 Now we know that for a triangle ABC according to the Pythagoras theorem, AC square is equal to AB square plus BC square that is hypotenuse square is equal to some of the squares of other two sides that is AC square is equal to AB square plus BC square so this is a Pythagoras hypothesis that is BC upon AC? And this into angle apartments then the C and AC that is BC upon AC and that is BC upon AC and A, we want to solve the quotient . , so let's start the solution we have given a triangle PQR, Right angle at Q is equal to 5 centimetre q r is equal to 25 centimeter and is equal to 5 centimeter. Therefore, equal to 25 centimeter minus q r to the Pythagoras theorem q r square. So, 25 minus q r whole square is equal to 625. So, we have 625 is equal to 25 centimeter minus 12 centimeter is equal to because Pythagoras 25 centimeter minus q r and q r is our 12 centimeter. Therefore, Pythagoras is equal to 13 centimeter centimeter and this is q r is our 12 centimeter. We want to find the values of is equal to centimeter upon 31 p cube that is 5 centimeter. Answer for the above question is sin p is equal to 12 over 13 is equal to 5 over 13 is equal to 12 over 5. So, this is the answer for the above question. I hope the solution is clear to you. Bye and take care.