 Hello and welcome to the session. Let us discuss the following problem today. Solve the following pair of linear equation by reducing them to a pair of linear equation given to us 10 by x plus y plus 2 by x minus y is equal to 4 and 15 by x plus y minus y by x minus y is equal to minus 2. Now let us write the solution. The given equation can be written as plus y plus 2 into x minus y is equal to 4 minus 5 into 1 by x minus y is equal to minus 2, equal to q. So we get equal to minus 2. Now let us name this equation as 1 and 2. Now solving 1 and 2 we get first to form equation 1 by equation 3, q is equal to 20. So we get which implies 10 plus 10 q is equal to 20 which implies 10 q is equal to 20 minus 10 which implies 10 q is equal to 10 which implies q is equal to 1. Therefore, equal to 1 by 5 and q is equal to 1. x plus y is equal to p and 1 by x minus y is equal to q therefore we get x plus y is equal to p and 1 by x minus y is equal to q which implies 1 by x plus y is equal to 1 by 5 and this implies 1 by x minus y is equal to 1 plus y is equal to 5 and this implies x minus y is equal to 1 equal to 5 and x minus y is equal to 1 exists 2x which is equal to 5 plus 1 which x is equal to 6. Therefore x is equal to 3. Now substituting equation 5 we get plus y is equal to 5. Understood the problem. Bye and have a nice day.