 When the pressure increases by 100%, when the pressure increases by 100%, the volume becomes 625 ml. When the pressure increases by 100%, the volume becomes 625 ml. When the pressure increases by 100%, the volume becomes 625 ml, calculate the volume of each month. When the pressure increases by 100%, the volume becomes 625 ml, calculate the volume of each month. What 150 is the volume that the system that you have the container of that 1 liter and you should understand the question. Understanding of like the question is also the one part of the testing. So, no one will explain you what the question is, point is the volume of gas containing 10 marble at one atmospheric pressure is one litre, this is what it is given. Understand the question is the gas cylinder which contains 10 marble at one atmospheric pressure is one litre, means the gas cylinder plus 10 marble the volume is, the total volume is 10 litre. 25 ml is correct. See, you assume the volume of one marble that is V, what is the volume of 10 marble? 10. The volume that is available that is the volume of gas. The point is if you have 1000 litre of this container if you have, like 1000 litre of this container and in this 1000 litre suppose 200 litre is occupied by some solid object which you kept into this container, 200 litre is occupied. Means what is the available volume? 1000 minus 200. Means this volume which is available in this volume only the gases will be there. So, you need to find out the volume which is available for the gaseous molecules and then you can apply BVS equals to BVL equals to P2P2 because that is applicable only for gaseous system. So, in the question it is given one litre of container you have which is 1000 ml. And in this 10 marble is present. Volume occupied by one marble it is B suppose. So, the volume of the gaseous molecules will be 1000 ml minus 10 V. So, this is V1, pressure is given one atmospheric, P2 is what? P2 is 100% increase that will be what? Initially it is 1, it becomes that 2 because 100% increase is there. So, V is the volume of one marble. So, the volume available for the gaseous molecules V1 is equals to 1000 minus 10 V into ml. T1 is given in the question that is 100. So, V1 atmospheric P2 now increase by 100%. So, it becomes 2 atmospheric V2 will be what? The volume becomes 625 minus LV 625 ml. Now, you can apply BVLV1 is equals to P2P2. So, 1000 minus 10 V is equals to 2 into 625 minus 10 V. We are just calculating first the volume which is available for the gaseous molecule. In that volume we are applying BVLV1 is given. Next write down Charles's law at constant pressures for a given amount of gas at constant pressures the volume is directly proportional to temperature. The volume occupied by the gas is directly proportional to temperature. When you remove this proposed standard sign we will get V is equals to KT where K is what? When you compare this with the series goes to LRT equation K is a function of pressure and we can also say K is inversely proportional to pressure. So, when you draw the graph of Nt V and T. So, again you will get a state like a different difference present P1 P2. If I ask you what is the relation of order of P1 P2 and P3 what is the answer tell me? P3 is maximum. Why P3 is maximum? Slope is K right? Slope is minimum here then maximum in case of P1 right? So, when the slope is maximum K pressure will be what? Minimum because K and P are inversely proportional. Slope is maximum here so pressure will be minimum order of P1. Then you can draw a line straight line and then also you can draw. T and log V graph is what? You have to have a log T and log V graph. Log of? Log isn't log base V or log base T. Anything you make measure of the graph. You have to draw log like this right? Whatever Y and X axis we have you try to draw a relation first in between the Y and X axis. Like we have log V and log P we have the relation of V and D take log both side. What do you get? Log V is equal to log T plus? No, it's log KT right? Log T plus log K right? No I suppose. T is Y, this is X and this is C, Y is equals to Mx plus C where M is equals to 1 right? V is Y here, Y axis is log V right? X axis is what? Log T, log T is X, log V is Y and log K is constant C. K is constant. You get a log P here also, log V also. Log V and Y axis. How do you know that it is Y axis and Y axis? Y axis and Y axis. This is in the form of this, no Y axis is Y axis. C is Y axis, it means it is because of Y axis. It is in the form of Y axis plus Y axis. What is the reason for this one? This one, yeah. Because the axis is log V and log C. What is the question of this? Log V and log T. How do we draw the graph of this straight line with positive slope right? So it will be like this positive Y intercept. This will be like this. It will be positive Y intercept. It will be positive Y intercept. It will be positive Y intercept. If you draw like this, it will be positive Y intercept. If it is positive Y intercept, it will be 0. Yes, because the slope is 1. This angle is 45 degree. Sometimes what happens, they will give you this. This will give you the graph. And you need to write down the expression for V and T. This gives you log K. This distance is log K. From here you can find out K and then you can find out the equation of V and T. And then suppose at a given volume, what temperature we have to find out that we can substitute there and find out T. Understood this? So basic principle is what? Whenever you have to compare or draw a graph, you just find out the relation of the Y axis. The variable which is there in Y axis and X axis. Depending upon the nature of the equation that you get, you can draw the graph. And mostly in chemistry, you will get a straight line. Most of the cases, 99% of the cases, you will get a straight line. So that is what is required. If you write down here, the relation of volume