 I mean welcome to the session, I am Ashur and I am going to help you with the following question that says solve the equation x square minus 2x plus 3 upon 2 is equal to 0. The standard form of a quadratic equation is ax square plus bx plus c is equal to 0 where a is not equal to 0 and so, solution of this quadratic equation is x is equal to minus p plus minus root over v square minus 4ac upon 2a. So, with the help of these two ideas, we are going to solve the given equation. So, this is the idea, this is the beginning of the solution and the given equation is x square minus 2x plus 3 upon 2 is equal to 0. Now, comparing it with the standard form of the quadratic equation we find here that a is equal to 1, b is equal to minus 2 and c is equal to 3 upon 2 and we are required to find its solution. So, let us first find the value of root over b square minus 4ac. So, b square minus 4ac on substituting the values of b, a and c is minus 2 whole square minus 4 into 1 into 3 upon 2 which is 4 equal to 4 minus canceling the common multiples we have minus 6 which is equal to minus 2 and since minus 1 is equal to iota square. So, this whole can be written as 2 iota square. Now, square root of b square minus 4ac will be root over 2 iota square which is equal to root over 2 iota and now in this kind of solution. So, x is minus b plus minus root over b square minus 4ac upon 2a. Now, b is minus 2, so minus of minus 2 plus minus root over b square c is root over 2 into iota upon 2 into a. So, 2 into 1 which can be written as 2 plus minus root over 2 iota upon 2 and now separating the real and imaginary parts we have 2 upon 2 plus minus root over 2 upon 2 iota canceling the common multiples we have 1 plus minus root over 2 upon 2 iota. That is unsolving the given equations and the answer is 1 plus minus root over 2 upon 2 iota. So, this completes the solution. Hope you enjoyed it. Take care and have a good day.