 And so in this question, in the hcf of smallest prime number and the smallest composite number. Now this question was asked in cbac 2018, cbac. This question was asked in cbac 2018 mathematics paper and it was off on mark. Now question says, find the hcf of smallest prime number and smallest composite number. So as we know, smallest prime number, smallest prime number is 2, right and smallest composite number. Obviously 1, 2, 3 are not composite number, the smallest composite number is smallest composite number, composite number is 4. What is composite number? Composite number is a number which has more than 2 factors, more than 2 factors, right? So if you see 4 has 3 factors namely 1, 2 and 4 itself. So there are 3 factors, so 4 is the least or smallest composite number. Now let us find the hcf using long division or Euclid division method, Euclid's method or we can also use long division method. So hence finding hcf of, hcf of 2 and 4, you already know hcf is 2 here, but we will demonstrate. So let us say 2 and we go by this division method. So hence 2 times 2 is 4, so you get 0, so hence this is my hcf, my hcf, okay? So hcf is, you can write hcf of 2.