 Hi, and welcome to this session. I'm Priyanka, and let us discuss the following question. Let's say find the value of other five sigma metric functions when the value of 4x is given to us as minus 1 by 2. And x lies in the third quadrant. So let's start with our solution. Since we are given the value of 4x, we can easily find the value of finite. Because we know that I squared x plus cos squared x will be equal to 1. Therefore, it will be equal to 1 minus cos squared x that is in the square root. So let us substitute the value. We have 1 minus minus of 1 by 2 the whole square. So do us 1 minus 1 by 4 that is equal to square root 3 by 4. That is root 3, 2. Since it's given to us that x lies in the third quadrant, that means sine x is negative. So we have the value of sine x as root 3 by 2. Further, we can find out the value of tan x how it could be finite by 4x. The value of sine x is minus root 3 by 2 divided by minus 1 by 2. On simplification, we have the value of tan x as root. We can easily find out the value of cos xx that will be 1 by 5x. And then it will be equal to this 2 by root 3. Whereas, x can be found out by 1 by cos x. That will be minus 2, as it will be 1 divided by minus 1 by 2. Which on simplification, will be minus 2 and 4x is 1 by tan x. 1 divided by the value of tan x will be 3. So the value of 4x is 1 by root 3. So these are the 5 values which were supposed to be found out in the question. That will be the value of sin x, tan x, perfect, weekend and perfect. And so this concludes the question that was given to us. I hope you enjoyed. Do remember your trigonometric functions quickly.