 Hello and welcome to this session. In this session we will discuss the question which says that find the area of triangle having vertices minus 4, 3, 3, 1 and minus 3, minus 2 using determinants. Now before starting the solution of this question we should know a result and that is if a triangle has vertices given by audit pairs A, B, C, D and E then area of triangle is equal to 1 by 2 into determinant with elements in first row as A, B, 1 elements in second row as C, D, 1 and elements in third row as E, F, 1. Now this result will work out as a key idea for solving our given question. Now let us start with the solution of the given question having vertices minus 4, 3, 3, 1 and minus 2 using determinants. Now from the key idea we know how to find area of triangle using determinants. Now where vertices of triangle are given as minus 4, 3 then audit pair 3, 1 and audit pair minus 3, minus 2. So determinant B and 1 that is minus 4 then elements in second row as D, 3, 1 and 1 and 1 that is minus 2, minus 2 and 1. Now expanding area of triangle into 1 into 1 into 1 the whole minus 3 into 3 into 1 the whole is equal to 1 by 2 into 1. Now 1 into 1 is 1 minus 2 into 1 the whole minus 3 into 3 into 1 is 3 minus of minus 2 into 1 is plus 2 the whole 2 is minus 6 minus the whole and this complete whole and this is equal to 1 by 2 into minus 3 into 3 plus 2 plus 1 into minus 6 plus 2 is minus 4 the whole minus 4 into 3 is minus 12 minus 3 into 5 is minus 15 and 1 into the whole 1 by 2 into now minus 12 minus 15 minus 4 is equal to minus 31 the whole. Now 2 into now area of determinant of triangle 10.5 solution of the given question and that's all for this session hope you all have enjoyed this session.