 Hello and welcome to the session. Let us solve the following question that says in exercise 1 to 8, find the equation of the line that satisfies the given conditions. Fifth one is intersecting the x-axis at a distance of 3 units to the left of the origin with slope minus 2. First, let us learn the equation of a line passing through a given point. Let the point be x1, y1 having slope m is given by y minus y1 is equal to m times of x minus x1. So with the help of this idea we are going to solve the above problem so this is our p-idea. So start with the solution and here we are given that the line intersects the x-axis at a distance of 3 units to the left of the origin. Therefore the given point is minus 3 comma 0 and also we are given this slope. Let us denote it by m so this is equal to minus 2. Now equation of a line is given by y minus y1 is equal to m times of x minus x1 and here the line passes through minus 3 comma 0. So this implies x1 is equal to minus 3 and y1 is equal to 0. Therefore the equation of the line is equal to y minus 0 is equal to minus 2 times of x minus of minus 3. So this gives y is equal to minus 2x minus 6 or plus y plus 6 is equal to 0. Thus equation of the line is equal to 2x plus y plus 6 is equal to 0. So this completes the session. Take care and have a good day.