 Hello and welcome to the session. In this session we discuss the following question which says find the probabilities that a EPS selected at random will contain 53 Sundays. First of all let's see how do we find the probability for an event E probability of E is equal to number of outcomes favourable to the event E upon triple number of possible outcomes. This is the key idea to be used in this question. Now let's see the solution. So we have to find the probability that a EPS selected at random will contain 53 Sundays. First of all we have a fact that in a leap year there are 366 days. Now 366 days means 52 weeks, 2 days and we have to find the probability that this leap year will contain 53 Sundays. Now since we have 52 weeks in this leap year so this would mean that a leap year is 52 Sundays but we have to find the probability that it contains 53 Sundays. So of these 366 days we have covered 52 weeks that is 52 weeks contains 52 Sundays. Now we are left with these two days. Now the remaining two days can be Sunday and Monday, Monday and Tuesday or Tuesday and Wednesday, Wednesday and Thursday, Thursday and Friday or Friday and Saturday can also be Saturday and Sunday. So clearly you can see that there are seven elementary events associated with this experiment. So let's consider let A be the event that a leap year 53 Sundays. Now the event A that a leap year has 53 Sundays will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday. Thus we say event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday. Thus favorable number of elementary events is equal to 2. So out of these total seven elementary events two are the favorable elementary events. Thus the probability of the event A that is probability that the leap year has 53 Sundays is equal to favorable number of elementary events that is 2 upon the total number of elementary events which is 7. So probability of A is equal to 2 upon 7 or you can say the probability that a leap year selected at random will contain 53 Sundays is equal to 2 upon 7. So this is the final answer. This completes the session. Hope you have understood the solution of this question.