 I think what will do now I think let us try to just work on the tutorial let us do the tutorial may be in 10 minutes or 15 minutes so the tutorial problem is displayed so any of the centers if you can give me I z or I y or maybe just try to first get the I x so again I will give a quick hint so it is a cone and then again we have to take a thin disc as an element so there will be a thin disc let us say at a distance x so thickness of the disc will be dx so just look at the lecture problem solve slides so can we do that way and remember the radius of the disc at a distance x that has to be a function of x as well so represent the r in terms of x in that in that disc yeah some of you are giving the correct answers I x I see here on the chart answer is correct 3 by 10 m a square so answer is 3 over 10 m a square how about the I y and I z any center first of all I y should be equals to I z that is one thing I think 1 2 2 4 yeah some of those centers are giving just take your time I think these are you know you know delivery to students specially how to look at these problems are going to be challenging yes I think I have the answer for now I y I z is also coming up so those are correct so the solution is displayed it will be also posted on the module you look at your video solution is there as I said the basis will be the basis is really to construct this see ultimately everything lies here how to construct this thin slab or thin disc okay and you we know already that what are the mass moment of inertia about 3 perpendicular axis so you see that r is represented by a multiplied by x over h right so that is the main basis and ultimately the answer I do not know if it will be clear but here you have the answer for I x 3 by 10 m a square similarly remember for when we are doing the I y right so I y prime we can calculate d I y prime and then we have to look at the parallel axis theorem to go to the y so the final answer as some of you are giving already that is the final answer 3 by 5 m 1 by 4 a square plus h square so let us move on to the next problem just a quick problem we are going to do so for this assembly we have to find out the mass moment of inertia about the y axis now that is the easiest part actually about the y axis when the body is rotating so what we will do we will try to quickly find out the y axis and then other 2 you know I will post the solution so please look at it okay so I just need the result for the y axis for the time being and the x and z axis we can do at as an homework exercise so there is a cut out here 20 mm radius that cut out is there and we have a cylinder here connected so I just need the answer for the first part that is y axis and then we can do the rest of it you know as an exercise later on so now let us look at the solution as such it is not a complicated problem at all see if you go by the solution the approach would be so it has to be discretized into 3 bodies as you see here 1 2 and 3 okay so 1 is that complete solid disk 2 is the cylinder and 3 is that cut out okay in the form of a let us say cylinder okay so ultimately we have the mass m1 m2 and m3 of these 3 bodies and then remember that the first one that means first body you can get it m r2 over 2 so that is very simple for the total body total solid body it is m r2 over 2 similarly all of these has actually m r2 over 2 about its own centroidal axis right all of these bodies about their own centroidal axis that is y axis mass moment of inertia about the y axis of individual centroid is always m r2 over 2 now for body number 2 and body number 3 we need to use the parallel axis theorem so ultimately that is done if you look at it carefully so the body number 1 is m r2 over 2 body 2 m r2 over 2 plus mass times d2 and body number 3 needs to be subtracted because this one is already considered as solid body 1 is considered as solid so ultimately final answer is 20.6 10 to the power minus 3 kg meter square okay.