 Hello and welcome to the session. Let's discuss the following question. It says, find the number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each color. To solve this question we should know the theory of combination which says that our objects from n objects can be selected in our ways. We should also know the fundamental principle of counting which says that event A occurs in m ways, m different ways and event B occurs in different ways then event A and B occur in m into n ways. So this knowledge will work as key idea. Let us now move on to the solution. We have to select 9 balls consisting of 3 balls of each color. Now the number of ways to select 3 red balls from 6 red balls is equal to the number of ways to select white balls from white balls is equal to 5C3. This is by the theory of combination. Again the number of ways to select blue balls, blue balls is equal to 5C3. Now the total number of ways to select blue balls is equal to 5C3 into 5C3. Again this is equal to 6C3 is given by 6 factorial upon 3 factorial into 3 factorial. 5C3 is given by 5 factorial upon 3 factorial into 2 factorial, 5 factorial upon 3 factorial into 2 factorial. Again solving this, 6 factorial can be written as 6 into 5 into 4 into 3 factorial upon 3 factorial 3 factorial can be written as 3 into 2 into 1 into 3 factorial into 5 factorial can be written as 5 into 4 into 3 factorial upon 3 factorial into 2 factorial 5 into 4 into 3 factorial upon 3 factorial into 2 factorial. Now 3 factorial gets cancelled with 3 factorial, 2, 2's are 4 and it is equal to 5 into 4 into 2 into 5 into 2 into 5. That is it is equal to 1000. Hence the total number of ways to select 9 balls of each color, 9 balls consisting of 3 balls of each color equal to 2000. And this is the required answer and this completes the question. Bye for now. Take care. Have a good day.