 OK, let's try to do this one, then. So the problem states that 2.25 liters of the gas at 16 degrees Celsius and 1 atm is compressed at a pressure of 125 atm at 20 degrees Celsius, then calculate the new volume of the gas. OK, so notice we've got volume, temperature, and pressure reading. And they change around. So we have to use the combined gas law for this one. So the combined gas law, of course, is Vi times Pi over Ti equals Vf times Pf over Ti. We're going to have to know the values for all those variables. So the first thing we want to do is write down, what's Vi? Well, Vi, 2.25 liters. Pi, 1.08, and Ti is 16 degrees Celsius. But of course, we can't use Celsius. We have to use Kelvin. So get to Kelvin for Celsius, 273. You guys can talk. It doesn't matter if it's a temperature. It's 289. So it's 281. 289. 289. Kelvin. And now we need to know, well, Vf, Pf. So Vf, well, it says calculate the new volume of the gas. So that's something we don't know. Pf, well, we know that because it says it's compressed at a pressure of 125 atm. So that's the new pressure on 25 atm. And Tf, of course, is 20 degrees Celsius plus 273. So 20 plus 273. It's 293. It's 293 Kelvin. So now we have all the information we need to plug into the problem. The only thing we need to do now is to isolate Vf. So Vf is on this side of the equation. So it's not alone. Of course, it's got Pf and Tf there. So we've got to do stuff to get those out of it. First thing we've got to do, of course, is going to be multiplied by Tf. That cancels Tf. So now we've got Tf there. But Vf is still with Pf. So we've got to divide by Pf. Cancel like that. So now we've got to put Pf over here. So we've divided it like that. So now our new equation, we can get rid of all of this stuff. But it's essentially Vf equals Tf times Vi times Pi over Pf times Ti. Why do you think that Tf goes on the left or on the right? And that's the end of the question. Oh, yeah, they're both multiplied. You can multiply it. So this says that it's multiplied by these two guys. If you put it over here, it would be multiplied by that, too. I just put it over there because it's more convenient than erasing it and then putting it back. So Tf 293 Kelvin, 2.25 liters, Pi 1.00 atm divided by Pf 125 And you made it, huh? Yeah. And Ti 289 Kelvin. So you're in front of the table. Oh, that's all right. You can sit there. Just nobody can see the problem. OK, sit down. Oh, yeah, we all get to see you. OK, so you just multiply the top, multiply the bottom, and divide them into two, OK? So 293 times 2.25. Well, I guess we could show the units they cancel first, OK? Atm's will cancel there and there. And Kelvin's will cancel there. So we're going to get a volume here, or liters, OK? So that's cool because we're looking for Vf, OK? So, OK, so now we'll multiply and divide it. So that, OK? So the volume I got was 0.0182 liters. If you compress this thing, and if you compress this thing by 125 times and increase the temperature by only 4 degrees, the volume will get much smaller, OK? So on this one, there's 3, 3, 3, 3, small numbers. Well, actually, this one should maybe have a 0.0 or something like that, you know, in a test problem. I would make sure, you know, that the safe things were proper, OK? So like here, since you only got the one safe thing, this probably should be one safe thing, right? So I guess that we're doing safe things, right? So if you're doing a regular question, you look at the lowest number of safe things, but the answer is the lowest number. Well, for some reason, I'm coming up with a totally different answer, and I'll plug it in the same number. OK. There it is. Fairness.