 ச தந்பிப்பின்பதான்,கண்ட்பமருந்து மிக விலக்கைவிட திட்டிருங்கள், மாயுச்சியைcomp dairy ப своеРக்கிறாம், நான் influenced these halfs proudhewsு அதிகாதைத்து. அப்பாககாத முகத்தன் கதிபவாடும் அடிக்கும் கடம்பே ரைந்துக்காண்டு க வைத்துகிறார் என்று, மகிழ்ந்தி அதற்கரு, மகிழ்ந்தித்த, சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும் சரியாக இருக்கும வகும் 1005 கீர்ஷ்வணு. வகும் கீர்ஷ்வண்டார்கள் நினைckenதான் மறந்தாகம் இரவு மறந்தாகம் போல் freezing அது கண்ணிகளுக்குப் பீள்கள்யணர்டப்பட வீள்களBLEEPயாக இங்கு ஏன் போல்стройர்களம் ஒரு மீதட்டும் பெரும்apon சரிதாகங்கள்களுக்குப்புலிக் கொஞ்சம் small, then it will be meaningless, okay. இது திடா இயி இர்வு உடன்பல் поэтому உளுங்களுக்கு ஓதப்பட்லும் நிருப்பட்டத்தோமாக, கிச்சர்ந்த வாடகாரிற்க அழைத்தும் ஊதிவி கடவிாகப்பட்டு. உளித்துக்கொள்வது நீ ஒன்றாகக் காக்கலாத்தை முதலி சீர்ந்து மிக்னில் உள்னிருந்து感ிவு உன்குPression. ஆகினியில் அத்தின் நடித்தய is the temperature of an air parcel, detect the temperature of an air parcel is the temperature of an air parcel when all the வாடு வ tempted, as condensed such that الطைதிசார்சின் பிறதில் டைக்கில் ஆகினிற்குத் திட இருக்கிரும் . рез tim Question you missed some classes theா? ஏதுல் டைக்கில் டைக்கில் கிடர் சத்தாக வகு ஒல்லை of that is the equolent potential temperature is actually the potential விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்து விருந்த சேடரி நான் தீட்டியில் சந்திப்பத் பெரிப்புழுக்கு வாக பிரச்சையாக மீண்டும் பொறுப்பும்iserb lowered, உண்மையாத முகாரியார் கிற வானத்திற்கு candidates டித்தக்கத் தீட்டி மூர்மை விட்டுமோண்டிactivism விஷ dramற்றி நம்பி விortun்சைகள் முகமை விண funeral adore ஒது பிரசிக்கை நீன் வந்திவகிறது. யார் பழைத்து மன கணவை நственно எதிர்வாரும் ஆகின்றவடம் இருக்கிறது யார் அது வருந்திக்காரச் Bass சக்கும் பாலிரிங்மான சிகிஜாட்செல்ல வேண்டும், கதுனுகabadіт்டி ஒது மற்றிவித்தை தினீர்காகிவிட்டத கிறுப்புக்கொள்வதை முயின்கு அருகெல்லாம் சொன்று பார்லாது, விளைஐந்து அழகாயஜதான் எளிவாகச் செல்கத் தேரியாகச் செல்குன்து தொ rhoமை கித்துகொறுங்கள் மேல் சொல்கிறீர்கள். சரறு குணபீர்த் தீவில் ப பப்படை başka புறக்கமேல் அவருக்குப்பட்டத் மிக увидச்சும் savesUnit1-1х4 வகாடா பள்ளி செய்துதால் வந்தே எடுத்துக்கொள்ளார்கள்斐ப்பாட குறிசியில் ஒரு மபமுகி phys உகசும் செய்து பாடிா உண்மாக குறிசியில் ரவ்டு க proverb எல்லோகத் தீடு OFrechi குறிசியில் வகுகுமீர் குறிசி новых ஒளிாக மத gymnastics என்பதை செய்துகொள்ளார்கள் சரியமாக ஆடப்விற்குல Prayer சினிற்காமலர் நல்லம் செய்து அவையுப்owej நீங்கள் ராசியாகக்குள் பொரி்யன் நிச்சயம் அந்தும் முடிந்துகொஞ்சி எகளின் பூரிம் செய்தும Duncan ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹார்ஹா ஐயாலும் 100 ஆகுர் ventilator வெற்றின் வெட்டு இடுக்கில் ஒலுவங்கு வாழமியார். அனுதம் epidemi Vai ஐயாலும் இந்த சல்வு எண்ணாதே விளக்க நேரர் ஒன்று கு. ஓன்இம் பேச start ao. அனுகத்து நிலமை புர்த்து வெழுந்தீட்டு மு曾ன்னப்வது மு சந்தி வெற்இம். என்ன எங்கள் அனுதமு கொண்டி சொன்று கூறும். என்ன ஆண்டு be சரியgsகரி மன்னிடமுடைய ஆண்டுக் கடந்தாயர் தருக்கிக்கொண்டomatic, அல்லவு பல்ல மாட்டா வேண்டும், பாரமீடர் like let's say omega ask you to find r as ask you to a specific unit as you find d2 point temperature lc ltheta theta w whatever so you should have patience and do one by one why it is not very difficult but you have to be very meticulous and systematic okay and you have to use the right line after lcl if you again use theta is equal to constant you will go somewhere you will come back to the original point after the lcl you theta is equal to constant alright now I want to introduce one more quantity called mse any guesses what this could be is the moist static energy of air okay the msc can identify the three terms first term is it gives you an idea of the total energy available with the air the total energy of the air has got three components component one is please feel free enthalpy the component one is enthalpy the component two is geo potential which is a reflection of its height okay potential energy and the third is the energy contained in the form of latent heat so which is the dry part and which is the wet part first two are dry very good so this is dry static energy first two are dry parts right what did you say dry static energy now as z increases what happens assuming that all the process in the atmosphere or ad batting as z increases please tell me what happens to each of the three components t will cp into t will decrease what about the second part it increases for the dry if it is for dry air if it is dry air the third part will also decrease correct is it correct or I am making a mistake okay so the first two you are fine right no I made a mistake for dry air what about this it is not under consideration remains unchanged right now for moist air now tell me what happens to third term decreases correct okay however the sum of the three is a constant so in atmospheric processes you can consider involving moist air you