 Hi and welcome to our session. Let us discuss the following question. The patient says, integrate the following functions. Given function is sin x by sin x minus alpha. Let's now begin with this illusion. In this question we have to integrate the function sin x by sin x minus alpha with respect to x. Now we will add and subtract alpha from x in the numerator. This is equal to sin x minus alpha plus alpha by sin x minus alpha dx. You know that sin a plus p is equal to sin a cos p plus cos a sin v. So using this formula numerator is equal to x minus alpha cos alpha plus cos x minus alpha into sin alpha by sin x minus alpha dx. Equal to integral of sin x minus alpha cos alpha by sin x minus alpha dx plus integral of cos x minus alpha sin alpha by sin x minus alpha dx. This is equal to integral of cos alpha dx plus integral of cos x minus alpha sin alpha dx and this is equal to cos alpha into integral of dx plus sin alpha into integral of cos x minus alpha dx. Now this is equal to cos alpha into x. You know that integral of dx is x. We have learnt that integral of cos a x plus b dx divided by derivative of a x plus b that is a plus c. So using this for integral of cos x minus alpha with respect to x is log mod this is equal to and so I require the answer is c. So this can be the section. Bye and take care.