 Okay. So this is a question of exam 2b. It's question number 5. And the question states, write the correct total ionic and net ionic equations for the molecular equation given. So this is the molecular equation. But we want to go ahead and write the total ionic equation. Start there. For the total ionic equation, all you want to do here is take anything that has the state of aqueous, okay, and then just break it up into its constituent ions, okay? So 2naf aqueous. So we should be able to break that up because it's aqueous, right? So 2nafs have 2na's, right? So we're going to put 2. Remember the charge on na, which is plus 1. And then we just put aqueous. Then we go to f. Do the same thing. So of course 2nafs have 2f's as well. So we're going to have 2f minus. Then we go to the next one. Well, pvn03 or lead 2 nitrate, okay, aqueous has 2 ions that we can break up. So the first one is going to be lead 2 plus. It's good. And then we'll put plus. This time, nitrate only has a minus 1 charge. So we need 2 of them to counterbalance the 2 plus the lead 2. So what we're going to do is take this polyatomic anion and put it over here. But we're going to take this number here, the subscript, and put it as the, in front of the ion, okay? So it will be 2. We took 2 from the subscript and made it the coefficient there. Just keep going. So this one here, this one's not aqueous. So we can't break that up. So it stays the same. So it's pvf2 solid. And then this one over here, sodium nitrate, that's aqueous. So we can break it up. So there we go. 2 and plus. We'll just put it underneath there. 2, does that make sense on how to do the total ionic equation for it all? So now let's do the net ionic equation. We'll do it in a different color, okay? So the spectator on each side, so they have to be ions, okay? So the ions on each side that appear on each side of the equation, okay? We look here and we say, well, we have 2 and a plus aqueous ions, right? If we go over here, do we have 2 and a plus aqueous ions? Yes. So what are we going to do? We just cancel that. That's a spectator ion. We look here, 2f minus aqueous and an ion. So we've got to go to the other side. Do we have 2f minus there? No. Do we have it there? No. So that's not a spectator ion. That's going to be within the net ionic equation. So let's write that down. 2 plus aqueous. Is that on both sides of the equation? Will we look over here? I don't see it there, right? So it's going to be not a spectator ion, right? We've got 2 of them over here as well. So that's a spectator ion. The last thing we'll go over here, look on this side of the equation, Pbf2 solid. Well, that's not even an ion, so we can't cancel that out, but we wouldn't find it, okay? So we just take what are called spectator ions. The net ionic equation tells you exactly like the participants in the reaction. Spectator ions didn't do anything in the reaction, okay? So this would be your net ionic equation. Not to be your total ion.