 Hello and welcome to the session. My name is Mansi and I am going to help you with the following question. The question says the following data on the number of girls to the nearest 10 per thousand boys in different sections of Indian society is given below. We see that first column is for section and the second column is for number of girls per thousand boys. So in the section schedule cast we have 940 in the sections scheduled tribes 970 non-SEST 920 backward districts 950 non-backward districts 920 rural 930 urban 910. The first question is represent the information above by a bar graph. First of all we draw a graph here on the x-axis we take SEST non-SEST and so on which are the different sections and on the y-axis we have number of girls per thousand boys. So now we have to draw a bar graph here. So let us make the bar graph. So this is a bar graph. Now let us take the midpoints of these bars like this, this, this, this, this. Let us name them now. Let us be B, C, D, E, F, G, H. Now we join all these points. So this is the required graph. Now let us see the other question. The other question is in the classroom discuss what conclusions can be arrived at from the graph. So let us see the answer to the second part. We find that the number of girls the nearest per thousand boys are maximum in scheduled tribes whereas minimum in urban. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.