and temperature. You won't use this in solving numericals, but I will just give you one definition here. You see V and T, volume and any temperature T, we can write this as V0 or V0 also we call it as plus T divided by 273. Now this V0 is the volume at 0 degree Celsius. Volume at 0 degree Celsius. This volume at temperature T degrees Celsius. So when the temperature is minus 273, or better we write this as capital T. Now if this temperature you take minus 273 degree Celsius. Minus 273 degree Celsius. Now VT will be what? VT will be 0, which is theoretical. It means the volume occupied by the gaseous molecules at this temperature will be what? 0. This temperature we call it as absolute 0 temperature. No, it is not possible. It is impossible. We can say, but I cannot say it is impossible because nothing is impossible. So if you say impossible, I won't say impossible, but very difficult to say. So you can say minus 273 degree Celsius, but you cannot touch a point on the slide. You cannot make it absolutely 0. That is no velocity volume. That is why I said that it is a theoretical. That is why I said theoretical. Because anything if it is there, any molecules, any size, they will occupy some volume. Sir, what is the volume? Sir, what is the volume? No, no, no. Actually you know, in absolute 0 temperature I mean for this temperature it is very low. You are not increasing the temperature. The temperature is decreasing, right? The temperature is very low. So kinetic energy will be almost 0 in that case. Actually the definition of absolute 0 temperature is what? There is a temperature at which all kind of motion of the molecule freezes. Sir, like that. Even vibration motion is also not there. Sir, the temperature of the molecule freezes. No, that we can find out. But this temperature, the definition of this is what? All kind of motion freezes at this temperature for the molecules. That is why this is very difficult to achieve this temperature. You cannot achieve this temperature and you cannot freeze all kind of motion. Translational motion you can freeze, but vibrational motion you cannot freeze. Sir, it is going to freeze. So it is a theoretical thing. Practically we cannot achieve. Sir, just theoretically we achieve this temperature, right? Where you did it for an electron, it is in the electric or the electric position. No, we are talking about theoretical. Practically we cannot do. So how do we know the position of the electron? Sir, what is the most important? Most Einstein. But that is a very high temperature. Most Einstein is very high temperature. Different states of matter, all those plasma and most Einstein. It is possible it is very high temperature. Sir, how do you know both Einstein? Sir, you know both Einstein. Sir, you know both Einstein. The other states of matter you are talking about, right? Like plasma and both Einstein. Yeah, so all those plasma things even exist that, you know, when the temperature is like in the surface of the Sun that we have. And that we have this expression. That near the surface of the Sun temperature is very high. Under those circumstances the plasma and both Einstein are states of matter they exist. Different isotopes of higher temperature. That is what you are talking about. Sir, how do you know both Einstein? Both Einstein is low temperature. Low temperature. Very low temperature. Yeah, yeah. Wait sir. Sir, so sir. So, we measure temperature, the section measuring the kinetic energy of the particle. Sir, so what is that velocity of the particle? That one is just opening up. Sir, because we like the velocity for gas in the particle. Yes sir. Sir, because like if I am measuring that velocity I can prove why you can never achieve that. Because if you want to have zero velocity that means that the velocity of everything has to be zero. So that it can't... Everything means what? Every molecule. The entire universe has to have zero velocity. So that I can have zero relative... No, no, no, no, no. The entire universe has no velocity. That means that it has no velocity relative to anything. And to do that I need to convert all of this kinetic energy into potential or I have to destroy the kinetic energy. Since I can't destroy it, I need to potential it. So now to convert it into potential I need some machine. And that machine in itself needs more energy. So there needs to be a machine to convert that machine's energy into potential energy. How many machines do you want to do in finite machines? And you can't? That's why something's still happening. Right, that's also happening. But the point is any molecule that you have, this molecule, they always have vibrational motion in them. Suppose rotation motion you can control, translation motion you can control. But vibrational motion you can also do that. Because there's energy. Vibrational motion is more... Across one point, the molecule is so vibrational. Sir, that's the whole point of creation. Sir, that's the whole point of creation. Yes, yes. Sir, has it been thrown among the various machines? Yes, sir. Sir, it's been thrown among the various machines. Yes, sir. It is a possible version. Yes, sir. The definition of absolute energy is what? It is the complete energy. All kind of motion of the molecule freezes. It completes the energy. That's practically non-mole. And how do you make this? Sir, let's take a break. Sir, it is practically non-mole. It is any molecule. Let's talk to my number. Sir, what is this? Sir, you said that the molecule is non-mole. Sir, it was non-mole. Sir, you are talking about gas in this thing. Sir, it was non-mole. Sir, I said that what is the gas in this thing? Sir, it is non-mole. Sir, it is non-mole. Sir, it is non-mole. Sir, you say that the molecule freezes is non-mole. Sorry. Sir, it is non-mole. I just have them. Yes, sir. Sir, you as you said are non-mole. Give me the space. Okay.