in concentration of the toxicant at successive trophic levels you know the 10 law okay so obviously the biomagnification is going to increase at the each successive trophic level okay and will be the highest in the fourth fourth trophic level so you go for the answer as third easy answer come on easy question i think come on so let's talk about the next question that is 167 167 is just matching question here you just see it's a botany again okay okay 167 option we'll see later on come on so is a anyway botany question 168 in which blood copper cells the hiv undergoes replication it's a very important question here you see in which blood copper cell the hiv is going to undergo for replication so there are two cells one is macrophages other is your helper t cells correct so here is the helper t cells so helper t cells you got it you haven't got the macrophage you got the helper t cells so helper t cells they are going to replicate in the human body correct and that is why the t helper cells or the macrophages macrophages and t helper cells they are called as a factory you know where these hiv will replicate fast clear beta come on next question we'll see now 169 i think correct okay one minute yeah 169 169 yeah so let's see you have to match the list one with list two so if you have a basic idea what is fovea fovea is found in the eye correct and that is the region which has only the cones the fovea has only the cones so maximum resolution will be in the fovea correct so let's talk about anything resolution anything talking about resolution keyword here is a resolution you got fovea answer you got a forward third option anyway we'll cross check it anyway you got the answer you see a is three so you got the answer also but go for cross checking always iris you know iris is the visible visible colored portion of the eye not the color portion it's a visible colored portion so they have clearly mentioned visible colored portion okay and those iris muscles are going to control the diameter of the pupil also that's also mentioned here very good because it has two types of muscle one is circular muscles one is radial muscles correct blind spot blind spot is the area where there's no image formation because from there the nerves are going out correct so let's see blind spot point where the optic nerve leaves the eyeball so this is option c will go for fourth so c is going for fourth b is going for one and slera slera is the white portion okay which is made up of collagen so here you can see it's made up of dense connective tissue okay this is external layer so slera will go for last second option is a correct option because d matches with what two got it now easy easy I think it's not tough okay come on so let's move to the next question now that is 170 okay so 170 question what it talks about 170 question is again I think some botany only so let's see what answer can be there so in prokaryotes the positively charged DNA is held with some negatively charged proteins called nucleoids correct okay so how in prokaryotes will you have histones no you don't have any histones in eukaryotes the negatively charged DNA is wrapped around the positively charged histone octomatiform nucleosome this is also wrong statement so you go for what both statements are false here okay so we'll go for what both statements are false in case of 170 got it come on 171 it's a bit you know not clear but still we'll try to manage it let's see come on so I'll just read it given below are the two statements one is statement one other is statement two so a statement one says statement one says ligaments okay ligaments are dense connective tissue a statement two says cartilage is dense irregular okay irregular tissue sorry it says regular tissue one minute it says the regular tissue okay so let's see yeah so it says dense regular tissue so it says regular but you know that there are skin and cartilage are irregular tissues correct is skin and cartilage are irregular so this is absolutely wrong here the statement two is wrong now comes a statement one ligaments are dense connective tissue but but it says dense irregular tissue I was not able to read it okay so let's talk about it says what dense irregular now so it's also wrong because ligaments can never be irregular they are stretch of fibers so they can never be what irregular so they are what regular so both statements will be false in this case so we'll see which option is that which says both are false answer is third so both statement one and a statement two are false here you got it very easy question okay come on so let's move to the next one that is again botany so I think the question is from genetics okay and what he is asking in that which one of the following symbols represent mating between relatives in human pad degree analysis so you know that is consangent marriages the consangent consangent managers will have double you know you can see this should be two rows here this is one row so this is ruled out this will be the answer here very easy question either easiest question in the complete biology section okay 173 now so what does a 173 question says let's let's talk about it 173 says which one of the following techniques does not serve the purpose of early diagnosis now many students did mistake I saw this boy also has the mistake here okay how you do mistake is actually he's asking what which are the following techniques does not serve you see does not serve he's asking does not serve and this boy someone has answered he has gone for enzyme linked immunosorbent assay that is actually the you know technique for early treatment so this is absolutely correct but he's asking about not that means wrong answer so recombinant DNA technology yes ELISA yes but serum and urine analysis yeah this you go for clinical things you know you don't go for early treatment when you are diagnosed with something when you have some problem then you go for blood test or urine test or if you don't have any problem and you unnecessarily go for the blood test or urine test you only go when you have some symptom or you have some you know nausea like feeling or something then you go for it so answer is absolutely this one because he's saying not which will not serve the early means diagnosis in the early stages so that should be your third option got my point serum and urine analysis come on next question is 174 here which is I think from the you know animal kingdom so it says match list with the list list one with list two so you can see a bit of you know clarity is not there but I'll write it so this is tinnia and this is the parametriom I think yeah parametriom here okay I'm writing it here parametriom and here is your periplaneta okay and here is your ferritima so let's match it now so tinnia is a platy helminthus platy helminthus have what excretory organ as flame cells so a will go for three a is going for three you see the right answer you got still we'll cross check it parametriom parametriom has a condyle vacuole correct got it so parametriom will go for condyle vacuole that is b is two here next is periplaneta periplaneta is what cockroach so periplaneta excretory organ will be what uricose glands got it so answer for c will be fourth got the right answer again ferritima ferritima is a adwam and it belongs to analytics so excretory organ for analytics was nephrida so we'll go for d as one you got the right answer as fourth okay see the questions were so easy if you have little bit idea about the you know animals here you can easily do it and this all these things were given in your chapter called as excretory products and the elimination on the first page itself they have mentioned which phylum will have which excretory organ they have clearly mentioned in that okay come on so we'll go for the next question now was the next question you see it's 175 here and it is talking about the amniocenters okay it's from reproductive health sorry it's 176 of the bhakni i think yeah yeah we did this 175 yeah yeah 175 so 175 is on the from the reproductive health chapter come on so let's talk about they're talking about the adhesion and reason question correct so adhesion says amniocentesis for sex determination is one of the strategies of reproductive and child healthcare programs that is rch program so if you apply your little bit brain will amniocentesis help in any way checking the population or something it was never meant for this even the mtps also were not meant for this so amniocentesis was a technique by which in the early stages we can check if there is some genetic disorder in a you know developing embryo okay in the developing fetus is there any genetic issues so that we can get rid of or you can just be prepared for that okay the parents should be prepared for that so not correct okay so amniocentesis for sex determination is one of the strategies if you so say i'll never agree with that okay so this is absolutely wrong but anyway so let's talk about the next reason now ban on amniocentesis checks the increasing menace of female fetuside yes in india in india it's absolutely correct because amniocentesis was a very good technique which was to detect any genetic defect in the early stage of embryo or fetus but india what they did they just try to check the x and y chromosome if she is female so many places like hariana and all they went for what female fetuside which was a very bad the you know means image we had an international community also so this is absolutely correct here so ban on amniocentesis has a check on what that is menace of female fetuside so this is correct but the first one is wrong so let's talk about it assertion should be wrong but the reason should be correct so i think you can find somewhere yeah the first option is a is false but r is true for it very nice come on so let's move to the next question now 176 so 176 is from the botany section we'll just go with the answers here so 176 the two statements are given okay one is a statement one says the electrostatic precipitate is most widely used in