 This is Shila Ratna Bansode from Walshchand Institute of Technology, Solapur. Today we are going to see the topic sections of solids and in that we will be looking into particularly cone. We will move further with the learning outcomes. Student will be able to draw the sectional view of cone. Now at this moment I suggest you to pause the video and recall how a cone looks or what is the structure of cone. Moving further with an example we have a cone its base is 65 mm diameter and axis 70 mm. It stands vertically with its base on HP. The section plane is perpendicular to VP and parallel to one of the end generators of the cone and passes at a distance of 20 mm from it. We have to draw the sectional plan and the true shape of the section. Now here we have a cone whose base diameter is 65 mm, axis height is 70 mm. It is mentioned that it stands vertically with its axis or its base on HP. So a cone is kept straight its axis is vertical and it is resting on its base in HP. Then we have a section plane which cuts the cone. The section plane is perpendicular to the vertical plane and is parallel to one of its generator end generator of the cone. As we know there are no specific edges for cone because it is solid of revolution hence no edges we have generators. So it is parallel to one of the end generator and it is 20 mm away from that. It is parallel and 20 mm away from the end generators, the cutting plane. Let us move further. This is our X-Y line. What we draw? We will start with the top view as we have the base diameter as 65 mm. We divide the circle into equal parts. It can be 8 or 12. We name each part as 128. I have divided the circle into 8 parts. Further I project all these points into front view. I project all these points into front view. I complete the front view and extend the generators. So axis height you can see is 70 mm and base diameter as 65 mm. So this is your first condition as per the question that a cone stands or stands vertical with its base on HV. Moving further we name the points and then we have a section plane. Here you can see this is an end generator and this is an end generator. Here specific end generator has not been mentioned. So the cutting plane can be taken parallel to any of the end generators. In this case I have taken it to this O21, this end generator. I have taken it parallel and 20 mm from it. This is my cutting plane being represented by a red line or red section plane. Now moving further we mark the points where the cutting plane cuts the generators. We don't have edges in cone so we consider generators. The first point we get it at the base as it is circular so we have two points. Point one and two. On this generator we have three and four back and front. This we have five and six and at this single point we have on this generator that is point seven. Whenever it cuts the generators we have marked those points. Now we project all the points in top view. We project all the points in top view like the point one and two is on the base. We project it point five and six point seven. Now only the point three and four are remaining. For that we project the point three and four on one of the generators as you can see on screen. We project it on one of the generators. As this cannot be plotted in top view so we need to do the construction we project it in one of the generators either this or this. Then we project it vertically downwards. We project it vertically downwards that is we have projected it on O5. So in top view also we have projected it on O5. Now we rotate these points. So this is the point three four after projection we rotate it back to its original generator that is O3 and O7. It is on O3 and O7. So we have rotated those points back to its original generators. So these are the new points. This is the section we join the points P1, P2, P4, P5, P7, P6 and P3. P6 is on generator four six. So we have obtained P6 and P5 on generator four and six seven on five and point one and two on the base. So this is your sectional view of the core. This part has been removed. This is the remaining portion that we have darkened. Now to draw the true shape in some videos we have seen that to draw the true shape we take a plane parallel to the cutting plane. Here we have seen we will see a different method where we draw a section plane parallel to XY itself. We mark the points P1, P2, P3, P4 and P7 on this new line which is parallel to XY line and then we project each and every point. We project P1 from this line and P1 from the top view P2 similar way. We project all the points P3, P4, P5, P6 and P7. We join these points. This is the true shape of the section. This is the true shape of the section when the cone is cut by the given condition. Let us consider another example. Here we have a cone whose base is 60 mm diameter and axis 85. It is lying on one of its generators in HP with the axis parallel to VP. It is cut by a section plane inclined at an angle of 35 degrees to HP and perpendicular to VP. It passes at a distance of 30 mm above the base along the axis so that the apex is retained. We have to retain the apex and then draw the section. Here we have a cylinder cone based diameter 60, axis 85. It is resting on one of its generators totally lying on one of its generators on HP and the axis is parallel to VP. Then we have a cutting plane inclined at an angle of 35 degrees to HP and perpendicular to VP. Now as inclined to HP seen in front view perpendicular to VP it is seen as a line view in the front view and it passes at a distance of 30 mm above the base. From the base we have to mark a point at 30 mm at an angle of 35 degrees we draw a line. Let us move for the solution. We start with the top view. We have the base diameter as 60 mm. We divide the circle into equal parts. Here I have divided it into 8 you can take as 8 or 12. We complete the top view and then the front view. We draw the generators then we go for the next step. It is said that it is lying on one of its generators. As mentioned in the previous example these are the end generators and it is totally lying on the end generator. So this is the second condition. For this we name the parts and then completes its top view. The new top view or the second top view. For this we project the points from front view and previous top view and complete the object. That is the core when it is resting on one of its generators. We consider the cutting plane it is 30 mm from the base inclined at 35 degrees to HP and perpendicular to VP. So wherever this section plane cuts the generators we mark those points. We project each and every point in the top view in this way and join the points together. Like we have point P5 on O5 we project it on O5, P1, P2, P3, P4 all the points on the respective generators and join all the points. So this is the sectional view. We dark the remaining points. Thank you.