 Hello and how are you all today? The question says draw a circle of radius 4 centimeter draw any two of its cord construct the perpendicular bisector of these cords where do they meet? So let us first draw a circle of radius 4 centimeter. Now here this is a circle with center C and radius 4 centimeter. Now we need to draw two cords. Let this be one of the cords and let this be the other cord. Let us name it as A, B and D. Now we need to draw the perpendicular bisector of AB first and then BD. So taking A as the center and radius more than half of AB draw an arc above AB and below AB. Similarly taking B as the center and the same radius draw another arc to intersect the previous arc at point X and Y. Join these two points like this. Now taking B as the center and radius more than half of BD we need to draw an arc above BD and below BD and then taking D as the center and same radius we need to draw another arc intersecting the previous arcs at point let's say E and F. Then we have joined these two points to intersect at point C. They all are intersecting at point C. So where do they meet? We just need to answer that they meet at the center of the circle that is point C. So this completes the session. Hope you understood the concept well and enjoyed it too. Have a very nice day ahead.