thermal power plant obviously it should be used correct because you have to get rid of the suit statement two says electrostatic precipitate in thermal power plant removes ionizing radiations never it can remove ionizing radiations it can remove only particulate particles it can't remove the ionizing radiation so answer is what the statement one is correct but his statement two is incorrect you go for the fourth answer here okay so 176 will be fourth answer got it okay 177 now 177 very good question they gave from the human physiology let's talk about it so once the undigested and unobserved substances enter the cecum so when they are coming to cecum that means they're coming from what a small intestine and which is the last part of the small intestine that is helium so from helium they are coming to what cecum so their backflow should be prevented by their backflow should be prevented by so let's talk about so it should be helium and cecum so it should not go again back to helium so it should be heliosecum valve it should not be a sphincter remember so sphincters are ruled out sphincters are ruled out sphincters are ruled out it should always be a valve because valve is always one way opening so you got very easy answer heliosecum valve why heliosecum valve because cecum and helium between the helium and cecum that valve should be present which will prevent the backflow got it clear come on next next question we'll see it is 178 okay so 178 question you see was that it is from the human reproduction chapter so match list with the list list one with list two vasectomy so as it says vasectomy so we are just going to cut the vas deference so wherever you see surgical method so surgically you are going to what cut the vas deference that is called as vasectomy so it's a surgical method next comes the coitus interruptus in the coitus interruptus what is happening it is a type of natural method natural method of contraception okay in the coitus interruptus you know that you know coitus is not suggested between the 10th and 17th day of the menstrual cycle okay because there only the maximum chance are there to have the sperm and egg should be meeting that that time only so that is again a natural so we'll go for a as 3 b as 4 so a as 3 b as 4 you got it here cervical caps cervical caps are always a barrier method okay cervical caps are a barrier method because they will not allow the sperm and egg to meet so that is second c we'll go for a second saheli saheli you know it is a non-esteroidal drug it was prepared in Lucknow by cdr i so it is again a oral method means it's a it's a pill so saheli is a pill which is taken orally once a week okay what my point here let's come to the next question now so 179 okay so 179 very good question they give very good question from biomolecules okay excellent question and it's absolutely the exact statement they have taken from ncrt and they have put up here simple let's see how the ncrt statement says low temperature preserves the enzyme in a temporarily inactive state yes when the temperature is low the protein will be in an inactive state but when the temperature is increased it will completely denature the protein it will be denaturing the protein so it's absolutely correct and as such the statement has come from the ncrt they have put up here only next is the statement two when the inhibitor closely resembles a substrate yes when the inhibitor will closely resemble a substrate in its molecular structure and inhibits the activity of the enzyme it is known as competitive inhibitor again the exact same statement which is written ncrt they have put up here now you have to see this is the statement is also correct this statement is also correct so we have to see that anything is matching are they talking about the reasoning here no so we have to just see where the statements are correct so answer is both statement one and statement two are true here got it and exact that statement has come from ncrt so see that is why we emphasize on studying ncrt because as such the statements may come from ncrt and I am sure that some students who have not read ncrt properly they may would have you know made a mistake or somewhere okay come on so let's talk about the next question now so 180 question that is says that says which of the following is not a cloning vector so cloning vectors you know it is pbr322 okay pbr322 bac that is bacterial artificial chromosome yac that is east artificial chromosome but do you think that probe will be a kind of cloning vector is it going to clone or probe you are going to use in a PCR or something you know which will decide the kind of segment of DNA you are checking for so probe is not going for a cloning vector it's not a cloning vector it is something which is going to read your sequence and check that sequence which you want okay so that's a probe there come on next question you see now 181 so 181 is a very good question again and it may be many students would have made mistake but it's a very easy question I think okay and it was from the chapter called locomotion and movement which are the following functions is carried out by the cytoskeleton in a cell so it can be transportation it can be nuclear division or protein synthesis or mortality so here you see nuclear division is anyway ruled out because that's not going to be with the help of cytoskeleton but in some cases like you know when they are going for this what you call when they are going for you know dividing in a you know NFA's that may sometimes require some micro filaments so that will rule out here still protein synthesis is anyway not with the help of cytoskeleton so transportation yes some you know transportation can happen but it's still not a very good option here so mortality mortality can be the right answer here why because in muscles also you see they have cytoskeleton in a muscle cell also you have what cytoskeleton which is helping in what a kind of mortality so if something has to move in a cell definitely it has to have the help of cytoskeleton so we'll go for answer as fourth okay now let's talk about the 182 see now they ask some questions from biomolecules correct and there's a very important question here you see how smartly they have asked this so given below our two statements here statement one says a protein is imagined as a line there's as such a statement from ncrd a protein is imagined as a line and the left hand represented by the first amino acid is a c terminal here you see there's a trap so left hand will always be your n terminal not the c terminal and the last that is right and by the last amino acid always should be what c terminal so this is absolutely a wrong statement okay they have taken the ncrd statement and they have changed these two terms got it statement two i think this was not mentioned in maybe same chapter but somewhere else you have this i think genetics so adult human hemoglobin consists of four subunits that is two subunits of alpha type and two subunits of beta type this absolutely correct statement because a hemoglobin is a quaternary protein it has two subunits of alpha type and two subunits of beta type alpha type has one twenty one amino acid and one twenty six are present in the beta type so this is absolutely correct statement so you'll go for what statement one is false but a statement two is true got it easy i think come on let's move to the next question so let's talk about a very good question here they give from human reproduction correct let's see given below our two statements here one is labeled as assertion other is reason so assertion will read first endometrium is necessary for the implantation of blast sources it's absolutely correct statement because if the endometrium is not there where the implantation will happen correct next comes a reason in the absence of fertilization the corpus luteum degenerates that causes a disintegration of the endometrium so this is you see explaining the first part it's explaining the assertion also because in the reason if you just read the reason now in the absence of fertilization yes in absence of fertilization the corpus luteum will degenerate if the corpus luteum degenerates it will cause what disintegration of the endometrium so the endometrium is disintegrated blast source means implantation will not happen so this is completely and completely explaining it it's supporting the first statement so whenever you find that you know state reason is supporting the assertion you'll go for the both options are correct and it is explaining it got it so let's see anything is there like that let's talk about it both a and r are true and r is the correct explanation of a so we'll go for what second answer got it come on be very careful while solving these questions you have to be very careful here okay so let's talk about the next question now what's the next question yes this is from genetics again and it is you know ncrt based question in ncrt exact those statements are mentioned in genetics you see in the down syndrome they have clearly mentioned broad palm okay with palm crease with palm crease if they have broad palm it is the answer should be what down syndrome so down syndrome the picture also the photo also they have made okay in which they have shown you the palm crease okay and the broad palm so you go for down syndrome here someone has marked I think wrong but it should be down syndrome here got it so answer should be downs syndrome come on the next question now 185 so 185 question what's that again from reproduction let's see here which of the following statements are correct regarding the female reproductive cycle so let's see in non primate mammals cyclic changes during reproduction are called Easter cycle absolutely correct statement because non primates it's called Easter cycle and primates it is called as menstrual cycle correct now this is absolutely correct first menstrual cycle begins at puberty and it's called menopause you see it's not called menopause menopause is the last end menarch it should be what