 Hi and welcome to the session. Let us proceed on with the question. It says, find the general solution for each of the following equations. Now here the equation which is given to us is cos 4x is equal to cos 2x. Let us proceed on. On taking cos 4x to the right hand side we have cos 2x minus cos 4x is equal to 0. Or 2 sin 2x plus 4x by 2 sin 4x minus 2x by 2 is equal to 0. Now here we have used the identity that is cos A minus cos B. Right proceeding on we have that or we can simplify it and write it down as 2 sin 6x by 2 sin 2x by 2 is equal to 0. And simplifying it further we have 2 sin 3x sin x is equal to 0. Right now we have 2 possibilities which can occur. One is if sin 3x is equal to 0 so that means 3x is equal to n pi that gives us the value of x as n pi by 3. Right and the other option says that sin x is equal to 0 which says that x is equal to n pi. So the answer comes out to be x is equal to n pi by 3 or n pi and where n belongs to the set of integers. So this is our required answer that is the general solution of the equation that was given to us. I hope you enjoyed the session. First of all start solving the equation that you have and when you reach a point that this equation cannot be factorized further then you proceed on with the general equations and the term that you have learned in your previous classes. Bye for now.