 Welcome to the session, I am Deepika here. Let's discuss the question which says the given distribution shows the number of runs scored by the top batsmen of the world in one day international cricket matches. Run score 3000 to 4000 then the number of batsmen are 4. Run score is 4000 to 5000 then the number of batsmen is 18. For 5000 to 6000 it is 9. For 6000 to 7000 it is 7. For 7000 to 8000 it is 6. For 8000 to 9000 it is 3. For 9000 to 10000 it is 1. For 10000 to 11000 it is 1. Find the mode of detector. Now we know that in the group frequency distribution it is not possible to determine the mode by looking at the frequencies. Here we can only locate a class with the maximum frequency called the modal class. The mode is a value inside the modal class and is given by the formula mode is equal to 0 upon minus F0 minus F2 where the size of the class into the frequency of the class modal class is the frequency of the class in the modal class. So this is a key idea behind the question. We will take the help of this key idea to solve the above question. So let's start the solution. We are given the run score by the batsmen of the world and the number of batsmen that is Fi. So if the run score is 4000 then the number of batsmen is 4 and if the run score is 4000 to 5000 then the number of batsmen is 18. For 5000 to 6000 it is 9. For 6000 to 7000 8000 and for 8000 to 9000 10000 it is 1000 7000 it is also 1. This table we observe that the maximum frequency in the maximum frequency is 4000 to 5000. Therefore n is equal to this is the lower limit of the modal class is 4000 is the size of the modal class which is 1000 F1 is the frequency of the modal class which is 18. The frequency in the modal class succeeding the modal class is 9 and substitute equal to n plus F1 minus F0 upon is equal to 4000. Now 14 upon 20 times 60 is 7 in 2000 and therefore is equal to answer for the above question is mode is equal to 8.7. I hope the solution is clear to you. Bye and take care.