 Now, we can go to the fourth problem where we see that temperature has been given T is equal to 170 degree centigrade and H is equal to 2821.5. So, here we had P and entropy here we have T and H. Again the approach is remain the same here P was given now we got T. So, I will go to table number 1 and get the value of H F and H G and compare with given value of H and come to the answer. So, now we have understood many things just get the value of H F and H G and compare them with the value of H at temperature is equal to 170 degree centigrade. Can we see table number 1, but before that let us come to the calculations. So, question number 4 T is equal to 170 degree centigrade and H is equal to 2821.5 kilo joule per kg. We know that temperature is less than T critical. So, we are not in supercritical zone definitely. So, what we can do is go to table number 1 and at T is equal to 170 degree centigrade we can get the values of H F and H G. So, let us go to table number 1, locate T is equal to 170 degree centigrade and locate the values of H F and H G. So, this is table 1 saturation line base temperature let us go to T is equal to 170 degree centigrade. So, here we are at 170 degree centigrade and this is table number 1 and correspond to that let us locate the value of enthalpy H F and H G which are 719.08 and 2767.9 alright. So, this is the H F value and this is the H G value and let us then try to compare the given H with these two values. Let us come back to the calculations. So, we have got at T is equal to 170 degree centigrade H F is equal to 719.08 kilo joule per kg and H G is equal to 2767.9 kilo joule per kg the given H value is 2821.5 which is more than H G what does it mean? H G is nothing but saturated vapor line and you are beyond that it means that this region is super heated region super heated vapor zone that we are in alright. So, this is the answer I will write this answer in our table now. So, come to the fourth question T is equal to 170 degree centigrade H is equal to 2821.5 my answer is super heated vapor or super heated steam. Let us come to question of 5 where P is equal to 5 bar and V is equal to 0.0001 meter cube per kg. So, again you have got a one pressure or one temperature condition and other one is V that you have. What again would do? We will go for P is equal to 5 bar on table 2 let us get the value of V F and V G and see and compare where this V lies as compared to V F and V G. So, let us try to do this faster let us go to table number 2 directly and compare the value of V. So, we say that 5 bar is 0.5 MPa. So, we are at this point and corresponding to this point let us find out the value of V. So, these are our V F and V G alright V F is 0.0010925 while V G is 0.37481 and let us compare our V value with this V F and V G. So, let us come back to the calculation now. So, P is equal to 5 bar and V is equal to 0.0001 meter cube per kg as we went and saw for P is equal to 5 bar or at 0.5 MPa we had V F and V G and we had V F is equal to 0.00109 and we had V G is equal to 0.37481 both meter cube per kg meter cube per kg and what you can see now our V is less than V F alright. So, V is less than V F and therefore where would we lie if V is less than V F that means we are in sub cooled region alright we are the left side of the dome or left side of the L V line. So, therefore we are in sub cooled region I am sure that you are understood this let us go back and write in the table. So, our last case is P is equal to 5 bar V is equal to 0.0001 meter cube per kg we say that we are in sub cooled or compressed liquid region alright. So, this is the way we have solved we have solved 1, 2, 3, 4, 5 problems in the first two problems pressure and temperature were given to us and that is very simple depending on table 1 or table 2 whatever we can come to the answer we will go for table 1 or table 2 will come to the same conclusion while in other three problems we have got either pressure or temperatures and one other property was given to us. So, depending on the comparison of this value with S F and S G we can decide whether we are on L V line weight region in the inside the dome superheated region that is beyond S G value or beyond H G value and sub cooled region that means less than V F value or S F value or H F value accordingly we can classify different zones over here. Thank you very much.