 Hello and welcome to the session. In this session we discuss the following question which says, in the given figure, a rectangular plot of land measures 6 meters by 5 meters. In each of the corners, there is a flat bed in the form of a quadrant of a circle of radius 2 meters. Also, there is a flat bed in the form of a circle of radius 2 meters in the middle of the plot. Find the area of the remaining plot. First, let's recall the formula for the area of a rectangle. This is equal to L into B where this L is the length of the rectangle. B is the breadth of the rectangle. Then we have the area of a circle is equal to pi r square where r is the radius of the circle. This is the key idea to be used in this question. Let's move on to the solution now. This is the figure given to us. So, this ABCD is the rectangular plot. It measures 6 meters by 5 meters. So, area of ABCD is equal to 6 meters into 5 meters. This is equal to 30 meters square. Now, in each corner, as you can see there is a flat bed which is in the form of the quadrant of a circle of radius 2 meters. So now, area of one flat bed which is in the form of a quadrant of a circle is equal to 1 upon 4 into pi r square that is 2 square since it's given that the radius is 2 meters. So, we have this is equal to 1 upon 4 into pi into 4. Now, this 4 4 cancels and so this is equal to pi meter square is the area of one flat bed which is in the form of a quadrant of a circle. Now, since in the figure you can see that there are 4 flat beds which are in the shape of or in the form of quadrant of a circle. So, area of the 4 flat beds which are in the form of quadrant of a circle is equal to 4 into the area of one flat bed which is pi meter square. So, 4 into pi meter square is the area of 4 flat beds. So, this is equal to 4 pi meter square. Now, we have one more flat bed which is in the form of the circle of radius 2 meters. So, area of the circular flat bed which is in the middle of the plot is equal to pi into 2 square since we have the radius r is 2 meter square. So, this is equal to 4 pi meter square is the area of the circular flat bed. We need to find the area of the remaining plot which is the shaded region. So, we have the area of the remaining plot is equal to area of the plot a v c d minus the area of 4 flat beds which are the quadrants of a circle plus the area of one circular flat bed. So now, this would be equal to we have already found out that area of the plot a v c d is equal to 30 meter square. So, this is equal to that is the area of the remaining plot is equal to 30 minus area of 4 flat beds which is equal to 4 pi meter square. So, here we have 4 pi plus area of one circular flat bed which is also 4 pi meter square. So, area of the remaining plot is equal to 30 minus 4 pi plus 4 pi meter square that is equal to 30 minus 8 pi meter square which is equal to 30 minus 8 into 22 upon 7 that is we put the value 4 pi as 22 upon 7. So, this is equal to 210 minus 176 upon 7 and this is equal to 34 upon 7 which is equal to 4.86 meter square. Thus, we have the area of the remaining plot is equal to 4.86 meter square. So, 4.86 meter square is our final answer this completes the session. Hope you have understood the solutions for this question.