 Hi and welcome to the session. Let us discuss the following question which says in figure O is the center of a circle, the area of sector OAPB is 5 by 18 of the area of the circle find X. Before moving on to the solution let's see the key idea that we will use for this question area of a circle is given by pi r square where r is the radius of the circle and area of sector of angle theta is equal to theta upon 360 into pi r square here r is the radius of the circle. Now let's move on to the solution. First of all let us see what we are given in the question. We are given that area of sector OAPB is 5 by 18 of the area of the circle. So we have area of sector OAPB is equal to 5 by 18 into area of circle and we need to find the value of X. So first of all let us assume that radius of the given circle B r let us denote it as 1. So 1 implies area of the sector OAPB which will be given by X upon 360 into pi r square as here theta is given by X and radius is r is equal to 5 by 18 into area of the circle that is pi r square. So this implies X is equal to 5 by 18 into pi r square into 360 upon pi r square and this will be equal to 100. So the value of X will be 100 degrees thus X equal to 100 degrees is the required answer. With this we finished this session hope you must have enjoyed it goodbye take care and have a nice day.