first menstrual cycle is menarch so we solved these type of questions if you remember okay these type of questions we solved also during the before I think 15 days of examination also we were discussing these questions and we did this kind of question okay so you got it correct now so this is wrong lack of menstruation maybe indicative of pregnancy now you don't have to think about so much advanced you know versions of this you have to think what is written ncrt and ncrt clearly mentioned this statement as such this statement is written that lack of menstruation is indicative of pregnancy as such a statement is written in ncrt this is absolutely correct next comes the cyclic menstruation extends between menarch and menopause this is absolutely correct again so what you have to find out now which of the following statements are correct so you got a correct, c correct and d correct so you got the right answer as first one clear such a easy question you see such a easy question it is as such each and every statement is coming from ncrt okay come on so 186 now we will see I think 186 we will see now yeah we got it so let's see 186 question what the question says here which of the following statements are correct regarding skeletal muscles please see skeletal muscles and many students I am damn sure they would have done this mistake here what was the mistake I can tell you now muscle bundles are held together by collagenous connective tissue layer called fascicle so you see many students would have done mistake because it was written fascicle here and it should be here fascia why it should be fascia because there are many muscle bundles it is not one bundle so when one bundle is covered by a connective tissue layer it is called fascicle when many bundles all these bundles are covered by a common collagenous connective tissue that should be called as fascia so this is absolutely wrong statement here and he's talking about the correct ones sarcoplasmic reticulum or muscle fiber is a storehouse of calcium ions absolutely correct okay because sarcoplasmic reticulum will restore what calcium ions and when it is needed it will send to the sarcoplasm correct next is striated appearance of a skeletal muscle is due to the distribution pattern of actin and myosin proteins absolutely correct see actin and myosin proteins many students think they're not present in the smooth muscles but they're present there they're not arranged in a proper pattern so distribution pattern is important which is there in what which is there in the striated muscles or the skeleton muscles got my point here next last point you see m line is considered as functional unit of contraction called sarcomere absolutely wrong m line is in the middle of what the a band it is never a functional unit okay it will disappear when the muscle is contracting so this is absolutely wrong statement so two statements are wrong one is a and one is d so correct ones are what b and c so where you saw the b and c the third option so b and c are the correct answers got my point here clear very easy question if you have a little bit idea of that okay come on so 187 we'll see now 187 what's that question now 187 says how you are going to differentiate okay what is the following which are the following is characteristic feature of cockroach regarding sexual dimorphism sexual dimorphism means how you are going to differentiate the male cockroach and the female cockroach correct so male and female cockroach can be only you know differentiated by one structure that is anal style not sarcai it should be anal style so wherever you see the keyword as anal style go for it you see such a easy question they give such a easy question and someone is marking you see someone paper is there and he's marking dark brown body and all not required okay so it's a very easy question which is anal style is found in males it is not found in females so clearly you have differentiated between what male and female got it come on 188 now 187 we did now 188 so 188 is a very important question very nice question they made you see very nicely they have made from ncrt let's see the question first which are the following your statements are correct now correct it says an excessive loss of body fluid from the body switches off switches of osmo receptors now you think that when the body is losing you know excessive loss of fluid is taking from the body will it switch off the osmo receptors or at that time it is an emergency it has to you know activate it an ncrt statement was written it activates the osmo receptor the same statement they have given for ncrt it should be activates which is wrong here so this is statement is wrong adh facilitates water reabsorption to prevent diuresis see any student who knows a full form of this anti diuretic hormone so it will prevent diuresis simple clear it's absolutely correct anf causes vasodilation yes because anf is coming from the heart and it is causing the vasodilation because excessive pressure is there on the heart muscles so it is releasing the hormone from the atria of the atrial walls of the heart so that is absolutely correct and it is against the RAS system you know renin angiotensin aldosterone system it works against that now adh causes increase in blood pressure you know the other name of adh if you know the other name of adh this also you will do it correct how adh name other name is vasopressin vasopressin means it will constrict the blood vessels so it will constrict the blood vessel mean it will increase the blood pressure got it now this is also correct now adh is responsible for decrease in gfr how is it possible when adh is working blood pressure is increasing blood volume is increasing so blood pressure and blood volume when they increase do you think that gfr will decrease or increase so this is also this will be wrong so what how many you got the correct one so you got the b c and d as correct so b c and d i am telling you many students would have done this wrong i can see here also many students were not clear in their approach the conceptual learning should be there you know you should learn the concepts how this mechanism is operating in your body how your kidneys are functioning that is the only you know reason why human physiology questions are there for you which if you do correct then only you will get the best marks or the maybe the hundred percent marks okay so understand the concepts here come on so let's talk about the 189 question now 189 again is from botany here so we'll just see what's the answer for this come on let's let's take the answer the answer should be i think the logistic growth is going forward person individuals of pre reproductive age is the largest followed by reproductive and post reproductive age groups correct exponential growth will happen only when there's unlimited resource so you got the keyword here correct you got the keyword so a is for three okay sorry a is for two here okay a is for two and b is for one correct a is for two and b is for one i think 189 once you can check it once again 189 yeah so a is for two and b is for one okay expanding pay age pyramid expanding age pyramid should be when you have the percent in size i think this will go forward see you will go for three okay b you will go for two exponential growth will happen only when there is limited unlimited resource so b you go for one a you go for two c you go for three and d you go for four got it come on the next question now now 190th question you see which talks about the mammals here so what is the feature of mammal what is a unique feature of mammal the unique feature if i talk about you will definitely say it's mammary glands so one option you know that is mammary glands correct so wherever mammary glands are not there you remove that okay so that is your fourth option is gone okay fourth option is gone even it says indirect development which is wrong so mammary glands are given now in three cases now next unique character of mammals is what hairs so hairs mammary glands so where is hairs and mammary glands you got these two options now one is hairs timpanic membrane and hairs and pinna so i'll go for three why because timpanic membrane is also found in amphibians it is also one in reptiles so timpanic membrane can't be a unique character to mammals so hairs pinna and mammary glands that's the right answer for mammals that is a unique characters of mammal got my point now let's go for the next question now 191 so 191 i think which is again from botany here but it's still you see was the right answer for that which one of the following is the sequence on corresponding coding is strand is a sequence on mRNA form is as follows that is 5 prime a u c okay so 5 prime is saying a u c so you just see a is a will go for what a you'll replace with u correct so let's see now what sequence you'll go for what 191 you'll go for what it's a mRNA sorry it's a mRNA sequence so mRNA sequence you'll go for what a will go for a u will go for t correct u will go for what t because mRNA is forming the DNA now so you will go for what 5 prime a t c okay 5 5 prime a t c g that's the answer for that okay come on next question we'll see now again it's from botany only so let's see what it says here come on so given below our two statements statement one says during g zero phase of cell cycle the cell is metabolically inactive so g not phase g not phase is what g not phase is the resting phase correct in which the cell is not dividing so in that case you see the statement one should be correct or incorrect so g not phase is resting phase resting phase is what inactive that's correct next question next statement the centrozome undergoes duplication during s phase is absolutely correct okay so this is also correct and the above one is also correct so we'll go forward both statements one and two are correct for it come on let's move to the next question now i think there was a easy question here okay now we'll go for the next question that is select the correct statements with the