 Please drop a graph, velocity, let's say 5 meter per second, how it will look like? So if velocity is displacement, we have seen here right now, now if velocity is not constant then can I say area under the graph is the displacement? How can you prove it? What's the point? I am changing for that small time interval, very very small delta D it is, suppose it will know some changes there then of course from 5 meter per second it would be 5.0001 meter per second, so almost constant if time interval is very small, so displacement in this delta D is how much? Out here and if I add a displacement, I am adding small small displacements. So from here to here, time is D, find the area of this first point out and since the coefficient is constant, you can take A of D, it is constant. V minus U, UT plus half a T square, so this is a graph with constant acceleration. I think we have done this, we have done this, last class I have taken as negative. So if you want you can stay back, I will not say no to it, but then you can leave also. See, let's start this problem practice session. Here is the first question, I am just taking some additional questions. And I will give you sufficient time so that you can solve each one of them yourself and I will give you hints also. So it will not be like I tell you the questions and then I will stand aside. Here is the first question. The curve accelerates from rest at a percent rate. To come to rest, first one is maximum velocity, how much distance to have it. In terms of that, try solving, stop increasing. Second is divided into two parts, in terms of constant acceleration. So it is the final velocity of alpha equal to the initial velocity of beta. Alpha beta t square divided by 2 alpha beta. 2 alpha t square. Yes, correct. Alpha beta t square divided by 2. Yes. Okay the third is. Alpha t square divided by 3 means 3 times t minus z divided by 2. 2 times t minus z divided by 2. Now you are 3 times of T, so here 3 times t minus z divided by 2. 3 times t minus z divided by 2. Okay shall I repeat constant acceleration beta. So alpha t or these two equations you can get just solved in simultaneous equation. That's it for this video, thank you very much!