can treat mse to be constant and work out problems with that if height is chosen as a coordinate height is chosen as a coordinate means phi is chosen as a coordinate are you getting the point so that is also possible நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் நான் ந செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும் செல்லும சத்தேனை அவளவி ஏற்பங்கத்திருப்பு என்கு ஏற்பை我也 சேர்த்தேன், எடிக்கவும் ஆக முறை சபருத்துваோ என்று தேர்மாக நல்மத்தில ஒரு பிடி Odyssey ஏற்பை விருந்தை முறை, நமர் முறை செய்தால், உணர்єம்OurP' சத்தேன் ரான் பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டிலான பிசாட்டில பார்சில் and the theta e-line that passes through twp and the theta e-line that passes through the twp and the omega s-line that passes through the tdp not tdp that passes through the tdp of the partial it is I am just stating the obvious okay. So, it is a three way interaction you can start from mid bulb temperature or you can start from dew point or you can start from this thing and everywhere it will all converge to LCL alright. So, now I will show you two presentations how to get the lifting condensation level okay on the skew-t lnp chart first locate the isotherms locate the isobars with the help of the isobar and isotherm you know the point A which is given by tp the two yellow lines will intersect and you will get the point A now point A whose coordinates are temperature and pressure fine now please look for the saturation mixing ratio lines omega is equal to constant and omega is equal to omega s apart from temperature and pressure we will give you one quantity for A let us assume that that is omega find out where omega is equal to omega s and have that yellow line. So, this is okay I will just go I cannot write this presentation okay omega is to omega s and identify that line what happens now where the original isobar cuts the omega is equal to omega s-line that is the td then look for the dry adiabat take the dry adiabat from A and located and then this dry adiabat this dry adiabat and this omega s which is cutting the isobar at td they will intersect that is the lifting condensation okay. So, how do we get the wet bulb temperature look for the isotherms look for the isobars intersection fix the point one more moisture parameter will be given look for the saturation mixing ratio find out where the saturation mixing ratio is equal to your omega which I have given 8 grams per kg to 12 grams per kg whatever fix the dew point look for the dry adiabat look for the one which is originating from A that is theta equal to constant and then look for this omega s-line which is shooting off from td get the lifting condensation level now look for the orange color line which are the saturation adiabats or theta e equivalent potential temperature constant that yellow line is fixed then that intersects this original isobar corresponding to A and td and you get the wet bulb temperature if you go down further assuming that at A the pressure is not 1000 hPa you will get the theta w is it okay please take down this problem problem number problem number 38 an air parcel at 1000 hPa an air parcel please take down the problem problem number 38 an air parcel at 1000 hPa has a temperature of 30 degree centigrade and air parcel at 1000 hPa has a temperature of 30 degree centigrade 30 and the mixing ratio 14 grams per kg what is the tw of air now I will not ask what is the lcl when I say now you are we are advanced now what is the tw of air means you have to get lcl isn't it okay what is the tw of air question mark problem continues the air parcel is lifted to the 700 hPa level the air parcel is then lifted no not then the air parcel is lifted to the 700 hPa level by passing over a mountain the air parcel is lifted to the 700 hPa level by passing over a mountain and 80% of the water vapor that is condensed out and 80% of the water vapor that is condensed out by the ascent A S C E N T that is with ascent or the lifting right so I come again the air parcel is lifted to the 700 hPa level by passing over a mountain and 80% 80% of the water vapor that is condensed out by the ascent is removed by precipitation is removed by precipitation determine the following quantities temperature potential temperature mixing ratio and the wet bulb potential temperature so determine temperature potential temperature mixing ratio and the wet bulb temperature of the air parcel after after it has descended down determine the temperature potential temperature mixing ratio and wet bulb potential temperature of the air parcel after it has descended down to the 1000 hPa level after it has descended down to the 1000 hPa level on the other side of the mountain you understand why it is getting lifted up some wind is there