 Hello and welcome to this session. In this session we will discuss a question which says that final equation or equations of the plane or planes A part parallel to x axis such that the y-intercept is equal to minus 4 and the z-intercept is equal to 3 v part parallel to the plane 6 x minus 9 y plus 8 u z plus 20 is equal to 0 units from the origin. Now before starting the solution of this question we should know some results. First is the equation of a plane which cuts off intercepts a, b and c respectively y and z is given as over b plus z over c is equal to 1. Secondly the equation plus b y plus c z plus t is equal to 0 is given as a x plus b y plus c z plus k is equal to 0 where k is any arbitrary constant. The perpendicular on the point p whose coordinates are x1, y1, z1 plus b y plus c z plus d is equal to 0 is given plus b y1 plus c z1 plus d over 1 plus b square plus c. Now these results will work out as a key idea for solving out this question. And now we will start with the solution. Now we will start with the a part in which we have to find the equation of the plane parallel to x axis such that y intercept is equal to minus 4 is equal to so given the plane to x axis is equal to minus 4 and z intercept is equal to 3. Does not contain the idea that is equation of the plane in the intercept form where the required equation over a material this equation will not contain x term as the plane is parallel to y over b that is the y intercept and y intercept here is minus 4 z over c that is 3 is equal to 1 which parallel plus and 12 is equal to 1 which parallel plus 4 z is equal to r equation of the plane equal to minus 4 and z intercept is equal to and the b part we have to find the equation are equations of the planes this result which is given in the key idea and the b part the equation 8 y plus 18 z plus 20 is equal to 0 which is given as 8 y plus 18 z is equal to 0 where k is any arbitrary constant like this the equation number 1 also given that the plane which is given by equation number 1 is whose coordinates are 0 0 the equation of the plane which is given by equation number 1 is given as key idea we have that is 6 into 0 into 0 that is minus 8 square plus c is equal to now this implies mod of k is equal to 4 which further implies minus 8 y plus 18 z plus 18 square is equal to 8 y plus 18 z is equal to 0 required equations of the planes stop the given equation and that's all for this session thank you for watching