 Hi, I am Kanika and I am going to help you to solve the following question. The question says which term of the following sequence is B part is root 3, 3, 3, root 3 is 729. Let's now begin with the solution. Given GP is root 3, 3, 3, root 3 and so on. Let nth term of the given GP is 729. Now in the given GP, first term that is A is equal to root 3 and common ratio that is R is also equal to root 3. We know that we can obtain R by dividing any term by its preceding term or dividing 3 by root 3 we get root 3 and on dividing 3 root 3 by 3 again we get root 3. So R is equal to root 3. We know that general term of a geometric migration is given by Tn is equal to A into R to the power n minus 5. Now here we have assumed that nth term of the given GP is 729 that means Tn is equal to 729. Now Tn is equal to A into R to the power n minus 1. So A into R to the power n minus 1 is equal to 729. Now A is equal to root 3 and R is also equal to root 3. On substituting the values of A and R we get root 3 into root 3 to the power n minus 5 is equal to 729. Now this implies root 3 to the power n is equal to 729 and this implies 3 to the power n by 2 is equal to 729 and this implies 3 to the power n by 2 is equal to. We can write 729 as 3 to the power 6. On comparing exponents we find that n by 2 is equal to 6. Now n by 2 is equal to 6 implies n is equal to 12. Hence 729 is the 12th term of the GP. This is our required answer. So this completes the session. Bye and take care.