 Hi and welcome to the session I'm Kanika and I'm going to help you to solve the following question. The question says express each of the complex number given in the exercises 1 to 10 in the form a plus iota b. Given complex number is 1 by 5 plus iota 2 by 5 minus 4 plus iota 5 by 2. Before solving this question we should understand how to find the difference of two complex numbers. Z1 is equal to a plus iota b and Z2 is equal to c plus iota d are any two complex numbers then the difference that is Z1 minus Z2 or we can say that addition of Z1 and minus Z2 equal to a minus c plus iota b minus t. This is the key idea in this question. Proceed on with our solution. Given complex number is 1 by 5 plus iota 2 by 5 minus 4 plus iota 5 by 2. Now we will apply the rule for difference of two complex number so we will take the real and imaginary path in separate brackets. So this is equal to 1 by 5 minus 4 plus iota 2 by 5 minus 5 by 2 and this is equal to 1 minus 20 upon 5 plus iota 4 minus 25 upon 10 and this is equal to minus 19 by 5 plus iota minus 21 by 10. Thus minus 19 by 5 minus 21 by 10 iota is the required solution. Here a is equal to minus 19 by 5 and b is equal to minus 21 by 10. So we have reduced the given complex number in the form a plus iota b. So this completes the session by ended here.