reference to chordates the chordates characters you know what are the characters of chordates one is the pharyngeal gill slit one is your post anal tail other is your notochord and now chord correct four characters but they are very smart in asking questions you see presence of mid dorsal mid dorsals solid and double nerve chord do you think the chordates now chord is double that was clearly mentioned in ncrt ncrt they have clearly mentioned this point when they differentiated between what non chordates and chordates they have clearly mentioned they have made two columns in that double now chord is found in what double now chord is found in non chordates not in chordates so this is the absolutely wrong statement correct presence of closed circulatory system absolutely correct closed circulatory system is a characteristic of chordates next presence of paired pharyngeal gill slits that is also absolutely correct because in all chordates at some stage of development you will find what paired pharyngeal gill slits absolutely correct next presence of dorsal heart do you think chordates have dorsal heart or ventral heart you also were the were in the exam so you know your heart is on what side ventral side so this is absolutely wrong statement okay so chordates will have ventral heart next one triploblastic yes chordates are triploblastic are they pseudo silo mate or silo mate pseudo so silo mate only one phylum is here that is the phylum as Kelvin this so this is absolutely wrong here so you got what you got right as what you got only one as correct answer correct only one option is sorry two options one is your b another is c okay so let's talk about the correct options correct options are what the b1 that is presence of closed circulatory system and the c1 that is presence of paired pharyngeal gill slits these are the only two options are correct so you go for what b and c you got it easy come on easy easy match the list one with list two match the followings are very easy i think sometimes if you know one of the answer you can do the other one easily so here you have the mass cells mass cells where are they found they are found in a connective tissue simply you go for connective tissue where is that but now there are two options one is this one is this so mass cells will be found in a reolar connectivity issue okay still wait next comes the inner surface of bronchioles so inner surface of bronchioles so bronchioles usually have what type of epithelium you know it has a c-leated epithelium that is why you know bronchioles from bronchioles you have the dust particles coming out okay when there's an infection or inflammation then you know the mucus comes out from the upper regions so it should be c-leated epithelium next is blood so blood you know is a specialized the connective tissue it's a only connected issue which is fluid okay so that's a specialized the connected issue you got it very easily cs4 so you see the cs4 are two options here now come for a d now tubular parts of nephron so tubules of nephrons that is pct dct all will have the cuboidal epithelium brush bordered cuboidal epithelium not c-leated so you have ruled out the c-leated you have brush bordered cuboidal epithelium so that means d is for three so wherever you see d is for three there are two options now again cs4 d is three mass cells mass cells will be found in what are you all are connected issue you go forward as two as two the option answer is fourth a2 and b b is what inner surface or bronchioles that is c-leated you got the answer now clear so answer for 194 is fourth got it come on next now 195 195 very good question here very good question and that was that was from the chapter called strategies correct let's see the question which one of the following is not again you see this is the keyword here not an advantage of inbreeding not an advantage so first option it decreases the productivity of inbred population after continuous breeding yes that is a because if you go for continuous inbreeding they'll lose a vigor and vitality so this is statement is absolutely correct okay but anyway that's not a very good advantage or something but it's still option is correct it decreases homozygosity or increases homozygosity that was clearly mentioned the term is the word is mentioned it increases homozygosity so i got the answer as the wrong answer you see not so wrong answer i easily got it but it's still i'll read the other options also it exposes harmful recessive genes that are eliminated by selection absolutely correct it will remove those harmful recessive genes that is also a statement is given in ncrd elimination of less desirable genes and accumulation of superior genes yes this usually takes space when continuous inbreeding is going on so you have the superior genes which are getting favored correct so this is also correct anyway you got the answer but still you go for the other options you have to read once to cross check yourself okay let's move to the next question now that is 196 okay this is from what this is from i think human body fluids human physiology body fluids so which are the following statements are correct let's read the first statement basophils are the most abundant cells of the total WPC no neutrophils are the most abundant okay neutrophils are the most abundant so this is the wrong statement basophils secret histamine serotonin and haparin this absolutely correct they are quite similar to the mast cells of the connected shoes so this is absolutely correct and the basophils are involved in inflammatory responses yes they will be involved in what inflammatory response but still wait now basophils have kidney-shaped nucleus kidney-shaped nucleus is found in monocytes if you remember so this is also gone are the basophils granulocytes or agranulocytes this is also gone correct so now what options do you think now are left only i think b and c are left correct so we'll go for what b and c as the correct options got it b and c is it okay with you all so we completed 196 almost two three questions are more left so let's complete it first 197 197 what the question says here i think this is from the hormones chapter that is chemical coordination so which are the following are not again you see the keyword here not under the control of thyroid hormones when the thyroid hormones work they increase your BMR they maintain your BMR they support your erythropoiesis that is RBC formation so all these things if you know if you have in your mind you can easily solve these kind of questions let's see maintenance of water and electrolyte balance obviously thyroid hormones are meant for that they maintain water and electrolyte balance but it's still it's a function of aldosterone also we will wait regulation of basal metabolic rate absolutely correct BMR BMR is maintained by thyroid hormones normal rhythm of sleep wake cycle never sleep wake cycle comes from the pineal gland that is melatonin hormone so this is absolutely wrong statement here and he's talking about which are the following are not under that that means this answer development of immune system development of immune system is not a function of thyroid hormone that also is wrong statement but your answer is that supports the process of RBC formation this is absolutely correct so this is correct for thyroid this is correct for thyroid so only two statements are not correct for thyroid that is C and D so our answer should be what C and D only you got it how to get the answer that not he's asking about not the under the control of thyroid so these two are not under the control of thyroid hormones they both are under the control of pineal gland that is which is secreting the melatonin hormone correct got it let's go for the fourth answer for 197 correct 198 we'll see now so what was the 198 question I think 198 is again the botany answer the botany question here so let's see so at the correct statement okay but this from the cell biology this somewhat cell biology so let's see 198 question so I think he's asking the correct statement the tetrad formation is seen during laprotein I think tetrad formation is not seen during laprotein it is seen in ZPDD okay zygotein okay peccatine so LZPDD I think it's zygotein so let's wait this is during anaphase the centromeres is split and chromated separate is absolutely correct during anaphase the centromeres is splitting and the chromates are separating that's absolutely correct termination takes place during peccatine no it takes place in the later stages in the prophase that's also wrong so B is correct we'll go for B first nucleolus golgi complex and ERR reformed during kilophase that's also absolutely correct crossing over takes place between sister chromatids or of homologous chromosome or non-homologous chromosome so we'll go for B and D as a correct answer okay let's go for B and D okay 199 now the parts of human brain that helps in what this was a question we discussed in the you know during our discussion before 10 15 days when we're discussing the question papers and I clearly mentioned you I clearly mentioned you that this question may come and what you have to answer if you remember the parts of human brain that helps in regulation of sexual behavior expression of excitement pleasure rage and fear many students were giving answer at the time as only as limbic system but then I mentioned you that it's not only limbic system it is limbic system along with hypothalamus and that question has come as such you see okay it's not hippocampus it's along with hypothalamus so you got the right answer here limbic system and hypothalamus so it's very important to discuss the question papers also okay so better we discuss these questions also before there I think one more one way before examination we discuss all these okay come on last question we'll see now was the last question you see here so again a good question yeah because many students won't be knowing about the phallic gland that was given only in the diagrams okay in the diagram only it was given it was