 Hello and welcome to this session. In this session we discussed the following question which says find a unit vector in the direction of vector a equal to 3i cap minus 2j cap plus 6k cap. Now let's move on to the solution where given vector a equal to 3i cap minus 2j cap plus 6k cap. Now the unit vector in the direction of vector a is given by a cap is equal to 1 upon magnitude of vector a into vector a. Now we are given vector a is equal to this so we find out magnitude of vector a now this would be equal to square root of 3 square plus minus 2 square plus 6 square that is that is this is equal to square root of 9 plus 4 plus 36 which further is equal to square root of 49 thus we get magnitude of vector a is equal to 7 therefore we have that a cap is equal to 1 upon magnitude of vector a that is 7 into vector a that is 3i cap minus 2j cap plus 6k cap. So we get a cap is equal to 3 upon 7i cap minus 2 upon 7j cap plus 6 upon 7k cap. So this is the unit vector in the direction of vector a. Hence a final answer is the unit vector in the direction of vector a equal to 3i cap minus 2j cap plus 6k cap is a cap equal to 3 upon 7i cap minus 2 upon 7j cap plus 6 upon 7k cap. So this completes the session. Hope you have understood the solution for this question.