 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question here says solve each of the following equations. Fourth equation is minus x squared plus x minus 2 equal to 0. In this question we have to solve the equation minus x squared plus x minus 2 equal to 0. Now before starting the solution we see the key idea behind the question. Now solution to a quadratic equation A x squared plus B x plus C equal to 0 where A is not equal to 0 is given by x equal to minus B plus minus under the root B squared minus 4 AC divided by 2A. And that is equal to minus B plus minus under the root 4 AC minus B squared the whole divided by 2A Iota. Now we start with the solution to this question. The equation given to us is minus x squared plus x minus 2 equal to 0. If we compare this equation to the quadratic equation A x squared plus B x plus C equal to 0 we get A is equal to minus 1 B equal to 1 and C equal to minus 2. So we find B squared minus 4 AC by simply substituting the value of A, B and C that gives us 1 squared minus 4 multiplied by minus 1 multiplied by minus 2 and that comes out to be minus 7. Now from the key idea we have x equal to minus B plus minus under the root 4 AC minus B squared the whole divided by 2A Iota. Therefore we get x equal to minus 1 plus minus under the root minus 7 divided by 2 into minus 1. That is same as minus 1 plus minus root 7 Iota divided by minus 2. Therefore our solution to this question is minus 1 plus minus under root 7 Iota divided by minus 2. I hope you understood the question and enjoyed the session. Goodbye.