 So, let's do this mechanism here. So, here you see we have a terminal alkyne, specifically one hexine, and we're going to do a two-step process to it. First, we're going to add sodium amide and ammonia, and then after that intermediate form, we're going to add bromobuting to our solution. So, why don't we draw the mechanism? Do you want to draw the mechanism, or just show the problem? Okay, cool. Let's do it. First step of the mechanism is going to be reacting this terminal alkyne. So remember, terminal alkynes oftentimes are very reactive on that terminal proton there, and especially if you've got a strong base, like the amide anode, so I'm going to put its long pairs on there. It's got a negative charge. Notice I didn't put the sodium atom in that mechanistic step. Why? Because it's a spectator on it. It isn't going to participate in this part of the reaction, or any of the reaction. So what's going to happen? What kind of reaction is this going to be? Yeah, an acid-base reaction, right? Does everybody agree with that? Or a Bronsted acid-base? Yeah, that would work too. We're going to depredinate like that. We've got to have a second arrow. Is everybody okay with doing that? So notice, our solvent for this reaction was ammonia. Look what we're making here. Ammonia. So that's why it's a pretty good solvent for this particular reaction. So we have that negative charge there now. We have that. And if you want to, you can say we've made ammonia, which is the solvent. So that's the intermediate. That's the end of the first step. That's the product of the first step, the intermediate of the two steps. This is an anion, which is a good nucleophile. Yeah, very good. So what are we going to add to this? We haven't done the second step yet. We haven't put it in there, right? So we're going to add a good electrophile to this. So some things that are good electrophiles would be like a primary alkyl pylite. So that's what we're going to add to this one. It was bromobutane. Two, three, four. So if you want to, you've got to remember that this has got to attack from the backside. Okay? So it's backside attack. This is an SN2 reaction. Okay? It's not an addition at all. It's a substitution. So you guys see the backside attack? It's an attack from the backside of the bromobutane. You're recorded. One, two, three, four, five, six. So that's our new product. So that is what we went from a terminal alkyl to an internal alkyl by doing these two steps. Okay? Are there any questions on this one? Questions? This must be a backside attack. It has to be a backside attack. Yeah. This has to be a backside attack, because this is an SN2 reaction. And those have to be. Okay? Because that's where the anti-bombing all goes. Does it matter which way the cartons go? Like how the wing is kind of pointing up and this wing is pointing down. Now it doesn't matter at all. It's just confirmation of license. Like if I were to want to twist this one down to looking like that, it's totally cool. Okay? The one thing about this you want to remember is that this is 180 degree bond angle. So you want to kind of keep that in a straight line. Any other questions before we kill it? Question? Step. Okay.