 Hi and welcome to our session. Let us discuss the following question. The question says find the mean of the following frequency distribution. Now this is given to us and we have to find the mean of this frequency distribution. We begin with the solution. Now we will first make a table. The first two columns we have written the given information. Now we will find the midpoint of E's class interval which we denote by X i. Okay plus 30 divided by 2 is 20. 30 plus 50 divided by 2 is 40. 50 plus 70 divided by 2 is 60. 70 plus 90 divided by 2 is 80. 90 plus 110 divided by 2 is 1. Now we will find product of F i and X i. 90 into 20 is 1800. 20 into 40 is 800. 13 into 60 is 1800. 20 into 80 is 1600. 40 into 100 is 4000. This we get 200 and on adding all this we get 10,000. We know that mean that is X i is given by summation goes from 1 to L F divided by summation i goes from 1 to L F i and summation i goes from 1 to 5 if i is equal to 2 is equal to summation i goes from 1 to 5 if i X i divided by summation i goes from 1 to 5 if i and this is equal to 10,000 divided by summation i and take care.