 Hi and welcome to the session. My name is Reshi and I am going to help you with the following question. Question is solve the following pair of linear equations by the substitution method. First equation is 0.2x plus 0.3y is equal to 1.3 and the other equation is 0.4x plus 0.5y is equal to 2.3. Let us start with the solution now. First of all we will rewrite the equations given in the question and name them as 1 and 2. Now from equation 1 we get x is equal to 1.3 minus 0.3y upon 0.2. Now we name this equation as 3. Now substituting the value of x from 3 into we get 0.4 multiplied by 1.3 minus 0.3y upon 0.2 plus 0.5y is equal to 2.3 which implies 2 multiplied by 1.3 minus 0.3y plus 0.5y is equal to 2.3 which further implies 2.6 minus 0.6y plus 0.5y is equal to 2.3. Now we get minus 0.1y is equal to minus 0.3 or we can say y is equal to minus 0.3 upon minus 0.1 which is equal to 3. So y is equal to 3. Now substituting this value of y in equation 3 we get x is equal to 1.3 minus 0.3 multiplied by 3 upon 0.2 which is further equal to x is equal to 1.3 minus 0.9 upon 0.2. This implies x is equal to 0.4 upon 0.2. So we get the value of x equal to 2 right. So our required solution is x is equal to 2 and y is equal to 3. Substituting x is equal to 2 and y is equal to 3 you can verify that both the equations 1 and 2 are satisfied. This completes the session. Hope you understood the session. Bye and take care.