 Hi and welcome to the session. I am Neha and today I am going to help you with the following question. The question says draw a rectangle with adjacent sides of lengths 5 cm and 4 cm. So let's see its solution. Let us draw the rough sketch of a rectangle and write all the measurements on it to visualize the figure. So here we have a rectangle. Let's name it as A, B, C, D. Here in question we are given that the adjacent sides are of lengths 5 cm and 4 cm. And we know that in a rectangle length is always greater than the width. So the length will be equal to 5 cm that is A, B equal to D, C equal to 5 cm. And the width will be equal to 4 cm so A, B equal to D, C equal to 4 cm. So we got the four lengths of the rectangle. Now we also know that all the angles of a rectangle are right angles. That means each is 90 degrees. Now we have the two angles that is angle A and angle B. Also we have the measure of length AB. So we will take AB as days and let us draw AB equal to 5 cm. Alright so here we have AB equal to 5 cm. Let us write steps of construction side by side. So our first step of construction is draw a line segment AB equal to 5 cm. Now we have angle A equal to 90 degrees. So let us draw an angle of 90 degrees at point A. So here we have drawn angle BAX equal to 90 degrees. So let's write our second step of construction that is make angle BAX equal to 90 degrees at point A. Let's go back to our rough figure 4 cm. So we will take AS centre and radius 4 cm and we will draw an arc to cut AH at point D. So draw the arc and mark the point as D. So let's write our third step of construction that is with AS centre of length 20 meters at point D. Now again we know that angle B is 90 degrees. So we will draw an angle of 90 degrees at point B. So here we have drawn angle ABY equal to 90 degrees. So let's write our next point of construction that is make angle ABY equal to 90 degrees at point B. Now BC is also 4 cm. So we will take BS centre and radius 4 cm and we will draw an arc to cut BY at point. So we got the arc and the point C of construction which will be same as third one that is with BS centre of length 4 cm BY at point C. So now we have located all the points that is A, B, C and D and now to get the required rectangle we just need to join DC. So let's join DC and thus we got the required rectangle ABCD. So our final that is sixth point of construction is join DC and hence ABCD is the required rectangle. So with this we finished this construction and the equation as well. I hope you must have enlisted the construction. So goodbye for today and take care.