not mentioned something more about it so let's see in cockroach excretion is brought about by but I think you would have done correct because in at one place it was mentioned that excretion in cockroach is carried out only by what nephrocytes urechus glands and fat bodies that statement was written okay so if you would have read that statement you would have easily got the answer as b c and d okay whether phallic gland was mentioned or not it was only mentioned in diagram but you could have got the answer as correct if you would have read the statement so answer is what b c d somewhere you can see b c d yeah that's fourth one and you see someone has done wrong also the student has clicked it so I think now we are done with the zoology portion now wassala ma'am will be taking your botany portion okay thank you okay welcome again guys now let's give the biology minds a little break so you have seen enough of zoology so before we start with the botany let us get into chemistry again solve some problems and then we will go back to biology okay now we would be looking at the next 10 questions you would have total of 20 questions left this is the first 10 of the 20 questions left we are talking about pumice stone very simple pumice stone you would have come across this as a rubbing stone that we use while we're taking but what is pumice stone made up of simple it is made up of solid stone particles which has captured gaseous molecules so it's a solid particle which contains gases in it what is the solid or gas in a solid referred to as a gas in a solid colloid is referred to as a solid sol a very simple question we'll move ahead next which of the following statements are incorrect is the point all the transition metals except scandium form mo oxides which are ionic statement is right no doubt about it to be remembered the highest oxidation numbers corresponding to the group number in transition metal oxide is attained in se2o3 and mn2o7 correct in mn2o7 it is plus 7 which is the highest for manganese and here it is plus 3 which is the highest for scandium correct basic character increases from v2o3 to v2o4 to v2o5 this statement is incorrect very simple oxidation numbers are increasing oxidation number increases basicity should decrease basicity won't increase if you ask me why should basicity decrease because covalent character increases so this statement is wrong next v2o4 dissolves an acid to give v0o4 3 minus salts no it will give you v0o2 plus a statement straight out of ncrt so these two statements are wrong all the other statements are correct so it has to be option c and d straight out of ncrt questions now moving ahead on balancing the given redox reaction is given you a redox reaction and he's asking you for these stoichiometric coefficients it's very simple guys what we will do is we will just write the change in oxidation numbers and we will know cr2 plus is plus 6 from plus 6 it is becoming plus 3 so the change in oxidation number oxidation number is decreasing by 3 and there are two chromiums in 2 3 so that's 6 so the oxidation number of sulphur here is plus 4 from plus 4 it is becoming plus 6 so the change in oxidation number oxidation number is increasing by 2 all of us know what do we do with redox no whatever is the oxidation number change here we multiply chromium by that number and whatever is the oxidation number change for chromium we multiply sulphur by that number so basically it is 2 and 6 and all of us know we can dissolve I mean we can divide this by 2 because it is the multiples of 2 so this becomes 1 this becomes 3 look for an option which has a as 1 and b as 3 so option 2 straight away we can mark you don't even have to go ahead and balance the equation option 1 has 1 and 3 as a and b we have our answer in less than a minutes time okay moving on to next question what fraction of one edge centered octahedral void lies in one unit cell all of us know how a unit cell looks like no okay one unit cell is surrounded by how many unit cell one unit cell will be surrounded by four other unit cells one in the front one in the back one to the left and the right if you talk about center of a edge center now one unit cell will be surrounded by four unit cell so basically one edge center will be shared by four unit cells so the answer has to be one divided by four concept is very simple this is the edge center the edge center will be shared by how many unit cells this center is shared by one and two and in the second layer again it will be shared by one and two so basically this point or this point on the edge will be shared by four cells and that's one divided by four being the answer next one which of the complex is the most stable very simple you can straight away mark option D as the answer because this is a bidentate ligand and in bidentate ligands we get to see something called as chelation and wherever there is chance for chelation its stability automatically increases because it forms a four or a six membered ring structure formation of ring structure is referred to as chelation done okay which among the following will be the most readily dehydrated under acidic condition look at the options and you will have to check for those species which are beta hydroxy alcohol so what happens is this has a chance of becoming a molecule like this due to tautomerism it can become this there's one more ch2 C double bond O that's one carbon C double bond O and ch3 okay it has a chance of tautomerism if it has a chance of tautomerism this is beta hydroxy aldehyde or ketone beta hydroxy aldehydes and ketones are the ones that can be readily dehydrated so this has to be the option due to just a point that it is beta hydroxy aldehyde next one very simple let's say you have a lot of nutrients in the form of phosphates in a water body that will help in the growth of algae if algae grows such a body is referred to as eutrophication so nutrient deficient water leads to eutrophication no nutrient rich water body leads to eutrophication and nutrient we are considering as phosphates so statement number one is wrong statement two eutrophication leads to decrease in the level of oxygen that's hundred percent right see what happens when there is excessive nutrients algae grows algae grows at what cost at the cost of the dissolved oxygen present in water so what happens if the dissolved oxygen decreases aquatic water body I mean aquatic water beings face the problem so statement number one is wrong and statement number two is right so which is option one simple organic question aldehydes if it undergoes reduction what will it lead to if aldehydes undergo reduction it will lead to the formation of a primary alcohol what will happen if primary alcohols undergo reaction with sulfuric acid this is a dehydrating agent water and hydrogen gets removed so it will lead to the formation of an alkene perfect what will happen when an alkene reacts with HBr when an alkene reacts with HBr simple H gets added to one carbon Br gets added to another carbon it will lead to the formation of CH3 CH2Br okay this is alkyl halide this is aryl halide reaction between alkyl halide and aryl halide in the presence of sodium and dry ether is what is referred to as Wood's reaction so when an alkyl halide and aryl halide reacts it is Wood's fatigue reaction leading to this formation basically bromine and bromine combines with sodium in order for CH3 CH2 to combine with benzene ring the simple Wood's fatigue reaction equilibrium concentration of the species in the reaction A B C D R 2 3 10 and 6 these are the numbers involved 2 3 10 and 6 respectively so we are asked to find out delta G 0 it's a simple calculation based question delta G 0 is what minus n F or minus 2.303 RT log K okay our work is to find out delta G 0 let's substitute minus 2.303 most of you would have made this mistake of substituting 8.3144 log R value R value is 2 why is it 2 because the unit taken as calories and temperature is 300 into log what is the concentration of the products products are C and D concentration of product is 10 and 6 10 and 6 what's the concentration of reactants 2 and 3 okay 2 and 3 so 3 ones are 3 2s are so 2 ones are 2 ones are okay think 2 3 10 and 6 okay so if you go ahead and simplify this it will be minus 2.303 it's 2 3 for A B 2 3 okay so it's 2 3 for products and for reactants and 10 and 6 for products so that's 2 1s 2 thrice 3 and 3 log 10 all of us know log 10 is 1 how much is this 300 into 2 600 600 into 2 approximately 1200 and the answer that's matching is this option for 1300 and minus sign is there so minus 1381 a very simple one okay this will require knowledge of the structures of the acids involved here peroxo disulfuric acid peroxo disulfuric acid is H 2 H 2 O 8 H 2 S 2 O 8 you will have to know the structure it is O double bond O double bond O this is peroxo disulfuric acid next sulfuric acid sulfuric acid straight away I'll write the formula I mean the molecular structure H 2 SO 4 so this is the structure and pyrosulfuric acid pyrosulfuric acid is S O O S double bond O double bond O OH and that's 1 2 3 4 5 OH so I think the total count of oxygen 1 2 3 4 5 6 7 8 it should be 7 only so it's single bond sulfur this is the structure and sulfurous acid sulfurous acid is H 2 S O 3 these are the structures very simple guys we'll connect them 2 S OH bonds 4 S double bond O bonds and 1 S O S I have S O S here so 1 S O S 4 S double bond O and 2 S OH so this is nothing but pyrosulfuric acid connect that next one 2 SO H 1 S double bond O 2 S OH and 1 S double bond O it is sulfurous acid and then 2 S O SO H 4 S double bond O and 1 S O O S S O S though we have only in peroxid isulfuric no so this will be this and last one what is left C B sulfuric acid no sulfuric acid can be connected to this 2 S OH and 1 so now you figure out A is what A is 3 so A is 3 either A or B next B C is what C is 1 C is 1 so this has to be the option okay so that would be the end of 10 questions for me so it was great discussing the 30 questions of NEET for today I'll quickly introduce my colleague