 Hello and welcome to this session. Let us understand the following problem today. Find the sum given below. We have 34 plus 32 plus 30 so on till plus 10. Now let us write the solution here. A is equal to 34, D is equal to 32 minus 34 which is equal to minus 2 and A n. That is the nth term is equal to 10. Now we know that A n is equal to A plus n minus 1 D. Now substituting the values in this we get A n is equal to 10 which is equal to A that is 34 plus n is unknown D is minus 2. So here we have to find the value of n. So we can write it implies 10 is equal to 34 minus 2 n plus 2 which implies 2 n is equal to 34 plus 2 minus 10 which implies 2 n is equal to 36 minus 10 which implies 2 n is equal to 26 which implies n is equal to 13. Now we will find the value of sum. So sum is equal to n by 2 multiplied by A plus A n. Now n we have taken out to be 13 so 13 by 2 A is 34 plus A n is our that the nth term is 10. Now solving this we get which is equal to 13 by 2 multiplied by 44. Now here we see that this gets cancelled by 22. So it is equal to 286. Hence required sum is 286. I hope you understood the problem. Bye and have a nice day.