 Hi and welcome to the session. Let's work out the following question. The question says if the sum of the mean and variance of a binomial distribution for 5 trials is 1.8, find the distribution. Let us start with the solution to this question. Let n and p be the parameters of binomial distribution. Now it is given to us in the question that sum of mean and variance is 1.8. So mean plus variance is 1.8. Now mean is same as np and variance is same as npq. So np plus npq is equal to 1.8 where np and q are parameters of binomial distribution. This implies 5p plus 5pq is equal to 1.8 because we are given for 5 trials so n will be equal to 5. So we have 5p plus 5p into now q is same as 1 minus p is equal to 1.8. This implies 5p plus 5p minus 5p square is equal to 1.8. This implies 5p square minus 10p plus 1.8 is equal to 0. This implies p square minus 2p plus 0.36 is equal to 5. This we get by dividing throughout by 5. This implies p minus 0.2 into p minus 1.8 is equal to 0 and this implies that p is equal to 0.2 that is equal to 1 by 5. We neglect p equal to 1.8 because this is greater than 1. Now q will be equal to 1 minus 1 by 5 that is 4 by 5. So our answer to this question is n is equal to 5, p is equal to 1 by 5 and q is equal to 4 by 5. So I hope that you understood the solution and enjoyed the session. Have a good day.