 Hello and welcome to the session. In this session we are going to discuss the following question and the question says that, find area of triangle where angle B is equal to 52 degrees, A is equal to 43 centimeters, C is equal to 54 centimeters. We know that the area K of any triangle A, B, C is one half the product of the length of two sides and the sign of the included angle that is if we have this triangle A, B, C with sides A, B and C opposite to the angles A, B and C respectively then area K is given by 1 by 2 into BC sign A which is equal to 1 by 2 into AB sign C which is equal to 1 by 2 into AC sign B. With this key idea we shall proceed to the solution. We are given a triangle ABC where angle B is equal to 52 degrees length of side BC which is denoted by A is equal to 43 centimeters and length of side AB which is denoted by C is equal to 54 centimeters. We have to find its area. Now C we are given A and C and the included angle B so we can use result of area of triangle that is K is equal to 1 by 2 into AC sign of angle B. Now if we put the values of AC and angle B we get 1 by 2 into 43 into 54 into sign of 52 degrees which is equal to 43 into 27 into sign of 52 degrees. Now this is further equal to 43 into 27 into now using calculator we find the value of sign of 52 degrees and that is 0.78 so this is equal to 43 into 27 that is 1,161 into 0.78 which is approximately equal to 905.58 so area of triangle is 905.58 square centimeters approximately which is the required answer. This completes our session. Hope you enjoyed this session.