 addition of nitrosil chloride, addition of nitrosil chloride and OCL. It gives NO plus, NO plus and Cl minus. So the reaction of alkene with NOCl, Cl, Ni, T, R, T, R, O, S, Y, L, nitrosil chloride. So which one is weaker, NaIO4 or KiO4? Wicker in the same body. See NaIO4 and KiO4 gives Na plus and IO4 minus, K plus and IO4 minus. So Na plus, K plus, which one has bigger size? K, bigger, bigger size. So K will stabilize this mode. That's why this one is better. Okay. So what is the reaction of the nitrosil chloride? It is a reaction of nitrosil chloride, the product we write down, the product bonds here is hello nitroso derivative. It is nitroso chloride compound. Hello, it is plodonitroso compound. The general compound is plodonitroso compound. One important thing here is what, where we are going to discuss this is there in alkyl halide and aldehyde plodon chapter. If there is any hydrogen present here, then the reaction, then this is not the major reaction. Okay. But this converts into what? CCl double bond NaOH. CCl double bond NaOH. What is the name of this compound? This is oxene. C double bond NaOH is oxene. Can you tell me how this product forms? This one, this one. Second column is 3-4. 1, 2, 3, 4? Yes. This one? Yes. I have, it can be anything, hydrogen or any alkyl. It's just a C double bond series. One example I have taken, if it is hydrogen, then what happens? It can be anything, hydrogen or alkyl. What happens? Whatever is here, that will be here. If it is R, H and R, then here also it is R and H. But if it is hydrogen here, not alkyl, then this further converts into this. Why this conversion is there? And how this conversion is possible? Can you tell me? What is that? It is nitroso-oxene-totamyrism, right? Try it. H comes over here and this bond, double bond comes over here. C double bond and oxene formations. Very important. This oxene is, we will see the reaction in another chapter, but oxene formation is very important. So is this a subject which side? No, no, no. It's just a syn addition. It's very simple, like if I, if I want a carbon, I have R, I have H, R. In that case, we'll get a positive charge in the carbon, which is R, R. More stable positive charge. So we do which one is positive? In this case, if this case looks anything is possible, both are stable. So if you write here or here, both give the same answer. No, no, sir. Which one is positive? N-O plus and C-M-N. It is nitroso-nium ion, N-O plus. And this is chloride ion, C-M-N. Okay, make sure I don't. Try it in space. It is tried. See, keto-inol is very common one, but it is tried only. Possible with nitroso-noxene. Like keto-inol we have, so nitroso-oxene is very common. Try it. Okay, next slide down. Sir, what do you mean I have... I have discussed it, right? So it is one, two and three. So hydrogen from the third atom, it goes on to the first atom. And double bond from between the first and second atoms, it shifts between the second and the next. One, two, three. So even this thing is a try. This one is a try. This one is one, two and three. One, two and three. Okay, next slide. We'll finish this LP. Two, three more reactions, that is enough. See, it is two comma four addition reactions. I'll just give you the example, there's no theory of that. Two comma four means one molecule has carbon, two carbon atoms, C-H2 double bond C-H2. And when this is allowed to react with C-H2 double bond C-H, single bond C-H double bond C-H2. So two four addition, it is. Two four addition, four carbon, two carbon. Here you see what happens. It is a conjugated system. Right, conjugated system. So this converts into what if you write down the alternating structure, you get C-H2. C-H double bond C-H, single bond C-H2, negative and positive. Okay, now this negative charge, if I write down this molecule here, C-H2 double bond C-H2. So when these two molecules come closer for the reaction, so these charge separations polarize this pi bond also, the weak pi bond. So what you can write this negative charge, attack onto this carbon atom, this comes over here and this attacks on this carbon atom. And what you will get, you will get a cyclic structure here. And if you see the structure, the structure is this, isn't it? So what's a... C-H2 double bond C-H2 double bond C-H2 double bond C-H2. Dad, this is the first one. This is like... So we will look all of the first product when there are two double bonds, will all of it convert into the next region and become the cyclic compound? Only one molecule. Yeah, but like. Yeah, it will convert into something. Okay, what happens here, this comes over here and this comes over here, right? This bond will break pi bond, so 4 plus 2 will have a 6 member ring, this side we have double bond, C O O H and C O O H, this is like our possibility, correct? Now one more thing important here, this when you heat this compound, we haven't done this, but when you heat this compound, then this eliminates water molecule and forms anhydride, so the structure is the structure we get. How do you know it's H2? Actually, it loses only one H2. See actually, one thing you remember, we will