let's not get into that story so it is wind is bringing it and then it is rising and then it is raining on the mountain top then some moisture is removed wind is carrying it is going to the other side now the funda is you will get some surprising result what is the final temperature of the air which is hitting the city or the town which is on the other side of the mountain originally the air is at 30 degree centigrade you will get some surprising result okay so please start one by one like a typical quiz question okay once you have learnt moisture thermonet this will be the don't explain it ask a 15 mark question and what is the LCL okay alright so t equal to p equal to the first question was what is the wet bulb how much did you get I got 28 28 so we call that 0.1 a or whatever I am calling it as 1 so the relative humidity as 1 is 50% it is not required but I will find out whatever can be found out we will find out alright now dew point temperature dew point temperature is correct okay for the benefit of other people watching this we just show it a which is steeper the omega s or the isotherm okay so if I draw like this I am not making a mistake right okay I got this so this is my too much a which okay this is the point a 0.1 then I go all the way here this my TD fine dew point now keep this they are intersecting 850 alright so the LCL is 850 h bar we have not even answered the first part of the question right so we are still quite an involved problem now let us try and answer the first part of the question which is find the wet bulb temperature let us find the wet bulb temperature so I will use the green the theta E is equal to constant it cuts this somewhere it may correspond to Bangalore but the problem is it is not 1000 h point Bangalore the Bangalore is already at some height so you want to start with Bangalore you would start some 920 h bar 900 correct are you getting the point Bangalore is not at 1000 h bar because Bangalore is 900 meters above sea level no Chennai is at 1000 h bar but 30 degrees not Chennai that problem is there may be today maybe maybe it's 32 33 now okay so the wet bulb temperature is 22 out of 20 marks you've got six marks or seven marks already now the difficult part starts now it is further lifted it is further lifted to 700 h bar will it get lifted this is theta equal to constant so from here will it follow the green line or the pink line it will follow the green line I'll take the so now this is 850 h bar okay draw one more line 700 h bar okay for those people who are highly mathematically inclined with the scale 8 of 7.5 kilometer what is the height of the mountain that's 100 h bar just tell me 2 minutes use a hydrostatic equation tell me the height of the mountain assuming that 0 p0 equal to 0 right at 1000 h bar can you calculate or not you can write 2.67 is reasonable western guards is 2.00 ut is 2200 2300 meters on a mod 2695 so 2.7 kilometer is reasonable okay western guards height is about to so it has come up to 700 h bar so you must have this in mind so 700 h bar so the lifting condensation level will be able to one and a half kilometers right 1.2 to 1.5 because you guys are telling me this is 2.6 1000 is 0 1000 h bar is 0 700 h bar is 2.6 so I assume the date 50 will be around 1.2 1.5 so that cloud base height will be around 1.5 now from here you are taking it all the way up to 700 by using this so I am following this okay 1 now what should you do at 3 what is the temperature that you can easily find at 3 you have to find out isotherm t equal to it is very cold now the air parcel has become very cold I will just check my answer this is not asked this is not asked but anyway we will find okay this is not asked because I asked on the other side of the mountain but after it descends but anyway whatever you can calculate you calculate I know that you are proceeding on the right track now some difficulty now some difficulty arises because from its mixing ratio is how much its mixing ratio is always 14 grams per kg but now it has reached 700 h bar what is omega s so how much it has to shed as precipitation 4 but out of that 4 it is not shedding everything how much is it shedding 80% how much is that 3.2 grams so the remaining 0.8 will stay with this so what will be the omega what will be the omega of the air parcel when it starts descending after it has hit the 700 h bar will be the maximum it can take 10 grams per kilogram plus whatever it has not precipitated or I will come in some other route originally it had 14 at 700 h bar it is legally allowed to have only 10 the remaining must be must be thrown out that is 4 out of that 4 80% is actually precipitated that means 3.2 grams so out of 14 3.2 are thrown out so the 10.8 is remaining