Pallavi to take forward the remaining 10 questions and wind up chemistry completely guys so guys let's wind up the remaining 10 questions of chemistry okay so let's start with the first very first question which doesn't need any explanation if you only know the clear difference between vinylic and allylic so this is clearly the answer is allylic ally because you can see the positioning of double bond air with respect to halogens okay let's move to next question now read the if you read the statement this is talking about the sodium this is this is talking about sodium in liquid ammonia so when we take sodium dissolves in liquid ammonia it forms it evolves out the ammoniated electron and if you know that an electron has evolved that means it is definitely going to be paramagnetic but the reason for deep blue solution is also the same ammoniated electron and then there is a simultaneous disformation of sodium ammonia complex so it is definitely not the amide complex so your assertion is true but your reason is false okay so which is that option option number four okay there is no amide formation but yes that deep blue solution is ammoniated electron and it is paramagnetic okay moving to next question now in this reaction if you see the very first step the product is already given okay what is happening this the asynad attack has already taken place now when you take conch H2O4 firstly this conch H2O4 will what will be the effect on this compound so it is going to form it is COOH okay but we are still left with the heating thing okay heating so what will happen with this heating effect this is going to there is one hydrogen this side there is one hydrogen either of either of the two hydrogens you take and this is going to form the double bond so just check the COOH is still left which is that option so option number one okay let's move to another question yes so if you see the stability of Cu2 plus they are asking you the reason for stability of to Cu2 plus now if you see what are the what is the comparison Cu2 plus and Cu plus since the charge density is more here the power of like this more high water molecules will be surrounding the Cu2 plus and it will form more stable bonds with this Cu2 plus compared to Cu plus so because of the charge great charge density the hydration bond will be stronger and that is the reason for the stability of Cu2 plus so your answer option is four now let's move to the next question the questions are really easy now this is a question where like the in fact this is a debate question like if you see the assertion the statement what is the statement just a minute okay what is the statement here written so a reaction can have zero activation energy in general if the you read the statement yes most almost all the reactions have zero activation energy but you might have this is a bit updated questions you might have not read about the features of woods reaction obviously I've read about woods reaction but if you go to the activation energy of the woods reaction what happens there there you take two methyl free radicals and they are so reactive that they don't even need there's some extra energy and because of which even with zero activation energy this reaction is successful so although the statement looks like false but in if you take the possibility of woods reaction this statement gets the statement is true so most of you might have chosen this option which might where you might get the marks but actually this is also true that option number three why please check both the statements are correct this this is definitely correct because this is clear definition for activation energy but this is not at all the reason behind the statement so some of you might have taken this as your answer some of you might have taken this let's see what is going to be where you might score in your results okay so let's move to the next question now what is the next question let's move to next question now this this clearly what you have to apply let's go back to the previous question this clearly applies the Huckel's rule now what is this Huckel's rule it's already written 4n plus 2 pi okay 4n plus 2 pi electron just simply do the mathematics take out the n value wherever you get the exact n value there those compounds are following your obeys Huckel's rule okay so what are those just try to find it one must be this one two three four five six this is clearly following that 4n plus 2 okay so similarly if you go for all the compounds check this check this formula 4n plus 2 and your answer you out of all this four species are definitely obeying the Huckel's rule you have to find out which one okay so your answer is option two okay let's move to next question now this is very simple organic reaction what is happening here just see now in the presence of HIN heating firstly if you break this from where the cleavage is happening this is going to form your phenoxide ion and with the negative charge on O obviously it is going to get attracted to this part this one H and this one with the positive charge is going to get attracted to the I part so which option is the most correct one if you see option number four okay moving to the next question very easy questions let's move to the next one this is a factual question where you need to at least remember the blast furnace reactions okay so the one which is not at all taking place in this clear in this range in this range is option number b okay this is that reaction which doesn't take place in the blast furnace with this different with this range okay now let's move to next question now this is the question where you can apply the tolerance reagent distinguishing test what is tolerance reagent if you can see this is tolerance reagent and how does it distinguish aldehyde ketones so it is going to oxidize the aldehyde part but it never oxidize the normal ketones okay so which option where where do you see the oxidation of this aldehyde but no oxidation of this part and this is option number four where you see the oxidation of aldehyde into carboxylic acid but no oxidation of ketone has taken place okay let's move to the next question the last question of chemistry which is simply showing you the relationship between the change in the enthalpy change in the enthalpy delta h and change in the internal energy okay change in the internal energy delta h and delta u so if you see you have read about the relationship between delta h delta u p delta v where where we all the options are in the form of number of moles and the option number three is correct so this winds up your chemistry section and we are back with the uh biology question so what salam will be talking about discussing the biology questions thank you good evening everyone so because boutney your favorite subject i decided to come in the last fine so let's go quickly now so regarding the answers so what is the role of polymerase three in the process of transcription in eukaryotes so you know that polymerase one is related to it it helps in the formation of rRNA so polymerase to mRNA and polymerase three tRNA so hence the answer should be so it should be three so let me take the color yeah okay so let's go to the next question so movement and accumulation of ions across a membrane against their concentration against their concentration is the question here so against their concentration so against the concentration is uphill movement and hence the option is active transportation so let's go to the next question so upon exposure to uv radiation dna stained with ethidium bromide will show orange color so you have seen that so orange color is the answer so this is with respect to your ncrt orange is the answer so coming to the next question so the thickness of ozone in a column of air the atmosphere is measured in terms of dobson's unit so that should be your answer okay so let's go to the next question so among eukaryotes the replication of dna takes place in so you all know that synthetic phase is the phase where replication of dna takes place and hence the answer is s phase okay so let's go to the next question question number 106 spring of which of the following phyto hormone on juvenile conifer the same to same sentence is given in your ncrt so helps in hasening the maturity period that leads to early seed formation it is gibalic acid and that's the answer so let's go for tafford to the question number 107 so here there are two statements let me read the statement one the forces generated by transpiration can lift a xylem sized column of water over 130 meters height yes so more than 100 meters is sequoia gigantia redwood trees and therefore this statement is true and statement two is all about the transpiration cools leaf surfaces sometimes 10 to 15 degrees by evaporate cooling yes of course so whatever the perspiration in human beings is related to the transpiration in plants it requires the cooling effect and hence both the statement are correct and your answer should be option two so the historic convention on biological diversity the earth summit so was held in Rio de Janeiro in the year 1992 it happened in from 3rd to 14th june so it happened in Rio de Janeiro so that should be your option option 3 so ncrt direct question so let's go to the next which micronutrient is required for splitting of water molecules the element that is involved in oxygen evolving complex is manganese and hence the option two should be your answer so let's go to the next question so given below our two statement one is labeled as assertion a so this is an assertion reasoning statement so ATP is used at two steps in glycolysis okay so first ATP is used in converting glucose into glucose 6-phosphate and second ATP is used in conversion of fructose 6-phosphate to fructose 1 6-phosphate so these two are involved in the investment phase you know that glycolysis has 10 steps where first five steps are investment and the next five steps are payoff phase in the investment phase so this is in two ATPs are required so hence the option should be and ATP