 Hi, I am Shashi and I am going to help you with the following questions. Question is, using elementary transformations, find the inverse of each of the matrices if it exists. The given matrix is 4534. Let us now start with the solution. First upon, let us assume A is equal to matrix 4534. Find the inverse of A by elementary row transformation method. We will write A is equal to IA. We can write matrix 4534 is equal to matrix 1001, multiplied by A. We will apply sequence of row operations simultaneously on the matrix A on left hand side and the matrix I that is identity matrix on the right hand side. Till we obtain identity matrix on the left hand side. Now, first of all, we will make this element equal to 0. So, we will apply on R1 row operation 1 upon 4 R1. So, we can write, applying R1 row operation 1 upon 4 R1. So, we get 1, 5 upon 4, 3, 4 is equal to 1 upon 4, 0, 0, 1, multiplied by A. Now, to make this element equal to 0, we will apply on R2 row operation R2 minus 3 R1. So, we can write, applying on R2 row operation R2 minus 3 R1. We get matrix 1, 5 upon 4, 0, 1 upon 4 is equal to matrix 1 upon 4, 0, minus 3 upon 4, 1, multiplied by A. Now, to make this element equal to 1, we will apply on R2 row operation 4 R2. So, we can write, applying on R2 row operation 4 R2. So, we get 1, 5 upon 4, 0, 1 is equal to matrix 1 upon 4, 0, minus 3, 4 multiplied by A. Now, to make this element equal to 0, we will apply on R1 row operation R1 minus 5 upon 4 R2. So, we can write applying on R1 row operation R1 minus 5 upon 4 R2. We get 1, 0, 0, 1 is equal to matrix 4 minus 5 minus 3, 4 multiplied by A. Also, we know I is equal to A inverse multiplied by A. Now, this matrix is an identity matrix of 2 into 2 order. Now, comparing these two expressions, clearly we can see A inverse is represented by the matrix 4 minus 5 minus 3, 4. So, our required inverse is represented by the matrix 4 minus 5 minus 3, 4. This completes the session. Hope you understood the session. Take care and goodbye.