 Hi and welcome to the session. Let us discuss the following question. Question says, how many sites does a regular polygon have if the measure of an exterior angle is 24 degrees? Let us now start with the solution. Now measure of each exterior angle of a regular polygon is 24 degrees. So we can write measure of each exterior angle is equal to 24 degrees and we have to find the number of sites a regular polygon has. Now let us assume that number of sites of a regular polygon is n. So we can write let n be the number of sites of a regular polygon. Now number of exterior angles of a regular polygon is equal to number of sites of a regular polygon that is n. So we get number of exterior angles is equal to n. Now total measure of all exterior angles is given by product of number of exterior angles and measure of each exterior angle that is n multiplied by 24 degrees. Now property of a polygon states that the sum of the measures of the external angles of any polygon is 360 degrees. Now these two statements help us to conclude that n multiplied by 24 degrees is equal to 360 degrees. Now to find the value of variable n we will divide both the sites of this equation by 24 degrees and we get n multiplied by 24 degrees upon 24 degrees is equal to 360 degrees upon 24 degrees. Now here 24 degrees will cancel this 24 degrees and we are left with n on left-hand side is equal to sign is as it is and 15 times 24 is equal to 360. So we get 15 here on right-hand side. So value of n is 15. Note that this term has no unit as it represents the number of exterior angles. Now as per our assumption n is the number of sites of a regular polygon. So we can write number of sites of a regular polygon is equal to n is equal to 15. So this is our required answer. This completes the session. Hope you understood the solution. Take care and have a nice day.