 Hello and welcome to the session. Let us understand the following problem today. Let A is equal to matrix 2, 4, 3, 2 and B is equal to matrix 1, 3, minus 2, 5. C is equal to matrix minus 2, 5, 3, 4, 5, B, A. Now let us write the solution given to us as A is equal to matrix 2, 4, 3, 2. B is equal to matrix 1, 3, minus 2, 5. Now since number of columns of B is equal to number of row of A is equal to 2, therefore B, A exist. Now B, A is equal to matrix 1, 3, minus 2, 5, multiplied by matrix 2, 4, 3, 2. Now solving it further which is equal to multiplying first row by first column we get 1 into 2 plus 3 into 3. Now multiplying first row by second column so we get 1 into 4 plus 3 into 2. Now multiplying second row of B by first column of A so we get minus 2 into 2 plus 5 into 3. Now second row by the second column so minus 2 into 4 plus 5 into 2 which is equal to 2 plus 9 4 plus 6 minus 4 plus 15 minus 8 plus 10 which is equal to 11, 10 minus plus 11 plus 2. So hence B, A is equal to 11, 10, 11, 2 which is the required matrix and our answer. I hope you understood the question. Bye and have a nice day.