 Calculate the degree of hydrolysis, calculate the degree of hydrolysis, hydrolysis H. Calculate the degree of hydrolysis of a mixture of aniline and acetic acid, aniline, aniline, aniline, and acetic acid, each of them being 0.01 molar, each of them being 0.01 molar, Ka of acetic acid is given 1.8 into 10 to the power minus 5 and Ka of aniline is 4.5 into 10 to the power minus 10. Calculate the pH of the mixture, calculate the pH of the mixture and the nature of the mixture. Calculate the degree of hydrolysis of a mixture of aniline and acetic acid, aniline, and acetic acid. Calculate the degree of hydrolysis of a mixture of aniline and acetic acid, aniline, and acetic acid. Calculate the degree of hydrolysis of aniline and acetic acid, aniline, and acetic acid. Calculate the degree of hydrolysis of aniline and acetic acid. Calculate the degree of hydrolysis of aniline and acetic acid. Calculate the degree of hydrolysis of aniline and acetic acid. Calculate the degree of hydrolysis of aniline and acetic acid. Calculate the So, the H is very close to 0. It's fine. It's fine. See, which is greater? Can't be a bigger problem. A key. Sorry, I can't. So, the A key, the C key. See, we know the relation. Sir, one second. Sir, one second. Okay, okay, okay. What is of 2.5? That's one of the stations and companies. No, no, I guess super stations. Sir, you have change. 8 of 2 by K into KB. I got that. Why is it? 10 to the power minus 40. What is K? It's one point K. One point K, I do. I was making 30.5. 10 to the power minus 10. Yeah, 10 to the power minus 10. 4.7. 10 to the power minus 10. No, it's 4.5. 4.8. Of the answer. P H. What is KH from this? Sir, it's 10 by 8.1. 10 by 8.1. 10 by 8.1 is KH. KH of P H, huh? Sir, it's P H 4.7. 4.7 is correct. KH is 1.23. 4 it is. Okay. So, H is equal to 0.52. What is P H? 7 plus half of P K H minus P K B. You see, if they ask you the question, what is the nature of the mixture? You don't have to find out P H. Because K A value you can compare. This is K, this is K B. If you look at this value, K A is more than K B. Right? That's why the solution is acidic. So, answer should be less than 7. So, if they ask you only nature of the solution, you don't have to ask the P H for that. Just you look at this value, P K N, K B and anything like that. Okay. But formula of P H is this. P K, P K B you know. So, you substitute the value and get that. P H exact value is 4.7 for this question. Okay. Right on the question. Calculate H plus and O H minus ion concentration. H plus and O H minus ion concentration. In 10 to the power minus 3 monobasic acid. 10 to the power minus 3 monobasic acid. Which is 4% ionized. What is the P H, K A and P K B of the acid? K A and P K A not P K B. P H, K A and P K B. So, P K A of the acid. And you also have to find H plus and O H minus monobasic acid. That is not high. Yes. Yes. Calculate H plus and O H minus ion concentration. In 10 to the power minus 3 monobasic acid. Which is 4% ionized. They assume that when you add water, the reaction is C S 3 C O H plus H 2 O. C S 3 C O H plus H 2 O gives what? C S 3 C O O minus plus H 3 O plus. Sir, is it the acid wave? K A is? No. Sir, what is P H? When you take P H of that. Then you take O H. So cool. I don't know what I mean. Because they don't know what I'm trying to write. See, I'll tell you. This is the first case. On 4th case, I'll write K A. You have to write K A. Yes. Sir, what's my K H? No, not K H. P H, B O H. H plus concentration. O H minus concentration. K A P K. Sir, do you even get P H? No. P K is 6.2. What is P K? What is P K? What is K A? I want an A. K H is P K and B L. This is just water. You have to write K A. This is the reaction we have? This C is here. 10 to the power minus 3 molar. C minus C alpha. This is C alpha and this is C alpha. Alpha is given. 4 percent. What is alpha? 4 percent. So this 4 divided by 100. That is 0.04 is alpha. Or we can write this this way. 4 into 10 to the power minus 2. Okay. So alpha is O. C is O. What is K A of this? Concentration of C S 3. C O minus. Concentration of H 3 O plus. Concentration of H 3 O plus. Divided by concentration of. C S 3. C O H. That will be C alpha square. C alpha square. And 1 minus alpha. We are assuming it as 1. It is C alpha square. Alpha is very small. 4 into 10 to the power minus 3. Okay. So I calculate it without. Assuming 1 minus alpha is the value. That will be. 1.6 into 10 to the power minus 9. 3 more. K A is equal to 10 to the power minus 3. Into alpha is. Alpha square. 4 square into 10 to the power. Minus 2. Square. Right. This will be 16 into 10 to the power. Minus. 7. 1.6 into 10 to the power minus 6. This is K. K. P K is what? Minus log of K. That is 6 minus log of 1. 6. So that will be. Minus minus plus 7 minus. 4 into 1. 4 into 0.30. That will be. 5.8. P K. It is. 4 log 2. Log 1.6 you can write. Log 16 you can write. 4 log 2. And 1. 1.6 plus. 6 plus 1 becomes 7. Okay. It is 1.6. 1.6. So this can do the power minus 1. Minus 1. P K. But if you see this. 1.6 into 10 to the power minus 1. 1.6 into 10 to the power of minus 1. Can you write this? 8. So this plus 1 becomes 7. How it is minus 1, it is minus of log A minus log B, log 10 is 1 plus 6 7, 7 minus log 16, log 16 is 4 log, 4 log 2 is 0.30, log 2 is 0.30, log 2 is 0.30, not 4. Now H plus concentration is nothing but the concentration of H3O plus, this we can take, right. So, concentration of H plus is what? C alpha C is 10 to the power minus 3, alpha is 4 into 10 to the power minus 2. So, which is 4 into 10 to the power minus 5, P H is what? 5 minus 2 log 2, right. So, 0.30 into 2 is 0.6, so it is 4.4, H plus concentration also we have done. O H minus concentration is what? When you know H plus concentration, so we know H plus into O H minus is what? 10 to the power minus 14, right. H plus concentration you know, you can find out O H minus and then P over chicken, easy. Sir, how much is the 14 minus 4.4. So, we can do it. Yes, we can do it. Okay, so next class we will finish buffer, that is the last part and titration, okay,