 Okay, so let's try this problem. It says follow the flow of electrons indicated by the curved arrows in the following reaction And write the products that result Okay, so does everybody have a? Solution that they feel comfortable with in this one, right? Yeah, you're good with that Okay, so I want you to look at what I do and see where your problems are lying. Okay, so What was your first question? Did you have a question about the arrows? Yeah, so that's I always say it's like inspector gadget if you remember that for like for me That was when I was growing up There's this cartoon inspector gadget where he would go grab Shoot his arm and grab something and pull it back. That's like an acid base reaction In fact, that's what's happening here is these electrons are like inspector gadget arm They're going and grabbing the hydrogen and pulling it back Okay, in fact, that's what you want to always think of the arrows as doing okay is that the butt of the arrow is at the like if you imagine that it's inspector gadget analogy where his hand starts at and The head of the arrow is where it's going to okay, and that arrow shows the bond that's being formed Okay, that's what the arrow is showing and this arrow you see what's happening here This arrow is showing from these electrons here in this bond They're going to in between these two atoms here, okay, and this one's showing Similar thing kind of to this one here where these electrons here are actually going to that oxygen atom there Okay, so if we see what's going on here, right? We should be From our analogy thinking we're forming a bond between there We're breaking a bond Between those two we're forming a bond in between those two and we're breaking a bond in between those Okay, so let's and then we got to also remember our formal charges, okay afterwards So what I prefer to do on all of these problems Is to put in my lone pairs if they're not there. Okay, so I put the lone pairs And that's just for my own electronic counting So what do we say we're making a bomb there? So we're gonna have Everything else just leave the same right so h2o we've made that there this oxygen had the Two lone pairs what happened this bond went in between there, right? You see that this bond that was in between here is now in between here So we have that Okay, and this bond that was in between the carbon and oxygen. What has it done? It's put its electrons to the So that's the answer So did you forget your formal charge there So that's oftentimes the problem, okay Yeah, so that's essentially it's you didn't put your formal charge The other thing is is it looks weird And I know they didn't have the two lone pairs of electrons, but the way we're used to it, right? That looks right, so that's why I was saying Put in all your electrons. It'll make it easier and from here You'll see because the reason you only have those two electrons is because you are only thinking these electrons here, right? And that doesn't help you with your accounting where you get count your valence of oxygen and then can figure out your formal charge That's why I would always say Put your electrons in and you'll be able to figure out your formal charge Yeah, you're pretty close. Yeah, but the formal charge will make the homework tell you it's wrong, you know Questions on this one. No, I think my problem is I thought you're supposed to put it all together. Yeah. No Okay, are we good can we kill it?