is used in two steps and this is the correct explanation so therefore the option should be so both a and r are true and r is the correct explanation of a option two okay so let's go to the next question so that is 111 large colorful fragment this is the easiest question so in this paper so this is large and colorful brightly colored so vibrant colored petals are present in the insect pollinating flasks and this is the easiest question next one so given below our two statement again this is the assertion and reasoning question 112 question so this is so a the first stage of gametophyte in the life cycle of moss said that's bryophytes is protonima yes that's right so it is protonima and the protonima develops directly from spores produced in capsium yes that's right so embryo fighter begins from bryophytes and hence this answer both are correct and option two is the answer so let's go to the next question so which of the following stages of meiosis involve division of centromere because division of centromere doesn't takes place in meiosis one so meiosis two is required so meiosis has two phases phase one is the reduction and phase two is the equational phase and hence the option is and a phase two so let's go to the next question so it's 114 in angiosperm the haploid deployed and triploid structures in the fertilized embryo sack so you know that so everything in the female gametophyte that's a embryo sack is a haploid structure and one of that structure is synergies so synergies haploid haploid zygote is deployed and primary endosperm nucleus which is formed from triple fusion is a triploid so the option four is a correct explanation so 115 expressed sequent tags refer to what are estes estes are you come across that in two chapters one is the molecular genetics and another is the biotechnology so here the option two so all genes that are expressed as RNA so to have the precise explanation for the same ease so you can write it down if you want so messenger RNA sequences derived through single sequencing reactions performed on randomly selected clones from complementary DNA cDNA so therefore the option correct option is two so let's go to the next question so here it is a statement based endarch and exarch so when we say endarch and exarch endarch is development of the proto xylem towards the center and exarch is the proto xylem coming towards the periphery so therefore this is the characteristic feature of primary xylem so here they have given the secondary xylem so therefore that statement is wrong okay so here they have given the secondary xylem which is the wrong statement and exarch condition is the more common feature of root system yes so we get to see that in the root system and therefore so option one is wrong option two is correct so here yeah this is the correct answer so going to the next question what is the function of tassels so this is another very easy question for today so this is to trap pollen grains so what are tassels so they are the style okay so which trap so they are the gynaecium so they are the stigma style stigma which trap the pollen grains so therefore the option is three option three is the correct answer for this so going to the next question the process of appearance of recombination or dual occurs at which substrate or so prophase one recombination begins in packaging stage of the prophase one and therefore the option is three packaging so the next question 119 the phenomenon of pleotropism refers to so pleotrophism what is pleotrophism so a single gene affecting multiple phenotypic expression so multiple the classic example is signals in lanemia which is given in your ncrt so therefore the correct answer is option four so let's go to the next question so here so which all the options are right so deputy posts perform fragmentation yes so this is from your ecology chapter ecosystem so yes that is the right option okay so the humans is further degraded by some microbes during mineralization yes that is right and what is soluble inorganic nutrients go down into the soil and get precipitated by a process called the leaching so all the three options are correct and rest two are wrong so you can this is another easy question for today so it is directly the statements are directly from your ncrt so therefore abc is the right option cellulose does not form blue color like how are you starch forms what could be the reason so it does not contain complex helices like how starch has and hence cannot hold iodine molecules in the helical structure so no helices no iodine no sorry no blue color so therefore option four is the correct answer so in this equation so there's a gross and this is net so gross primary production minus r gives the net primary production so what is that r stands for so that is your question so here r is the respiratory losses in the producers so therefore option four is the right answer so how many ATP and NADPH2 are required for the synthesis of one molecule of glucose during calving cycle so one molecule of glucose requires six molecules of carbon dioxide so therefore six cycles it has to go through and totally we need 18 ATP and 12 NADPH2 so this is in the calving cycle calving cycle is a c3 pathway not c4 pathway c3 pathway hence the correct option is 18 ATP and 12 NADPH option three so in gene gun method used to introduce alien DNA to into the host cell micro particles of which metal is used so either gold or tungsten so they are they are used so gold is the noble metal and tungsten has high melting point so therefore these two are used in this process hence the option four is the correct answer so among the evil quartet which one is considered the most important cause driving extinction of species extinction of species is due to the biodiversity loss so the most appropriate for that is the habitat loss and fragmentation so when there is no habitat so then as good as biodiversity will is lost so therefore the correct option is habitat loss and fragmentation question number 126 so here this is an assertion and reasoning late wood has fewer xylary elements with narrow vessels late wood is autumn wood and hence the option is correct assertion is the statement is right and for this statement let's see is this right so because cambium is less active during autumn season so hence it has a fewer xylary elements so therefore both A and R are true and R is the correct explanation of A and option two is the correct answer so unequivocal proof that DNA is the genetic material was first proposed by Hashi and Mark Hatches so therefore option is three so frequency of recombination between gene based on the same chromosomes is a measure of the distance between genes to map so gene mapping who is the person who first developed this technique so it's by Thomas Morgan Hunt's student Alfred's Turtuent and therefore the option is four so let's go to the next question so the reaction center in ps2 has an absorption maximite so this is also one of the easiest question of today so that is 680 nanometer question number 130 so Fab AC differs from Solan AC and the Lily AC these three families is given in morphology of flowering plants so with respect to the statements pick out the characteristic specific to family Fab AC only Fab AC is nothing but legumino say papillon AC family but not found in Solan AC Solan AC has epipetalus stamen and there are only five and three so whereas in Fab AC it is in two bundles which means diadelphus and diathecus so it is diadelphus and diathecus option two is a correct answer so let's go to the next question so in tissue culture experiments leaf mesophil cells so leaf mesophil cells so please understand this so are put in the culture medium okay so they are put in the culture medium to form callus so callus is an undifferentiated mass of tissue so where the mesophil cells undergoed de-differentiation and they start developing many times to form an undifferentiated mass of tissue so hence the option de-differentiation is the right answer so which hormone promotes inter node ptole elongation in deep water eyes so this is directly from your ncrt where the it's ethylene okay so ethylene is the gaseous phyto hormones you have studied about this and it's directly from your ncrt let's go to the next question so during the purification process for recombination DNA technology so addition of chilled ethanol so you would have done this in your practicals also where you have spooled out the DNA fragments and hence this is for DNA and this is the practical based question for today so question number 134 so identify the pair of hetero sporous pyridophytes among the following so two names are given in your ncrt in plant kingdom under pyridophytes that is salaginella and salvinia so therefore the option three is the correct answer for this option three directly from your ncrt so let's go to the next axiom placentation is the characteristic of solanaceae please remember okay so hence we need to look for solanaceae but in your ncrt so apart from solanaceae so they have given about malvaceae so malvaceae is china rose and citraceae citraceae is lemon and therefore petunia is solanaceae so the option one china rose petunia and lemon are the correct options for this so here assertion and reasoning again a flower is defined as modified shoot of course yes so whereas in the shoot ethical meristem which changes into the floral primordia and develops into the flower so reason is inter node of the shoot get condensed to produce different floral appendages floral appendages floral voles calyx corolla and laterally to its successive nodes instead of leaves and hence we have the flower so assertion is for the statement assertion reason is the correct option so hence option both a and r are true and r is the correct explanation of a which is option two let's go to the next question that is 140 how many different proteins that the ribosome consists of it consists of 79 to 80 proteins that's what given in your ncrt so therefore here 79 to 80 range is not given so therefore let's choose the option 80 as the