 Hello and welcome to the session. In this session we discussed the following question which says in the given figure all steps are 0.5 meters high find the area of the shaded region. We know that area of a rectangle is equal to L into B where this L is the length of rectangle B is the breadth of rectangle. This is the key idea to be used in this question. Now we move on to the solution. Consider this figure we are given that AB is equal to 4.5 meters. Now that all steps are 0.5 meters high so in the figure we have that AD is equal to 0.5 meters then PF is equal to 0.5 meters QH is equal to 0.5 meters then BC is equal to 0.5 meters SE is equal to 0.5 meters and RG is equal to 0.5 meters. Also as you can see in the figure we are also given that DP is equal to 0.5 meters, FQ is equal to 0.5 meters, FC is equal to 0.5 meters and RE is equal to 0.5 meters. Now as you can see we have made these rectangles so area of the shaded region would be equal to area of the rectangle ABCD plus the area of the rectangle SPFE plus the area of the rectangle QRGH. Now area of the rectangle ABCD would be equal to AB into BC. Now AB is 4.5 meters into BC which is 0.5 meters so this is equal to 2.25 meters square is the area of ABCD. Next consider the area of SPFE this is equal to SP multiplied by PF. Now this SP would be equal to AB minus 0.5 into 2 that is we subtract these two sides from AB to get the length of SP. So this is equal to 4.5 minus 1 equal to 3.5 meters is SP. So this is equal to 3.5 meters into PS which is 0.5 meters and this is equal to 1.75 meters square. Next we find the area of QRGH this is equal to QR into RG. Now this QR would be equal to PS or SP minus 2 times 0.5 that is we subtract these two portions from the length of SP to get the length of QR so this is equal to 3.5 minus 1 which is equal to 2.5 meters so QR is equal to 2.5 meters. So this is equal to 2.5 meters multiplied by RG which is 0.5 meters and this is equal to 1.25 meters square. Now the area of the shaded region is equal to area of ABCD which is 2.25 meters square plus the area of SPFE which is 1.75 meters square plus the area of QRGH which is equal to 1.25 meters square and this is equal to 5.25 meters square. So area of the shaded region is equal to 5.25 meters square that is area of this region is 5.25 meters square. So 5.25 meters square is our final answer. This completes the session. Hope you have understood the solution for this question.