 Okay, so let's try, let's try this problem. So we'll just draw the fluid structure of xenon diachloride, okay? So how do we do this? First thing we want to do is, well, figure out which one of these atoms is going to be the central atom, which one do you think? Right, why? Just period three, pardon me, below, right? So fluorine is not period three, so it's got to be one of the peripheral atoms. So the first thing we're going to do is draw the fluid structure of the particular atoms. So hopefully you guys see we need one electron to bond to fluorine here, and one electron to bond to fluorine here, okay? So let's rearrange our lone pairs around here. I know this is the normal distribution but let's rearrange them to where we only have one here and one here, like it's expanded its valence, okay? I'm going to erase, I'm going to put one lone pair there, one lone pair there. So remember, xenon has to have eight, right? So I'm going to put one there and one there, like they move to different orbitals, okay? So now what happens? We do our fish hooks there and we do our fish hooks there. Is everybody okay with what I've done so far? Wonderful. So, and remember, we're just doing the Lewis structure here. I know you guys know about Vesper, but so that would be the Lewis structure of this molecule. So notice that xenon has expanded its valence, two, four, six, eight, ten, right? Electrons around xenon, okay? So that's bigger than eight so it's expanded its valence, okay? So that's the Lewis structure. If you wanted to confirm the formal charges of these things, right? We could do that. So the formal charge of xenon is going to be what, eight minus one-half of what the bonding electron, so two, four, right? Minus the non-bonding electrons, two, four, six, right? So we're going to get eight minus, the four divided by two is two, minus six, so eight minus two minus six is eight minus eight or zero, okay? So the formal charge of xenon is zero, and hopefully you guys could just tell that fluorine one has only one bond, its formal charge is zero, okay? Are there any questions on that one? Do you like that? Do you guys want to do anything else with this one? Any questions? Okay, wonderful. So that's a nice expanded valence on that one.