 Hi and welcome to the session. I am Deepika here. Let's discuss the question. If q01 is equidistant from p5-c and r, x6 find the values of x, also find the distances qr and pr. So let's start the solution to the question. q is equidistant from p and r. This implies distance qp is equal to distance qr. This implies on-squaring qp-square is equal to qr-square. So this implies now qp is 5-0-square on-square. This is equal to qr-square that is x-0-square plus 6 minus 1-square. So this implies 25-16 is equal to x-square plus 25. So this implies equal to 16 or equal to plus minus 4. That is plus 4 and minus 4. We have to find distance qr as well as distance pr. So if the coordinate, then distance qr is equal to minus 0-square plus 6 minus 1-square. This is equal to 16 plus 25 which is equal to root 41. And distance pr is equal to 5-square p-square which is equal to under root of 1 plus 81 which is equal to under root 82. Now if x is equal to minus 4 then equal to minus 0-square 1-square which is equal to 16 plus 25 that is equal to root 41. And distance pr is equal to minus 5-square plus 6 plus 3-square. This is equal to 81 plus 81. This is equal to the values of x41 if x is equal to 4 and x is equal to minus 4. In both the cases, distance qr is equal to 41 and distance pr is equal to equal to plus 4 and it is 9 root 2 is equal to minus 4. So this is the answer for the above question. I hope the question is clear to you. Why