 Hi and welcome to the session, I am Shashi and I am going to help you with the following question. Question is, find the second order derivatives of the functions. The given function is x square plus 3x plus 2. Let us start the solution now. First of all let us assume y is equal to the given function that is x square plus 3x plus 2. Now differentiating both sides with respect to x we get dy upon dx is equal to 2x plus 3. Now again differentiating both sides with respect to x we get d square y upon dx square is equal to 2. Finally we can see d square y upon dx square is the second order derivative of y. So the required second order derivative is equal to 2. This is our required answer this completes the session hope you understood the session take care and goodbye.