discuss this reaction in one chapter called heating effect of compounds, okay, compounds when you heat this, then what is the product possible? There is nothing in chapter like this, heating effect, okay, but we will discuss that, heating effect, separately we will see that. But what happens, suppose if you have a compound like C O O H, C H2, when you heat this compound, then what is the product we get? Okay, so if N value is 0 or 1, okay, N value is 0 or 1, then on heating this, you will get what molecular element is, CO2 molecules goes out into this, okay, for example, suppose this is the reaction, oxalic acid, okay, oxalic acid works, you heat, N value is 0, yes, right, so if you heat then CO2 molecules goes out and the product is H CO O H, means one of the CO2 you remove from it, H C H2, so we have to remember that, okay, cartozoic acid's heating effect is this, so if you have CO O H, C H2 O H also, then also the product you got, C H3 CO O H, can you tell me, this product is what, CO O H, C H2, CO O H, on heating this, this CO2 goes out, H comes over here, C H3, CO O H, okay, Jane and I have asked many questions, many, like, a lot of questions on this particular, you'll get some cartozoic acid in between somewhere and then the last, we'll heat this, okay, so CO2 goes out when N is 0 over 1, okay, you won't get all these things in any book, okay, that's why I always say, I don't know what's next, okay, this is what we're going to talk about, we'll just talk about this, I said no, heating effects will do separately, right, now N is, N is 2 and 3, number of this molecule is 2 or 3, then H2O molecules goes out, okay, only H2O molecules goes out, if N is 4 and 5, both CO2 and H2O both, okay, so in this one you see, between these two COO H, you have two carbon at the present, right, two carbon at the present, what happens? And values, what? Values 2, right, so H2O goes out, so this H and this C H2, right, you have just C H2O, top 2 alkyl group, means we have two alkyl group in between them, see this structure is C double bond O O H and this is C double bond O O H, we can just say that when you heat this, you see, see any one of this lone pair, this attacks onto this carbon atom because it is polarizing, carbon, oxygen, electronegativity, this part is positive, so what happens with this, carbon O minus O H, C double bond O O H. Now this H plus comes out to stabilize this oxygen atom and this H plus is taken up by this also, okay, this H plus makes this group as a good leaving group. So what happens here, double bond CO minus oxygen C double bond O and here we get O H2 plus now what happens, this lone pair of electron comes over here and this bond there and you heat it and hit right, C double bond O, only one bottom one, however you won't get this reaction in this chapter, okay, next write down, write down. This molecule intermediate one is osomite formation of osomite first and then it is easier with zinc dust, ZN2 goes out and you will get this product. The product of this reaction can be an anti-height, anti-height or ketone, both anti-height actually do, depending upon the structure of health, all three products possible. Write down the product in the reaction. So if you have like this, if you have like this, so when you do the other analysis of this, you will get many compounds into this one. It will be C, H, double bond O, double bond O, three molecules of O. What? We will get NCS-O, NCS-V. Let me think. On other analysis, these two products forms, okay. You write down the structure of the alkene which gives this product and how many such structures possible? How many, only one is such a possible? But the one such like God is a right. That one is like another one. So the other one, the third one. How to draw this structure now? See, I know just double bonds. Why you have drawn this beautiful structure? So because of that, I am looking into it. See, actually what happens, the product of this is what? You just have to create this bond and write down the double bond O with these two carbon. What happens? Okay, you see how do we write down the product? For this one you see, we have this CS3 double bond O2C double bond CH2, right. The overall analysis product of this is what? You just have to remove this double bond and double bond O here and double bond O here. This is what we are getting there. Right. So if this is given, you have to write down the original structure of alkene. What we will do? We will remove this oxygen atom. You just have to remove this O and O and attach this carbon and this carbon to the double bond. Right. So you see, this is the new molecule. Right. This too. Right. So the alkene, the structure of alkene is what? This is the structure of alkene. Right. Which bond overall analysis gives this two product. Okay. Now this is the structure of alkene and across this double bond, GIE is possible. Right. Yeah, pal. Yeah, pal. So we can have C praise ... 2 ... But this is the most stable ... 1 by L family. What is this? What is this? Replication Write down First one Fighting micro elimination Of What? Yes sir You didn't ask the right question