 Hello and welcome to the session. Let us understand the following problem today. Two water taps together can fill a tank in 9, 3 by 8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank. Now let us write the solution. Suppose the tap with larger diameter takes two fill the tank. Therefore, the tap with smaller diameter to fill the tank. Therefore, the two 1 by x is equal to 1 by x 5 by 8 which is equal to 75 by 8x. The two 75 by 8 into x plus 10 is equal to 1. Now solving this we get x plus 10 is equal to 8 by 75. Now taking the LCM x into x plus 10, x plus 10 is equal to 8 by 75. To 8 into x square plus 10x is equal to 8x square plus 80x minus 150x minus 750 is equal to 0. The 70x minus 750 is equal to 0 which can be written as 25 is equal to 0. Now solving by splitting the middle term we get 5 is equal to 0. Now taking 4x common we get x plus 25 common we get x minus 15 is equal to 0 which implies 4x plus 25 into x minus 15 is equal to 0. It is equal to 0 and 4x plus 25 is equal to 0 which implies x is equal to 15 and x is equal to minus 25 by 4. Minus 25 by 4 is not possible therefore x is equal to 15. Smaller term x plus 10 is equal to 25. I understood the problem. Bye and have a nice day.