correct answer melonate melanoic acid inhibits the growth of pathogenic bacteria by inhibiting the activity of so which particular enzyme is inhibited by a melonate so we have come across this in respiration implants that is succinic dehydrogenase the main enzyme which is also involved in electron transport chain is inhibited because of melonate and hence therefore option two is the right answer so this is a matching question matching type question so let's see take a look at this so oxidative decarboxylation so where there is removal of hydrogen and removal of carbon dioxide takes place at the same time and glycolysis so you know about glycolysis and oxidative phosphorylation in the presence of oxygen phosphorylation takes place and tricarboxylic acid cycle TCA so which option so here we have citrate synthase pyruvate dehydrogenase electron transport system and EMP so glycolysis has EMP name also Emden-Meyrov-Parnas pathway so therefore let's match this so next oxidative phosphorylation is nothing but so electron transport chain so for this option the correct answer is option one so A2 oxidative decarboxylation takes place so pyruvate dehydrogenase in the presence of that and B4 so glycolysis has also Emden-Meyrov-Parnas pathway and C3 oxidative phosphorylation is nothing but electron transport system or electron transport chain and tricarboxylic acid citrate synthase is the enzyme that's involved so therefore option one is the correct answer so given below are two statements so this is about the Gauss's organisms and population population interactions here so Gauss's competitive exclusion principle state that two closely related species competing for the same resources cannot coexistence indefinitely and competitively inferior one will be eliminated Gauss is given this statement so that's a right statement so for this statement so what is about the another in general carnivores are more adversely affected by computation no herbivores are more adversely affected by computation because they wouldn't be having any other source whereas carnivores will have many sources of food so hence the option four is the correct answer statement one is correct statement two is false which of the following combination is required for chemiosmosis chemiosmosis is one of the important phenomenon given by Peter Michel so we have studied that about that in photosynthesis as well as in respiration in plants so it requires a membrane a proton pump more than that proton gradient should be formed and ATP synthase f0 and fn particles the coupling factors act as ATP synthase and therefore so all these are present in both in the inner membrane of mitochondria and the membranes of chloroplast so sorry thylakoid so therefore the option is three given below our two statement one is level so again this is an aversion and reasoning in gymnosperms pollen grains are released from the microsperangia and carried by air currents so they have winged pollen grains so therefore air currents so that is animophily is correct so reason air currents carry the pollen grains to the mouth of the archegonia where the meal gametes are discharged and pollen tube is not formed so here it is not formed pollen tube is formed so therefore this is wrong and this is correct so assertion is true but reasoning is false so hence that option is correct option four so coming to the question number 143 so the question is not there but which one is not incorrect so here the question is which of the following statement is incorrect so let's read the statement the amount of some toxic substances of industrial waste okay so increases in the organisms it's successive so which is called as biomagnification that's right so the microorganisms involved in biodegradation of organic matter in the sewage polluted water body consume a lot of oxygen which is called as biological oxygen demand that's right so algal bloom caused by excess or organic matter in water improve water quality it never improves the water quality and it's called as eutrophication and that's wrong statement and water higher synth grows eichornia abundantly neutrophic water bodies and leads to an imbalance in the ecosystem very correct terror of Bengal you have learned about it and this is also correct so therefore option three is incorrect and that should be your answer so going to the next one which of the following statements are correct about clan filter syndrome so clan filter syndrome which one is the right one let's take a look here so here turner syndrome and clan filter syndrome so very first land in down down syndrome down reported down syndrome so this option is wrong and so it's question 144 so here such an individual has overall masculine development of course gynecomastia you have learned that word there so that is right so and the affected individually star chater no not not right physical and psychomotor development is retarded not really and such individuals are always sterile and that's right so b and e are right and option four is the correct option correct answer okay so now identify the correct statement lenticels are the lens shapes opening yes so they are present permitting the exchange of gases lenticels are present in the stem of the plants and bark is a technical term that refers to all tissues exterior to vascular cambium yes exterior to vascular cambium you have bark bark refers to the peridum phillum phillogen philloderm are the three words you have learned about the periderm yes that's right and phillogen is a single layer no phillogen just now it's not single layer it is multiple layers and therefore abc are the correct options sorry so hard bark so this is also wrong so ac and d acd i'm sorry phillogen is a single layer that is also wrong i'm very sorry about this so it is option three that is a is right and d is right so bark formed in the season is called hard work that's wrong and bark is a technical term so it's not a technical term it's a non-technical term so just like that we use we are not using it in botany so it is used in a general english as bark so hence that is a not a right option so therefore it is a and d correct option three only a and d are correct options so question number 146 so it is a matching so here let's take a look here so quiescent say stage is nothing but inactive phase quiescent is an inactive phase mitotic phase is the equational phase okay so and g2 is where the proteins are synthesized and g1 is the phase where um so it takes so therefore the which here 146 the option 4 is the correct answer so that is a4 b1 c2 and d3 so that is interval between mitosis and initiation of dne so dne synthesis is not given here which is the s phase so option three is correct so let's go to the next question 147 so mutualism commensualism this is the organisms interaction question and here so option a is mutualism both are benefited and b so commensualism one is benefited another is not affected and c amensualism is neither of them so one is not harmed and another one is not benefited and four is parasitism one is benefited another is harmed so therefore option three is the correct answer coming to the next so again it's a matching type question so here we have option so let's see the answers so a cohesion so what is cohesion cohesion is the mutual attraction among water molecules adhesion so adhesion is the attraction towards the polar surfaces that is the trachea elements or the vessels so that's what is the answer and the surface tension is the more attraction of the liquid when the substances are in the liquid phase and guttation is the exudation of water from the hydrothodes water in the liquid form so therefore option two is the correct answer so main steps in the formation of recombinant DNA are given below arrange these steps in the correct so this is from the biotechnology chapter and this is one of the easiest question for today again so answer is so the first is cutting of so here yeah isolation of the DNA so then what you do is second insertion of that yes cutting of DNA at the specific location then inserting it to the DNA into the host cell that is through the plasmid and amplification of that gene so then getting it in multiple copies is the next one so therefore option two is the correct answer so the last question for today so that is all about the mineral nutrition so here we have so iron so you know that so this is the again uh ruling out if you don't know the answer also definitely you will be knowing all about the molybdenum so molybdenum you find in nitrate reductase and nitrogenase and that should be the answer so d is always two and only one option has the d2 so you can figure out the answer so four is the answer so a three so that is activation of catalase enzyme so in hydrogen peroxide formation so you would have learned that and the zinc is the synthesis of oxin boron is required for cell elongation and differentiation and therefore the option four is the correct option so thank you all of you here's my center academy on behalf of center academy i'm signing off thank you all of you so this is to share guys and i hope you've got the answers for the paper you attempted today i know you all have put in a lot a lot of effort since last three four years and today was the day of redemption so my best wishes to all of you we will be publishing the key separately in this link itself in the description maybe by tomorrow morning you had a long day so just relax even if you know some of the questions are wrong don't worry you check it again tomorrow and don't worry about the results now just for an announcement we are launching our neat long-term program from 25th of this month it's a residential program so god willing all of you succeed but just in case if anyone wants to take a re-attempt you can always come to us and we will try and help you as much as possible so with those words signing off and best wishes to all of you once again do well and may god give you the force to become great doctors in this life thanks god thanks again bye bye and good night to all of you