agreed so 10.8 grams per kg is remaining within the air parcel with that 10.8 grams per kilogram what will happen to that okay it is coming down it is coming down correct when it comes down which process will it follow saturation adiabat when it it will follow the saturation adiabat till it reaches a height at which omega s is 10.8 are you getting the point after that all the moisture would have been removed it will follow a dry adiabat all the way up to 1000 h bar is that clear you understand what I am saying vivic you are following what I am saying so some fundas are there this 10.8 funda you understood right from the 10.8 what it will happen it will again come down it will again come down to a pressure at which when it intersects the omega s will be 10.8 what is that height I think it is 720 720 730 whatever thereafter when it goes down it won't follow a saturated adiabat it will follow a dry adiabat correct then it will follow a dry adiabat all the way up to air 1000 h bar then if you see the temperature you'll get a startling result please do that 40 degree centigrade 38 or 36 or 38 so what's happened actually happening you get a cool you get cool air on one side of the mountain the air the wind takes it up it sheds it moisture on the other side you get hot winds this is called a chinook wind so it happens in the rockies in the us it also happens in the alps in the in europe okay some little bit should also happen in the leeward side of west end guards which will be some tamal nado i mean for example in what is the other side of the west end guards if you look at tamal nado maybe that sivakasi virdhinagar and this side of madurai and all that west of madurai other side you will have all kerala towns what is that this is all west end guards east end guards is our i am going to so when you cross kerala this side there is tamal nado right after the west end guards there is some portion that's why you have got the sivakasi and all these places where they do this fire crackers there are only five rainy days out of 360 days why are all the fire crackers factories situated in sivakasi 360 out of 360 way guaranteed no rain because they are on the leeward side of the fountain the west end guards protects them from rain but the other side it just rains like mad other side you know that the other side if you cross the west end guard it'll be so green that's a moon hour and all those places okay so what is the temperature you're getting um now i will write it i think only the next class will be able to is it become too complex now so this is 720 then from here now the parcel is going down at 700 hpa unfortunately it is super saturated correct this is the funda okay now the parcel is descending at 700 hpa it is super saturated first it descends along the theta equal to constant till omega equal to omega at that level this is what is that level 720 okay i don't want to rub that okay what is the theta theta t is 36 no what is theta 38 isn't theta potential 38 t final same so what did i ask determine the temperature potential temperature mixing ratio is 10.2 10.8 mixing ratio is 10.8 wet bulb potential temperature same 1000 hpa wet bulb potential temperature is the same as before correct wet bulb potential temperature does not change right yeah now just one minute i think some people want to go to the next class so i'll just quickly summarize the net effect of an ascent followed by a descent the net effect of an ascent followed by descent is as follows the net increase in the temperature and theta of the air parcel we've seen that decrease in omega rh tb and tw no change in theta e or theta w wet bulb potential temperature is the same potential temperature is the same but uh why are you so surprised net change in omega it started with 14 it has come down with 10.8 so it has decreased so relative humidity also has decreased moisture has decreased right the relative humidity has decreased you can check what will be the relative humidity at the final point it would have decreased okay then the tw would also have decreased okay but there is no change in the potential temperature or the wet bulb potential temperature so you get a very hot air on the leeward side this phenomenon is called chinook win i'll show you some pictures and some we'll get into the internet and look at chinook wins for 5 10 minutes and i'll solve this problem on this qt lawn p chart for the first 15 20 minutes then i'll solve one more problem involving all this wet bulb and all that before we start on with the new sub chapter in this where we look at the stability of an air parcel after it goes up we'll go further it'll be uncontrolled or it is convectively stable unstable neutrally stable and all that thank you very much