 Hello and welcome to the session. Let us discuss the following question. It says A and V are events such that probability of A is 0.42, probability of B is 0.48 and probability of A and V is 0.16. Determine probability of not A, probability of not B and probability of A or B. Let us now move on to the solution. We have given that probability of A is 0.42, probability of B is 0.48 and probability of A and V is equal to 0.16. Now in the first part we have to find probability of not A and probability of not A is equal to 1 minus probability of A. So this is equal to 1 minus 0.42 which is equal to 0.58. In the second part we have to find probability of not B which is equal to 1 minus probability of B that is 1 minus 0.48 and this is equal to 0.52 and in the third part we have to find probability of A or B which is equal to probability of A plus probability of B minus probability of A and B. Now probability of A is 0.42, probability of B is 0.48 minus probability of A and B and probability of A and B is 0.16 and this is equal to 0.74. Hence probability of not A is 0.58, probability of not B is 0.52, probability of A or B is 0.74. And this completes the question. Bye for now. Take care. Have a good day.